Ammonium sulfate foreign producers 1. Highlights One of the largest producers of specialty chemicals‚ fertilizers‚ plastics and packaging in Latin America. Major producer of styrene and polystyrene. Latin America’s sole producer of acrylonitrile (AN)‚ methyl methacrylate (MMA)‚ acrylic and polycarbonate resins‚ polycarbonate films and cyanides. Largest producer of cast acrylic sheets in the Americas. Latin American’s largest ammonium sulfate producer http://www.unigel.com.br/
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Determining the Number of Water Molecules in a Hydrate Results Mass of empty beaker 55.11 g Mass of beaker with hydrated copper (II) sulfate 58.13 g Mass of hydrated copper (II) sulfate 3.02 g Mass of beaker with dehydrated copper (II) sulfate (last weighing) 57.22 g Mass of dehydrated copper (II) sulfate 2.18 g Mass of dehydrated copper (II) sulfate (2nd weighing) 2.11 g Questions 1. Calculate the value of “n”. Show your work. Include an example of ALL calculations involving
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Analysis: Copper Lab 1) Calculate the mass of the copper that was recovered 2) Use the formula shown below to calculate the “percent of recovery” of copper for your experiment. 3) Use the proper symbol and formula to write balanced equation for each of the five copper reactions‚ include state symbols. 4) Classify each of the five copper reactions. (Refer to the above order‚ please!) A) Single Displacement B) Double Displacement C) Decomposition D) Double displacement E) Single Displacement
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Purpose: To use electrochemistry to extract metals from ionic compounds in solution Procedure: -Start by attaching battery snap connector to a battery and fill beaker with between 100 and 200 mL of copper (II) sulfate solution -Connect clip to each of the nickel strips -Place nickel strips in copper sulfate solution without strips touching -Put one clip on the positive side of the battery and the second to the negative side. Observe -Switch clips to the opposite charged sides of the battery
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Carboxylic Acids and Their Derivatives Ma. Marielle M. Medura Prof. Emma Boncales Chem 23A (TTH 01:00-4:00 p.m) Carboxylic Acids and Their Derivatives I. Introduction Carboxylic acids is an organic compound that contains a carboxylic group(-COOH). Its general formula is R-C=OOH with R referring to the rest of the molecule such as H and C. They are directly attached to a carbonyl group and the interaction between them affects the reactions of each. The polarity of the O-H bond
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Weak Acid Titration Abstract: Our method for determining the unknown weak acid was to determine the equilibrium constant K from the molecular weight of the weak acid from our titration data. In this lab the acid Potassium hydrogen phthalate and two unknown acids were titrated. We determined the molar mass of the Potassium hydrogen phthalate‚ for the unknown acids we calculated the molar mass and the Ka values. We used NaOH as the known base for titrating in all three of the titrations. Our
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Taki Simadiris p1 Brierly Post-lab a. If you did not wash all of the Calcium Carbonate out of the beaker and into the filter during step 5‚ would your percent yield be larger or smaller? If you do not wash all of the Calcium Carbonate out‚ then the percent yield would be smaller because there is enough calcium carbonate left in the beaker that would have attributed to the final yield. b. If you used tap water instead of DI water what do you think would happen? Why? If you used tap water‚ the coffee
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A. Title – Acid-Base Extraction with Separatory Funnel B. Introduction – The main objective of the experiment was the extract an acid‚ a base‚ and a neutral compound from a 2:1:1 compound of benzoic acid‚ p-nitroaniline‚ and azobenzene. In theory‚ an extraction technique based on phase distribution should allow two immiscible solvents to separate with a portion of the solute distributed into each. Using a separatory funnel‚ acids were extracted with bases (NaOH)‚ and bases were extracted
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Chapter 13 Acids and Bases (Dr Chong Fai Kait) 1) A 7.0 103 M aqueous solution of Ca(OH) 2 at 25.0 °C has a pH of __________. A) 12.15 B) 1.85 C) 1.4 102 D) 7.1 1013 E) 11.85 Answer: A 2) The acid-dissociation constant at 25.0 °C for hypochlorous acid (HClO) is 3.0 108 . At equilibrium‚ the molarity of H 3 O in a 0.010 M solution of HClO is __________. A) 1.7 105 B) 0.010 C) 5.8 1010 D) 4.76 E) 2.00 3) Using the data in the table‚ which of the conjugate acids below is the weakest
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Acids and Bases Study Guide Properties of Acids/Bases: ACIDS | BASES | [Type a quote from the document or the summary of an interesting point. You can position the text box anywhere in the document. Use the Drawing Tools tab to change the formatting of the pull quote text box.] [Type a quote from the document or the summary of an interesting point. You can position the text box anywhere in the document. Use the Drawing Tools tab to change the formatting of the pull quote text box.] pH <
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