point and melting point when adding impurity (salt) to water. Diagram: Method: 1.Set up the apparatus as shown in the diagram 2. Get a known amount of ice in the beaker (half full)‚ and a known amount of salt in another beaker 3. Measure the temperature (melting point) of the ice without adding any impurity (salt). 4. Measure the temperature (melting point) of the ice after adding the salt into the beaker. 5. Heat up the beaker with both ice and salt inside 6. Wait until the substance in the
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Next‚ the salt will be separated from the mixture. In order to do this‚ a ring stand must be set up with an iron ring and a glass funnel. Take a piece of filter paper and fold it as demonstrated by Mrs. Montoney‚ and place it in the funnel. 8. Place a 250mL beaker under the funnel for the filtered water. 9. Put the remaining mixture in the funnel. 10. Pour some water in a beaker‚ record the amount of water and pour it in the funnel. The mixture will begin to filter and drain the salt‚ leaving
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Solubility product The Solubility product is related to SPARINGLY SOLUBLE SALTS ONLY!!!!! Examples are silver chloride‚ lead(II) chloride‚ calcium sulphate (in other words‚ it deals with salts commonly called insoluble salts) Consider a sparingly soluble salt MX Imagine the reaction that occurs when the solid is placed in water aMX (s) + H2O [pic] aMn+ (aq) + bXm- (aq) The equilibrium expression would be [Mn+]a [Xm-]b [MX]a [H2O]
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acid + metal -------->salt + hydrogen acid + metal oxide--->salt + water acid + metal carbonate---->salt + water + carbon dioxide Element | Symbol | Valency | Hydrogen | H | 1 | Oxygen | O | -2 | Carbon | C | 4 | Calcium | Ca | 2 | Iron | Fe | 2 | Aluminium | Al | 3 | Sodium | Na | 1 | Potassium | K | 1 | Magnesium | Mg | 2 | Zinc | Zn | 2 | Copper | Cu | 2 | Silver | Ag | 1 | Lead | Pb | 2 | Chloride | Cl | -1 | Sulphate | SO4 | -2 | Hydroxide | OH
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which was CuSO4 ?H20. Not only the percentage of water can be found‚ the moles of water can be found per one mole of anhydrous salt. An anhydrous salt is a hydrate that lost its water. Using various lab equipment such as burners‚ crucible‚ and balance‚ and techniques such as the mass-to-mole ratio and mass to percentage‚ the percentage of water in a hydrate was determined. Salts appear to be dry‚ yet when heated‚ surprisingly large quantities of water are driven off‚ because water is loosely bonded to
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immediately with a wet sponge or foam brush. INTRODUCTION If an opinion is said to not hold water it means that the point of view or statement put forward is illogical‚ inadequate‚ not sound or can be shown to be wrong. Hydrates are inorganic salts that hold water. They contain a specific number of strongly bonded water molecules as part of their crystal structure. Such water molecules are called water(s) of hydration‚ or water(s) of crystallization. The formula of a hydrate consists of the formula
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to Consensus Action on Salt and Health (CASH)1 the promotion of extremely high salt foods targeted at school lunchboxes is an unethical marketing practice. Four out of five items surveyed by CASH used a combination of at least three marketing techniques to specifically aim at children. "The use of marketing practices targeted at children to sell highly salted products is unethical." says Registered Nutritionist and Chartered Marketer‚ Kathy Lewis of Consensus Action on Salt and Health. "Ethical practices
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BUFFERS By: Luis P. Bazan‚ RPh.‚ Ph.D. A buffer solution is a solution of: 1. A weak acid or a weak base and 2. The salt of the weak acid or weak base Both must be present! A buffer solution has the ability to resist changes in pH upon the addition of small amounts of either acid or base. Consider an equal molar mixture of CH3COOH and CH3COONa CH3COOH (aq) H+ (aq) + CH3COO- (aq) Adding more acid creates a shift left IF enough acetate ions are present 16.3 Which of the
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separate components of a heterogeneous mixture can be separated by using differences in the components’ physical properties. In this laboratory experiment‚ I attempted to experimentally verify that the components of a heterogeneous mixture containing salt‚ sand‚ and benzoic acid can be separated using the separate components’ solubility properties (ability to dissolve in water). Because it is known that organic compounds (such as benzoic acid) are very soluble in organic solvents‚ a hexane: ethanol
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2 Plastic cups 2. Tap Water 3. Teaspoon 4. Bag of salt 5. Freezer 6. Clock 7. Paper 8. Pencil Procedures: 1. Take plastic cup and pour in one cup water in each 2. Take one teaspoon of salt and mix it in one of cups 3. Put both cups in the freezer 4. Observe. Conclusion: When salt is added to water it slows the freezing process down‚ therefore the freezing point of tap water is higher than the freezing point of salt water. Hypothesis: If... ‚ then...
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