The calculations completed for this experiment include determining the amount of Na2CO3 needed to do a full reaction. This was calculated through stoichiometry calculations: Molar mass was first calculated for CaCl2*2H2O Ca = 40.078g Cl2 = 35.453g*2 = 70.906g 2H2 = 1.00794g*4 = 4.03176g 2O = 15.9994g*2 = 31.9988g 40.078g + 70.906g + 4.03176g + 31.9988g = 147.01456g or 147.0 g CaCl2 1g CaCl2 * 2H2O x (1 mol CaCl2 *2H2O/147g CaCl2 *2H2O) = 0.0068 mol of CaCl2*2H2O Molar mass was then
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Lab Report for Experiment #10 Stoichiometry of a Precipitation Reaction Student’s Name ____________________ Date of Experiment ___________ Date Report Submitted _________________ Title: Purpose: Instructor Changes: Weigh out about 1.7 g of CaCl2·2H2O and record your mass to +/- 0.1 g (for example 1.6 g‚ 1.7 g‚ or 1.8 g). We have made this change so that you will have 2 sig figs in subsequent calculations. Have you made any changes to the procedure? Please explain: Data Tables and Observation:
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Ch. 1 Fundamentals of Chemistry Subchapter – Stoichiometry and Units 1. An element X forms an oxide with the formula X4O10. If 31 g of X combines with 40 g of oxygen‚ what is the identity of X? A. N B. P C. C D. S Correct Answer: B: P Explanation: We can solve for the atomic mass of X to identify it. The amount in g of X for any amount in g of O is given by: Rearranging the above equation and substituting the given mass of X and O‚ we get: Thus‚ the atomic mass of X
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LEARNING TASK NO. 4B Composition Stoichiometry Problems Mole Relationship from Chemical Formulas: a) Determine the number of moles of chloride ions in 2.53 mol ZnCl2. b) Calculate the number of moles of each element in 1.25 mol glucose (C6H12O6). c) How many molecules of oxygen atoms are present in 5.00 mol diphosphorus pentoxide? d) Calculate the number of moles of hydrogen atoms in 11.5 mol water. e) A sample of ethanol (C2H5OH) has a mass of 45.6 g.How many carbon atoms does the sample
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IB CHEMISTRY Stoichiometry Lab Data Collection and Processing Item | Mass | Small beaker (100 mL) | 47.0 grams | Large beaker (150 mL) | 82.4 grams | Mass of filter paper | 0.50 grams | Mass of coffee filter | 1.00 gram | 150mL beaker + 20mL water + lead nitrate solution | 96.1 grams | 100mL beaker + 20mL water + sodium carbonate solution | 64.2 grams | Watch glass | 32.2 grams | Precipitate + filter paper + coffee filter | 2.20 grams | Precipitate + 150mL + coffee filter
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Stoichiometry Section 11.1 What is stoichiometry? In your textbook‚ read about stoichiometry and the balanced equation. For each statement below‚ write true or false. _______true___________ 1. The study of the quantitative relationships between the amounts of reactants used and the amounts of products formed by a chemical reaction is called stoichiometry. ________true__________ 2. Stoichiometry is based on the law of conservation of mass. _________false_________ 3. In any chemical reaction‚ the
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Teresa Meng‚ Niharika Palakodety‚ Victoria Wang‚ and Grace Xiong Mrs. Rhonda Smith Honors Chemistry Period 4 13 May 2012 Redox Reactions Lab Report We wished to investigate the oxidation number of a metal that would form aqueous ions when reacted with an aqueous nitrate salt. For this purpose‚ we chose to investigate the reaction of solid copper metal‚ in the form of a wire‚ with aqueous silver nitrate. Before we began the lab‚ we hypothesized that when silver nitrate‚ AgNO3‚ reacts with
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Stoichiometry Practice Problems Be sure to balance all equations before you start calculating! Answer key is at the end. 1) Lithium hydroxide reacts with hydrobromic acid to produce lithium bromide and water. If you start with ten grams of lithium hydroxide‚ how many grams of lithium bromide will be produced? 2) Ethylene (C2H4 ) reacts with oxygen gas to produce carbon dioxide and water. If you start with 45 grams of ethylene‚ how many grams of carbon dioxide will be produced?
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Stoichiometry II- Synthesis of a Coordination Compound Report 〖CuSO〗_4 (s)→〖Cu〗^(2+) (aq)+ SO_4 (aq)^(2-) Cu^(2+) (aq)+ 4NH_3 (aq)→[Cu(NH_3 )_4 ]^(2+) [Cu(NH_3 )_4 ]^(2+)+ SO_4 (aq)^(2-)+H_2 O□(→┴(methanol solvent) ) [Cu(NH_3 )_4 ]SO_4*H_2 O 1.992 g 〖CuSO〗_4 (s) × (1 mol〖 CuSO〗_4 )/(159.6 g) = .0124 mol 〖CuSO〗_4 (s) .0124 mol 〖CuSO〗_4 (s)×(1 mol [Cu(NH_3 )_4 ]SO_4*H_2 O )/(1 mol〖 CuSO〗_4 )×(245.74 g [Cu(NH_3 )_4 ]SO_4*H_2 O )/(1 mol [Cu(NH_3 )_4 ]SO_4*H_2 O )=3.047 g [Cu(NH_3 )_4 ]SO_4*H_2
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Stoichiometry and Limiting Reagents Theodore A. Bieniosek I. Purpose and Theory The purpose of the experiment is to study and apply the processes of stoichiometric calculation on a controlled chemical reaction. We will be adding variable amounts of reactants in a chemical reaction in order to demonstrate the effect of limiting reagents. Based on the volumes of the reactants‚ and their respective molarities‚ we can calculate the theoretical yield of the reaction and compare it to the
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