osmosis rate on different surface areas‚ depending on different types of water solution An investigation showing the effect of surface area on osmosis rate‚ including some different types of water concentration. Osmosis is a type of passive (not requiring energy) transport of water molecules across partially permeable membrane‚ from an area of high water concentration into area of low water concentration. But how does surface area affect rate of osmosis? Surface area plays important role in
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least have to pick r and h such that pi r^2 h = 355. That means h = 355 / (pi r^2). The surface area of a cylinder is the top (pi r^2) plus the bottom (also pi r^2) times the lateral side (2 pi r h). So the total surface area is 2 pi r^2 + 2 pi r^2 + 2pi r h‚ or 4 pi r^2 + 2 pi r h. Substitute h = 355 / (pi r^2) into this to get the surface area in terms of just r. Now that you have the surface area in terms of just r‚ you can find the value of r that minimizes this by taking the derivative
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the cell? Hypothesis: The larger the cell is‚ the more difficult it will be for the chemicals to reach the centre of the cell‚ and diffuse throughout it. This is because there will be a higher surface-area to volume ratio in the larger cells‚ making the centre of the cells further away from the surface. Therefore‚ when dipped in sodium hydroxide‚ the larger cells will not be dyed pink all the way through like the smaller cells after the ten minutes. Materials: 1x1x1 cm agar cube 2x2x2 cm agar
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the sphericity F s‚ which is independent of particle size. The sphericity of a particle is the ratio of the surface-volume ratio of a sphere with equal volume as the particle and the surface-volume ratio of the particle. For a spherical particle of diameter D p‚ F s =1; for a non-spherical particle‚ the sphericity is defined as Dp: equivalent diameter of particle Sp: surface area of one particle vp: volume of one particle The equivalent diameter is sometimes defined as the diameter of a
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effect of the surface area to volume ratio on the rate evaporation of water in different sized containers. By measuring the time it takes for the whole amount of water to evaporate‚ a conclusion can be made about the validity of the surface to volume ratio in regards to the biological process of diffusion. Research Question: What is the effect of the surface area to volume ratio on the evaporation of water? Variables: - Independent: o Surface area in cm2 of the top most surface of water in the
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of red pigment from a beetroot cell and the surface area. To do this successfully I will need to alter the surface area of the beetroot cells accurately and then measure if any and how much dye is let out. I can hopefully then look at my results and then find a relationship between the two factors and be able to explain exactly why any changes took place. PREDICTION For this experiment I would expect the leakage of dye to increase as the surface area increases and this is based on the knowledge
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Sammy Hassan Mrs. Droege Biology‚ 4B September 7‚ 2007 Surface Area to Volume Ratio S.Hassan‚ September 7. 2007 AISJ‚ Jeddah Saudi Arabia Surface area is known to be beneficial to keeping organisms alive it allows huge organs such as the intestines to fit in a small area by being coiled and packed together tightly. This experiment looked if the surface area to volume ratio affected the speed of a chemical reaction. For this experiment‚ a film container was filled one-half full with
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divided by (∏ x 3 squared) Height = 6.01 round of to 6cm Allowing 1 extra cm for room Top and bottom of cylinder = 6cm + 1cm = 7cm Height= 6cm + 1cm = 7cm Total surface Area= area of base + area of top + Area of circle = (∏r squared) + (∏r squared) +( ∏ x Diameter x height) = (∏ x 3.5 squared) +(∏ x 3.5 squared) +(∏ x7x7) = 230.90cm cubed 1b The net of package
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Applications of Differentiation 1. If a line y = x + 1 is a tangent to the curve y2= 4x ‚find the point the of contact ? 2. Find the point on the curve y = 2x2– 6x – 4 at which the tangent is parallel to the x – axis 3. Find the slope of tangent for y = tan x + sec x at x = π/4 4. Show that the function f(x) == x3– 6x2 +12x -99 is increasing for all x. 5. Find a‚ for which f(x) = a(x+sinx)+a is increasing 6. Find the intervals in which the function f ( x ) = x3 - 6x2 + 9x + 15 is
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International Journal of Advanced Research in Management and Social Sciences ISSN: 2278-6236 RURALISATION OF URBAN AREAS: REVERSING DEVELOPMENT IN ZIMBABWE Jacob Mugumbate* Francis Maushe* Chamunogwa Nyoni‚ PhD* Abstract: Urbanisation is on an upward trend in Zimbabwe as evidenced by expansion of urban centres. Notwithstanding advances towards urbanisation‚ some urban centres are actually de-urbanising or ruralising as witnessed by deteriorating livelihoods‚ services and infrastructure
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