3‚000/5 = 600 Solution 2: The variance for x is 5‚000‚000 The variance for y is 5‚050‚000 Solution 3: The Standard deviation is found by squaring the result of the variance: SD of x = 2236‚ this tells us on average how far is from sample mean. SD of y = 2247 Solution 4: The coefficient of variation is as follows: The coefficient of variation for x is: 0.000447. The coefficient of variation for y is: 0.000445. Solution 5: On the argument that the SD of the first is greater
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NORTHCENTRAL UNIVERSITY ASSIGNMENT COVER SHEET Student: ODEDOYIN ABEL THIS FORM MUST BE COMPLETELY FILLED IN Follow these procedures: If requested by your instructor‚ please include an assignment cover sheet. This will become the first page of your assignment. In addition‚ your assignment header should include your last name‚ first initial‚ course code‚ dash‚ and assignment number. This should be left justified‚ with the page number right justified. For example: Student: ODEDOYIN A MGT
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MM207 Final Project Name: Eddie S. Jackson 1. Using the MM207 Student Data Set: a) What is the correlation between student cumulative GPA and the number of hours spent on school work each week? Be sure to include the computations or StatCrunch output to support your answer. My answer : 0.27817234 (from StatCrunch): Correlation between Q10 What is your cumulative Grade Point Average at Kaplan University? and Q11 How many hours do you spend on school work each week? is: 0.27817234 b)
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the items included in the sample. Required 1. Identify the audit objectives that are accomplished by this test. 2. Determine sample size based on the following audit judgments. a. Tolerable misstatement is assessed at $325‚000. b. The risk of incorrect acceptance is assessed at 37 percent. c. Anticipated misstatement is assessed at $100‚000. 3. Develop a scenario that is consistent with setting the risk of incorrect acceptance at 37 percent. 4. Select a PPS sample of the above inventory population
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Statistics – Case Chapter 9 1. It is not proper to multiply the average order size by the number of addresses (1.3 million people = population) in the target mailing because the sample is representative of the 600‚000 people in the database‚ not the 1.3 million target population‚ thus you cannot use the average of the sample as an estimate for the population. Also‚ multiplying by 1.3 million would suggest that the entire 1.3 million people would be purchasing. 2. It is better to multiply the endpoints
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zero‚ what would this mean? * Sampling error is the difference between the statistic estimated from a sample and the true population statistic. It is not impossible for the sampling error to not be zero. If the sampling error is zero then the population is uniform. For example if I were evaluating the ethnicities of a populations and everyone is the population was Black then taking any sample would give me the true proportion of 100% Black. 22. List the reasons for sampling. Give an example of
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No Yes Improvements in any process start Statistical process control‚ which is the random testing of a sample of output from the process to determine whether the process is producing items within a preselected range (Chase‚ Jacobs‚ & Aquilano‚ 2006). These samples may be either fit or unfit for example taking random samples from a batch of newly made Motorola I Pad. Testing may discover that some will work accordingly whereas other will not power on. Companies
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Collegiate Athletic Association (NCAA) reported that the mean number of hours spent per week coaching and recruiting by college football assistant coaches during the season was 70. A random sample of 50 assistant coaches showed the sample mean to be 68.6 hours‚ with a standard deviation of 8.2 hours. A. Using the sample data‚ construct a 99% confidence interval for the population mean. The confidence interval is as follows: 68.6- 2.58*8.2/ã50‚ 686+ 2.58*8.2/ã50 CI(65.6-71.5) B. Does the 99%
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$52 with a standard deviation of $4.50. A group of smart statistics students thinks that the average cost is higher. In order to test the bookstore’s claim against their alternative‚ the students will select a random sample of size 100. Assume that the mean from their random sample is $52.80. Perform a hypothesis test (6 step procedure outlined in class) at the 5% level of significance and state your decision. 2. A certain chemical pollutant in the Genesee River has been constant for several years
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distribution when the null hypothesis is true‚ or any in which this is asymptotically true‚ meaning that the sampling distribution (if the null hypothesis is true) can be made to approximate a chi-square distribution as closely as desired by making the sample size large enough. The Chi-Square ( ) test is the most popular non-parametric test/methods‚ to test the hypothesis. The symbol is the Greek letter “chi”. Like other hypothesis testing procedures‚ the calculated value of -test statistics is compared
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