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    Number and Rs.

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    _____________Download from www.JbigDeaL.com Powered By © JbigDeaL____________ NUMERICAL APTITUDE QUESTIONS 1 (95.6x 910.3) ÷ 92.56256 = 9? (A) 13.14 (B) 12.96 (C) 12.43 (D) 13.34 (E) None of these 2. (4 86%of 6500) ÷ 36 =? (A) 867.8 (B) 792.31 (C) 877.5 (D) 799.83 (E) None of these 3. (12.11)2 + (?)2 = 732.2921 (A)20.2 (B) 24.2 (C)23.1 (D) 19.2 (E) None of these 4.576÷ ? x114=8208 (A)8 (B)7 (C)6 (D)9 (E) None of these 5. (1024—263—233)÷(986—764— 156) =? (A)9 (B)6

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    the flow over a sphere.The flow around the bluff body was characterised using smoke test‚ and the region of flow separation was analysed. The drag characteristics of 3 spheres of different diameters were studied for a wide range of Reynolds number. The Reynolds number at which the transition occurs is strongly dependent on the degree of turbulence in the wind tunnel. Based on the following tests‚ the quality of the wind tunnel was determined. The turbulence level in the wind tunnel was experimentally

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    projected area is easily calculated from measured dimensions‚ and the density of the air can be measured or assumed. The drag coefficient can be calculated from experimental results and parameters. It depends on parameters such as the body’s shape‚ Reynolds number and surface roughness. The power (energy ratio) obtained in the test section versus the power input from the fan is described as Equation 2

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    Pipe Friction

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    Summary The purpose of this lab is to find the friction factor and Reynolds number for laminar and turbulent flow and also for values in the critical zone. Results were taken recorded and used to calculate the friction factor and Reynolds number. They were then compared with the Moody diagram. Aim This lab could be used in industry when dealing with a pipe line containing any type of liquid to calculate the Reynolds number and friction factor. It would also help in pipe and pump selection

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    Pipe Report

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    velocity in the pipe (remains constant) the friction factor f is defined by And the Reynolds number can be obtained by For typical flows in smooth pipes‚ laminar flow corresponds to Re<2300‚ and the turbulent flow corresponds to Re>4000‚ and the laminar/turbulent transition is 2300<Re<4000. During the experiment we will analyze the friction loss in a pipe system. And also how to calculate the Reynolds number to know if it is laminar or turbulent flow. Procedure: We verify that all the components

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    Pipe Friction Report

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    For constant conditions limits of flow‚ Osbourne Reynolds showed in 1883 that there are two kinds of flows according to the value of a dimensionless number called the Reynolds number and noted: ReD =ρV Dμ‚ where V is the flow velocity‚ D a characteristic size‚ and v the fluid kinematic viscosity. When the Reynolds number is low‚ the current lines are stationary‚ and the flow is said laminar. In contrast‚ when the Reynolds number is higher‚ the streamlines become unsteady and the flow is

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    Relationship between a model and Similitude For a model‚ similitude is achieved when testing conditions are created such that the test results are applicable to the real design. There are some criteria that are required to achieve similitude; 1. Geometric similarity – The model is the same shape as the application (they are usually scaled). 2. Kinematic similarity – Fluid flow of both the model and real application must undergo similar time rates of change motions. (Fluid streamlines are similar)

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    not applicable to fluids makes even the simplest tests to be a time consuming exercise. However‚ despite all these obstacles‚ over the years‚ people have managed to properly quantify the flow of a fluid. By establishing a dimensionless number called the Reynoldsnumber‚ it is possible to divide various flows into three separate regions wherein each region with its governing equations. Introduced by the famous mathematician Stokes and

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    Consideration of the basic factors affecting road vehicle drag and their associated affects 0718572 School of Engineering‚ University of Warwick Coventry‚ West Midlands‚ U.K Abstract: It is possible to improve the aerodynamic efficiency of road vehicles and reap many benefits. Fuel consumption being one of them‚ this report identifies how basic theoretical and experimental fluid mechanics can work in harmony to allow one to understand the key mechanisms that affect the aerodynamic properties

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    me309

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    However‚ when a Reynolds number reach about 300‚000‚ and the sphere is the largest one; for this case‚ the drag coefficient drops abruptly. We also found that for the same wind speed‚ the larger sphere has larger Reynolds number. The figure below illustrates the relationship between Reynolds number and drag coefficient. The results obtained from this experiment also tend to show the same relationship. Stoke’s Theory predicts that the drag coefficient decreases as the Reynolds Number less than 1000

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