sold‚ and that units left unsold at the end of the season were sold at a loss that average 8 percent of wholesale price. Therefore‚ the stock out probability equal to 8%/(24%+8%)=25% so there are 75% probability of being less than mean+0.67*SD (standard deviation). According to z table‚ z equal to 0.67 when probability is 0.75. Therefore‚ we can calculate quantity for each style include the risk of stock out by using formulate Q*=mean+z*SD. Therefore‚ we can get the maximum order units for each style
Premium Standard deviation Holding cost Risk
created on a graph when using a frequency distribution method for a set of data‚ splitting the mean symmetrically. There is a big difference between standard deviation and the bell curve! Standard deviation shows the difference in variation from the average; the bell curve‚ also normal distribution or Gaussian distribution‚ shows the standard deviation and is created by the normal or equal distribution of the mean among either half. The bell curve is an important distribution pattern occurring in many
Premium Normal distribution Standard deviation
histogram of the 1990 returns. (ii) Produce a histogram of the 1998 returns. (iii) Find the mean‚ median‚ range and standard deviation for the 1990 returns. Annual Returns % (1990) Mean 12.91865979 Median 11.38 Standard Deviation 9.297513067 Range 75.01 (iv) Repeat part (iii) for the 1998 returns. Annual Returns % (1998) Mean 6.355463918 Median 5.4 Standard Deviation 5.170830853 Range 42.76 (v) Which was the better year for investors? • 1990 was the better year for investors in
Premium Statistical inference Statistics Normal distribution
Mark|£10|£20|£30|£40|£50|£60|£70|£80|£90|£100| Number of candidates|15|65|||||905|||| (b) Draw a cumulative frequency graph of the distribution‚ using a scale of 1 cm for 100 candidates on the vertical axis and 1 cm for 10 marks on the horizontal axis. (5) (c) Use your graph to answer parts (i)–(iii) below‚ (i) Find an estimate for the median score. (2) (ii) Candidates who scored less than 35 were required to retake the examination. How many candidates had to retake? (3) (iii) The highest-scoring 15% of
Premium Standard deviation Number Frequency distribution
13. Variance and Standard Deviation (expected). Using the data from problem 13‚ calculate the variance and standard deviation of the three investments‚ stock‚ corporate bond‚ and government bond. If the estimates for both the probabilities of the economy and the returns in each state of the economy are correct‚ which investment would you choose considering both risk and return? Why? ANSWER Variance of Stock = 0.10 x (0.25 – 0.033)2 + 0.15 x (0.12 – 0.033)2 + 0.50 x (0.04 – 0.033)2 + 0
Premium Variance Probability theory Standard deviation
milligrams of tar per cigarette and a standard deviation equal to 1.0 milligram. Suppose a sample of 100 low-tar cigarettes is randomly selected from a day’s production and the tar content is measured in each. Assuming that the tobacco company’s claim is true‚ what is the probability that the mean tar content of the sample is greater than 4.15 milligrams? [0.00621] 2. The safety limit of a crane is known to be 32 tons. The mean weight and the standard deviation of a large number of iron rods
Premium Standard deviation Normal distribution Probability theory
Chapter 12 Problems 1. Cash flow (LO2) Assume a corporation has earnings before depreciation and taxes of $100‚000‚ depreciation of $50‚000‚ and that it has a 30 percent tax bracket. Compute its cash flow using the format below. Earnings before depreciation and taxes _____ Depreciation _____ Earnings before taxes _____ Taxes @ 30% _____ Earnings after taxes _____ Depreciation _____
Premium Standard deviation Income statement Variance
score decreases by -0.347 average number of hours per week. Next‚ we have to interpret the random error component ( ) of the least squares line. The estimate of error standard deviation for this particular data set is 12.28455 which suggests that the work-life balance score (y) values should be two times of the standard deviation. This can be best expressed as in the equation of 2s = 2(12.28455) which equals 24.57 average hours per week. Then‚ we can analyze the accuracy of hypothesis model to
Premium Statistics Regression analysis Economics
in analysing the data is determining if outliers exists within the data. The presence of outliers must be evaluated because their existence could distort the data and make it inaccurate. In order to determine if outliers exist the average and standard deviation must be calculated in order to calculate the Z score‚ which will show‚ wither or not outliers exist. In this instance to outliers where found present in the data set as all of the data fell within the +3‚-3 range‚ the largest positive outlier
Premium Standard deviation Final examination Data
9551/SQRT(300)‚1) = 0.0783 (c) A circuit contains three resistors wired in series. Each is rated at 6 ohms. Suppose‚ however‚ that the true resistance of each one is a normally distributed random variable with a mean of 6 ohms and a standard deviation of 0.3 ohm. What is the probability that the combined resistance will exceed 19 ohms? How "precise" would the manufacturing process have to be to make the probability less than 0.005 that the combined resistance of the circuit would exceed 19
Premium Standard deviation Probability theory Arithmetic mean