hypothesis test for each sample at the .01 level of significance and determine what action‚ if any‚ should be taken. Provide the test statistic and the p-value for each test. At 0.01 level of significance │Zᾳ/2 │ = 2.58 Reject Ho when │Z│> │Zᾳ/2 │ Sample 1 Sample 2 Sample 3 Sample 4 SAMPLE MEAN 11.958 12.028 11.889 12.081 POPULATION MEAN 12 12 12 12 SAMPLE STANDARD DEVIATION 0.22 0.22 0.20 0.20 SAMPLE SIZE 30 30 30 30 Z -1.028 0.712 -2.935 2.161 RESULT ACCEPT ACCEPT REJECT ACCEPT Sample 3 is the only one
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critical method * X= 60‚ level of significance= 0.05 * Reject null hypothesis GENETICS | | | | Data | Null Hypothesis = | 0.79 | Level of Significance | 0.05 | Population Standard Deviation | 20 | Sample Size | 100 | Sample Mean | 60 | | | Intermediate Calculations | Standard Error of the Mean | 2 | Z Test Statistic | 29.605 | | | Two-Tail Test | | Lower Critical Value | -1.959963985 | Upper Critical Value | 1.959963985 | p-Value |
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sampling effort‚ Boos Allen was confident that the population average household income is $119‚155 and that the population sample household income standard deviation is $30‚000. Two Playbill executives recently hypothesized that the average annual household income of its readership has increased and so believe that the magazine price should also increase. From a 2012 sample‚ Boos Allen has profiled the new average annual household income to be $124‚450 with a population standard deviation unchanged
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NORTHCENTRAL UNIVERSITY ASSIGNMENT COVER SHEET Student: ODEDOYIN ABEL THIS FORM MUST BE COMPLETELY FILLED IN Follow these procedures: If requested by your instructor‚ please include an assignment cover sheet. This will become the first page of your assignment. In addition‚ your assignment header should include your last name‚ first initial‚ course code‚ dash‚ and assignment number. This should be left justified‚ with the page number right justified. For example: Student: ODEDOYIN A MGT
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the items included in the sample. Required 1. Identify the audit objectives that are accomplished by this test. 2. Determine sample size based on the following audit judgments. a. Tolerable misstatement is assessed at $325‚000. b. The risk of incorrect acceptance is assessed at 37 percent. c. Anticipated misstatement is assessed at $100‚000. 3. Develop a scenario that is consistent with setting the risk of incorrect acceptance at 37 percent. 4. Select a PPS sample of the above inventory population
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approach in nature. It was appropriate because this study measured the variables objectively and achieved the purpose of this study. The healing of the wound was dependent variable. It was operationalized and was monitored visually by measuring its size and by a chemical test that indicated how
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RESEARCH REPORT TOPIC: TO ASSESS THE INFLUENCE OF WOMEN ON THE BUYING BEHAVIOUR OF MEN. YEAR: 2011 TOPIC: INFLUENCE OF WOMEN ON THE BUYING BEHAVIOUR OF MEN. ACKNOWLEDGEMENT “ A MAN ATTAINS PERFECTION WHEN HIS WORK IS WORSHIP OF GOD.” We would like to give our hearty thanks to our research head Mrs. Nivi Srivastava for constant support and guidance. Without her support it was a task next to impossible. She has been a constant motivator for the whole team. The final report is a result
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Wilson‚ F.‚ Brown‚ D.‚ Stephens-Ferris‚ M. (2006). Can easy-to-read immunization information increase knowledge in urban low-income mothers. Journal of Pediatric Nursing‚ 21(1)‚ 4-12. doi:10.1016/j.pedn.2005.06.003 Aspect of the Report Critiquing Questions Student Assessment Title Is the title a good one‚ succinctly suggesting key variables and the study population? The title is sufficiently brief yet describes key variables such as immunization information‚ urban-low income mothers‚ increased
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Statistical Results Statistic Current Model New Model Sample Mean 270.275 267.500 Standard Error 1.3840 1.5648 Standard Deviation 8.7530 9.8969 Sample Size 40 40 Confidence Level (95%) 2.62 3.14 Degrees of freedom 39 39 t = 1.33 Comparisons 1. A two tail hypothesis test was conducted based on the sample studies of 40 current and 40 new golf balls. The testing was performed with a machine designed to hit the ball the same every time. Both samples were tested with the same machine to ensure consistent
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population’s size. A portion of the population is captured‚ marked‚ and released. Later‚ another portion is captured and the number of marked individuals within the sample is counted. Since the number of marked individuals within the second sample should be proportional to the number of marked individuals in the whole population‚ an estimate of the total population size can be obtained by dividing the number of marked individuals by the proportion of marked individuals in the second sample. The method
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