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    Chemistry

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    KNO3 NaOH HC2H3O2 Na2CO3 NaC2H3O2 NaHCO3 Fe(NO3)3 NaNO3 Na3PO4 HCl MgSO4 KOH HNO3 Na2SO4 NaHPO4 CuSO4 NaNO2 CoCl2 Al(NO3)3 NiCl2 H2SO4 KCl NH4Cl 12. CuSO4 CuCO3.Cu(OH)2(s) + 2 H2SO4(aq) ----> 2 CuSO4(aq) + CO2(g) + 3 H2O(l) Na3PO4 Na3PO4 (aq) + 3H2O (l) --> H3PO4 (aq) + 3NaOH (aq) 13. Arrhenius definition says that a base yields the hydroxide ion (OH-) in an aqueous solution. Arrhenius definition is dependent on substances in aqueous solutions. On the other hand

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    crystalization lab report

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    this particular experiment we will be using solvent H2O. using a hot plate bring to a boil 0.5 g of impure Benzoic Acid and about 10ml of the H2O‚ if Benzoic Acid has not dissolved continue adding small portions of H2O. Once completely dissolved place the flask in an ice bucket to cool the solution‚ you should see white crystals forming. We must then separate the crystals from the liquid by doing a vacuum filtration using Buchner funnel. With cold H2O wash the crystals‚ dry with filter paper‚ and weight

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    Chemical Reaction Lab

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    2011 Mr. Nasir Uddin Pre Lab Questions: 1. CaBr2 (aq) + K3PO4 (aq) → CA(PO4)2(S) + KBr (aq) = Ca3(PO4)2 + 6 KBr Double Replacement 2. Li(s) + O2(g) = Li2O(s) =2 Li2O Decomposition 3. CH4 + O2 = CO2 + H2O = CO2 + 2 H2O Combination 4. AgBr(s) = Ag (s) + Br2(l) = 2 Ag + Br2 Combination 5. Mg(s) + H2SO4 (aq) = MgSO4 + H2 Decomposition Table Three: Formation of Salt via Double Replacement Reaction 0.1 KNO3 * (NO3)2 0.1 M AgNO3 0.1M NaCl

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    KOH(aq) + 6 H2O 2 K[Al(OH)4](aq) + 3 H2 (g) A gelatinous precipitate of aluminum hydroxide was created when sulfuric acid was added to the aqueous solution of Al(OH)4- ions. 2 K[Al(OH)4](aq) + H2SO4 (aq) 2 Al(OH)3 (s) + K2SO4 (aq) + 2 H2O Later‚ excessive addition of the acid causes the precipitate to dissolve in the solution. 2Al(OH)3 (s) + H2SO4 (aq) Al2(SO4)3 (aq) + 6 H2O Precipitation of alum was resulted from cooling in ice water bath. K2SO4 + Al2(SO4)3 + 2x H2O 2 KAl(SO4)2

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    sucrose will over time‚ go through the process of diffusion and be distributed throughout the coffee. Osmosis is movement of H2O molecules passing through a permeable cell membrane to the less concentrated solution‚ eventually to reach an equivalent number of molecules on both sides of the cell membrane. 1.2 The important factors in the process of diffusion and osmosis is H2O being present with soluble molecules that are small enough to be absorbed through the cell membrane to then be evenly distributed

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    chloride is hydrated‚ has the formula [Ni(H2O)6]Cl2‚ and is more properly called hexaquonickel(II) chloride. If ammonia is added to a solution of this salt‚ ammonia molecules compete with the water in bonding Ni2+ and because the ammonia forms a stronger bond than water‚ the ammonia replaces the water according to: [Ni(H2O)6]Cl2(aq) + 6 NH3(aq) → [Ni(NH3)6]Cl2(aq) + 6 H2O (l) or‚ as a net ionic equation [Ni(H2O)6]2+(aq) + 6 NH3(aq) → [Ni(NH3)6]2+(aq) + 6 H2O (l) In this net ionic equation‚ the product

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    This process is summarized by a chemical equation. In the Balancing Chemical Equations Gizmo™‚ look at the floating molecules below the initial reaction: H2 + O2  H2O. 1. How many atoms are in a hydrogen molecule (H2)? 2 2. How many atoms are in an oxygen molecule (O2)? 2 3. How many hydrogen and oxygen atoms are in a water molecule (H2O)? 2 H‚ 1 O 4. In general‚ what does a subscript (such as the “2” in H2) tell you about the molecule? The subscript tells you how many atoms of each element are in

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    Preparation of Alum

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    DEPARTMENT OF PURE AND APPLIED CHEMISTRY Visayas State University Visca‚ Baybay City‚ Leyte Name: Alecsa May S. Celaya BS-Chemistry 3 Date Submitted: December 19‚ 2014 Lab. Schedule: MW 2:00 – 5:00 pm Rating: Group No. 11 Experiment No. 5 Preparation of KAl(SO4)2•12H2O (Alum) OBJECTIVES This experiment aimed to: prepare KAl(SO4)2•12H2O‚ commonly referred to as alum‚ from aluminum metal from a canned soft drink‚ and determine the mass of the alum collected and its percent yield

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    Chem 120 Exam Sample

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    the above 2. (0.5 marks) What is the mass of 0.45 mol S? Choose the closest value. A. B. C. D. E. 9.7 g 0.45 g 14 g 0.049 g 15 g 3. (0.5 marks) Balance the following equation using the smallest whole number coefficients. C5H10O5 + O2 → H2O + CO2 What is the coefficient of O2 ? A. B. C. D. E. 2 3 5 6 none of the above 4. (0.5 marks) Sulfurous acid‚ H2SO3‚ is A. B. C. a strong electrolyte a weak electrolyte a nonelectrolyte CHEM 120 (Fall 2011) 5. Test #1 (Version 001) Page

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    repair‚ survival‚ and reproduction. Photosynthesis & cellular respiration are the main pathways of energy flow in living things. Photosynthesis is a process by which plants and some other organisms convert‚ light energy from the sun‚ CO2 from the air & H2O from the earth‚ into chemical energy stored in molecules like glucose. Cellular respiration is a process in which O2 is delivered to cells in an organism & metabolic process in cells leads to the production of ATP by the breakdown of organic substances

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