AREA (i) The area of a rhombus is equal to the area of a triangle whose base and the corresponding altitude are 24.8 cm and 16.5 cm respectively. If one of the diagonal of the rhombus is 22 cm‚ find the length of the other diagonal. (ii) The floor of a rectangular hall has a perimeter 250m. If the cost of paining the four walls at the rate of Rs 10 per m2 is Rs 1500. Find the height of the hall. (iii) A room is half as long again as it is broad. The cost of carpeting the room at Rs
Premium Volume Surface area
or be found in multicellular organisms. The unicellular and multicellular organisms are linked to cell size and surface area to volume ratio. The experiment for cell size and diffusion was set to see how and how much water can go to the cells. This movement of water is called Osmosis. Osmosis is the movement of water molecules from an area of low concentration (lots of water) to an area of high concentration (little water) through a semi permeable membrane‚ demonstrated in ‘figure 1’. A semi permeable
Premium PH Enzyme Osmosis
Investigating Ratios of Areas and Volumes In this portfolio‚ I will be investigating the ratios of the areas and volumes formed from a curve in the form y = xn between two arbitrary parameters x = a and x = b‚ such that a < b. This will be done by using integration to find the area under the curve or volume of revolution about an axis. The two areas that will be compared will be labeled ‘A’ and ‘B’ (see figure A). In order to prove or disprove my conjectures‚ several different values for n will
Premium Real number Number Mathematics
time taken for a substance to diffuse to its centre. Hypotheses- Part A) The 5x5x2.5mm block will turn clear first as the Surface area to volume ratio is high and the 10x10x10mm block will take the longest to completely diffuse the Acid to its centre. Part B) The flat‚ rectangular block will be the first to completely turn clear due to its high Surface Area/Volume Ratio. When measured‚ the cubic‚ rectangular block will have a significantly higher percentage of diffusion than the sphere. Materials-
Premium Chemical kinetics Geometry Physiology
environment. This activity will help you explore the relationship between diffusion and cell size by experimenting with model “cells.” In this experiment‚ you will use agar cubes to which the indicator phenolphthalein has been added. Phenolphthalein is an acid/base indicator that turns pink in the presence of a base such as NaOH. Thus the surface of the agar cubes will turn pink immediately when put into a NaOH solution. The NaOH will continue to diffuse through the cube and gradually turn
Premium Sodium hydroxide Chemical kinetics
Ligia Ramos 11th Grade HL Biology – Ms. Bartels Due Monday October 21st Limitations on Cell Size Research Question: What is the correlation between surface-to-volume ration and ion exchange and how does this relate to cells? Evaluation of Method and Results: Errors/ Limitations: | Suggestions for improvement: | Impact on Results: | Precision - Human error –cutting cubes freely‚ resulting in very different sized cubes‚ especially for the 1cm x 1cm x 1 cm cubes. All the cubes also had slightly
Premium Chemical kinetics Geometry Volume
Cell division happens after the cell is big enough so the daughter cells will be replicated without any flaws. The regulation and amount of materials that can enter and leave the cell is based on how large the cells surface area is. The rate of movement is also determined by the volume of the cell. Many factors like the decline of food and temperature fluctuations can cause the cell to stop dividing. Materials: Plastic Spoon 2 Blocks of agar phenolphthalein Beaker Dissecting tray Paper towel Sodium
Premium Geometry Chemical kinetics Sodium hydroxide
hollowness‚ overlap‚ and termination. These parameters were used to determine specific surface area to volume (SA/V) ratios for the organism. The control specimen for this study was a modern osmotrophic megabacteria. The SA/V ratios of the ediacaran organisms were compared to the SA/V ratios of these megabacterium to see if osmotrophy was a viable option for them. Since osmotrophy relies on a large SA/V ratio to insure the proper diffusion throughout the organism‚ osmotrophy becomes increasingly
Premium Area
ITEM PAGE Background Research 3-4 Experiment Hypothesis 5 Variables 5 Equipment 5 Risk Assessment 5 Method 6 Results 6 Analysis/Discussion 7 Conclusion 8 Acknowledgments/Bibliography 8 Table of Contents Background Research As an object becomes bigger its surface area and volume increases but the surface area to volume ratio decreases‚ this is because volume increases quicker than the surface area; as volume is three dimensional. This concept applies to cells and reaction rate because cells
Premium Chemical reaction Chemistry Reaction rate
The larger the surface area‚ means there can be more “paths” from the sides of the body that are capable of releasing this heat particles‚ and reaching thermal equilibrium faster. This is what happens when a hotter body is subjected to a colder one. Research Question: How does the surface area to volume ratio affect heat loss in organisms? Hypothesis: I hypothesize that the larger the surface area to volume ratio‚ the more heat will be lost and vice versa. In this experiment‚ there will be
Premium Thermodynamics Temperature Volume