"Stoichiometry and precipitation lab" Essays and Research Papers

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    Stoichiometry II- Synthesis of a Coordination Compound Report 〖CuSO〗_4 (s)→〖Cu〗^(2+) (aq)+ SO_4 (aq)^(2-) Cu^(2+) (aq)+ 4NH_3 (aq)→[Cu(NH_3 )_4 ]^(2+) [Cu(NH_3 )_4 ]^(2+)+ SO_4 (aq)^(2-)+H_2 O□(→┴(methanol solvent) ) [Cu(NH_3 )_4 ]SO_4*H_2 O 1.992 g 〖CuSO〗_4 (s) × (1 mol〖 CuSO〗_4 )/(159.6 g) = .0124 mol 〖CuSO〗_4 (s) .0124 mol 〖CuSO〗_4 (s)×(1 mol [Cu(NH_3 )_4 ]SO_4*H_2 O )/(1 mol〖 CuSO〗_4 )×(245.74 g [Cu(NH_3 )_4 ]SO_4*H_2 O )/(1 mol [Cu(NH_3 )_4 ]SO_4*H_2 O )=3.047 g [Cu(NH_3 )_4 ]SO_4*H_2

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    Investigating Stoichiometry with Carbonic Acid Salts Problem: Testing the actual yield versus the theoretical yield of NaCl when HCl is titrated into Na2CO3 and NaHCO3. When 0.15g of both NaHCO3 and Na2CO3 are titrated with HCl‚ then 0.165g of NaCl should form from the NaHCO3‚ and 0.104g of NaCl should form from the 0.15g of Na2CO3. Procedure: Weigh 2 samples of 0.15g of dried unknown each‚ and dissolve each into 50mL of distilled water. Add 0.5 to 1mL of bromocresol green indicator until the

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    Investigating Stoichiometry with Sodium Salts of Carbonic Acid Introduction: The student will perform the experiment in order to find the percent yield by using the theoretical value found using the balanced equation for sodium carbonate as well as sodium bicarbonate. The objective is to stabilize the substances by titrations and finding the percent yield when all the data is collected. The purpose of this procedure is so that the student will get better understanding of stoichiometry. The student

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    Quiz Top of Form Previous PageNext PagePage 1 of 4 Note: It is recommended that you save your response as you complete each question. Question 1 (2.7 points)   The combustion of butane‚ C4H10(g)‚ produces carbon dioxide and water vapor. In the balanced equation for this reaction‚ what are the coefficients of butane‚ oxygen‚ carbon dioxide‚ and water‚ respectively?  Question 1 options: 2‚ 13‚ 4‚ 10  1‚ 6‚ 4‚ 5  1‚ 6‚ 8‚ 10  1‚ 13‚ 4‚ 5    2‚ 13‚ 8‚ 10  Save Question 2 (2.7

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    Determining the Limiting Reactant and Percent Yield in a Precipitation Reaction Objectives: Observe the reaction between solutions of sodium carbonate and calcium chloride. Determine which of the reactants is the limiting reactant and which is the excess reactant. Determine the theoretical mass of precipitate that should form. Compare the actual mass with the theoretical mass of precipitate and calculate the percent yield. Materials: Balance 0.70 M sodium carbonate solution‚ Na2CO3(aq)

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    KWAME NKRUMAH UNIVERSITY OF SCIENCE AND TECHNOLOGY COLLEGE OF TITLE: REMOVAL OF HARDNESS OF WATER USING PRECIPITATION AND COMPLEXATION METHODS. NAME: KWARTENG YAW PRINCE COURSE: BSC. ENVIRONMENTAL SCIENCE YEAR: FIRST YEAR EXPERIMENT NO. : A.1.1.3. T.A.: BRIGHT KOFI LEONARD DATE: 7TH NOVEMBER‚ 2007. Aims and Objectives: 1. To describe water hardness.

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    lab lab lab lab

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    Lab #5: Refraction of Light Theory: Refraction can be defined as the bending of a wave when it enters a medium which causes it to have some reduced speed. In terms of light‚ refraction occurs when the ray passes through some medium which slows its speed; such as water or glass. In this instance the ray tends to bend towards the normal of the medium. The amount of bending or refraction which occurs can be calculated using Snell’s Law (). Objective: To measure the index of refraction of Lucite

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    1. What is the molarity of a solution of ammonium chloride prepared by diluting 50.00 mL of a 3.79 M NH4Cl solution to 2.00 L? 2. A student takes a sample of KOH stock solution and dilutes it with 100.0 mLof water. The student determines that the diluted solution is 0.046 M KOH‚ but has forgotten to record the volume of the original stock solution sample. The concentration of the stock solution is 2.09 M. What was the volume of the original sample of stock solution? 3. A chemist wants to prepare

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    Lab 3 no name

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    Lab #3: Stoichiometry of a Precipitation Reaction October 14‚ 2014 Abstract: The purpose of the labStoichiometry of a Precipitation Reaction‚ is to be able to calculate the amount of a second reactant we need to react with the reactant one. You must calculate the amount of the second reactant using stoichiometry to figure out what amount is needed. After the amount is calculated‚ you then can add it to the first reactant and it will give you a full reaction. To figure out what you

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    Subject: Chemistry SL Title: Preparation of a salt (lead iodide) by using precipitation method. Aim: To produce 1.50 g of lead iodide‚ PbI2‚ assuming 100 % conversion‚ using 1.00 g solid potassium iodide‚ KI‚ and 0.1 M lead nitrate‚ Pb(NO3)2 solution of volume 30 cm3 and hence calculate percentage yield. Calculations: 2KI(s) + Pb(NO3)2( aq) —> PbI2 (s) + 2KNO3 (aq) Mass of PbI2 to be produced = 1.5 g Moles of PbI2 = = 0.003 Moles of KI = 0.003*2 = 0.006 Mass of KI = 0.006*166 = 1.00 g

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