"Stoichiometry lab" Essays and Research Papers

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    Nitration of Naphthalene Wed 2/25/2015 Lab report # 1 Abstract: The purpose of this experiment was to nitrate naphthalene with nitronium ion‚ which is formed at low concentration from a reaction of nitric acid and sulfuric acid. The percent yield from the experiment was 54.4% of the product‚ and the melting point of the possible results were 59 °C for 1-nitronaphthalene‚ and 78°C for 2-nitronaphthalene. Introduction: Polynuclear aromatic hydrocarbons such as naphthalene can be nitrated

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    then that reactants becomes the limiting reactants. Once the limiting reactants will completely be ran out of‚ the reaction is done. So the limiting reactant is the key to start and finish the chemical reaction. B. Procedures and Materials In this Lab‚ we used different procedures and Materials. We had 12.53 gram of copper sulfate pentahydrate and

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    Although I love science‚ I encountered more problems in this subject than any other. Recently‚ I was assigned a lab. The purpose was to let Copper Sulfate react with Aluminum and obtain Copper. Before the experiment‚ I set up the stoichiometric equation carefully‚ predicting the production of Copper using my assigned mass of Copper Sulfate. Additionally‚ I intentionally made Copper Sulfate an excess in my equation‚ since it would be dissolved in water and I would only have to collect Copper at the

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    CHEM 2070 LAB

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    Purposes of Experiment: To synthesize a transition metal complex‚ potassium tris (oxalate)ferrate(III) trihydrate in a two step process‚ to learn new laboratory techniques such as decantation‚ recrystallization‚ gravity and suction filtration. Also the purpose of the experiment is to determine the actual‚ theoretical‚ and percent yields of product‚ and characterize the final compound by determining the number of waters of hydration by gravimetric analysis List of Observations: After adding

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    CHEMICAL REACTIONS OF COPPER AND PERCENT YIELD Objective To gain familiarity with basic laboratory procedures‚ some chemistry of a typical transition element‚ and the concept of percent yield. Apparatus and Chemicals  |0.5 g piece of no. 16 or no. 18 copper wire |evaporating dish | |250 mL beaker (2) |weighing paper | |concentrated HNO3 (4 – 6 mL)

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    Stoichiometry Lab Report

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    Chapter 3: Stoichiometry 3: Stoichiometry 5: Thermochemistry 8: Covalent Bonding and Molecular Structure 15: Chemical Equilibrium 16: Acids and Bases 3.2 Stoichiometry and Compound Formulas 3.1 The Mole and Molar Mass 3.2 Stoichiometry and Compound Formulas 3.3 Stoichiometry and Chemical Reactions 3.4 Stoichiometry and Limiting Reactants 3.5 Chemical Analysis Chapter Summary Chapter Summary Assignment Reference Tools Periodic Table Molarity Calculator Molar Mass Calculator Unit

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    Abstract A Friedel-Crafts alkylation was performed by adding t-butyl alcohol to p-dimethoxybenzene in order to produce 1‚4-di-t-butyl-2‚5-dimethoxybenzene. This reaction yielded 0.009g of 1‚4-di-t-butyl-2‚5-dimethoxybenzene having a percent yield of 5%‚ and a melting point range of 54.8°C-56.9°C. Introduction This reaction is designed to put functional groups onto aromatic rings. This is done through an electrophilic aromatic substitution where a positive species is strong enough to pull electrons

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    Title: Stoichiometry Reaction Objectives: 1. To decompose sodium hydrogen carbonate (sodium bicarbonate) by heating. 2. To accurately measure the degree of completion of the reaction by analysing the solid sodium carbonate product. 3. To calculate amount of product with given amount of reactant. 4. To determine amount of heat release in the reaction. Results: Part 1: Thermal Decomposition of NaHCO3 Materials Mass (g) Clean and dry test tube 15.1632 Clean test tube + NaHCO3 17.1647

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    Stoichiometry Lab Report

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    Na2CO3(s)+CO2(g)+H2O(g). The was the only equation that matched up exactly with my data in terms of percentage. To start off with‚ when I balanced out the equation‚ I got 2 NaHCO3→ 1 Na2CO3(s)+ 1 CO2(g)+ 1 H2O(g). Therefore when I set up my stoichiometry problem I got 3.2 grams NaHCO3 over 1 x 1 mol NaHCO3 over 84.007g NaHCO3 x 1mol Na2CO3 over 2 mol NaHCO3 x 105.987g Na2CO3 x 1 mol Na2CO3. Hence‚ I multiplied 3.2 x 1 x 1 x 105.987 and got 339.1584. Afterwards‚ I divided 339.1584 by 84.007 and

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    level‚ duly recognized both by the Commission and Higher Education (CHED) and TESDA. Back in 2010 our institution enrollment succeeded to a percent of one hundred and fifty. Our computer facilities intends only into a very limited units so that our Lab supervisor easily maintain and create schedules for students who has a computer subjects. By this time‚ Speed Computer College again increased by staggering a percent of two hundred enrollees. One of the main problems of Speed Computer College

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