APCOMS | DIGITAL IMAGE PROCESSING | ASSIGMNENT | | SIR SHAHID ISMAIL | 29-May-13 | | GROUP MEMBERS: USAID SHUAIB F-3313 AHMED TAUQIR F-3324 HAMMAD SHEIKH F-3325 GROUP MEMBERS: USAID SHUAIB F-3313 AHMED TAUQIR F-3324 HAMMAD SHEIKH F-3325 Representation Segmentation techniques yield raw data in the form of pixels along a boundary or pixels contained in a region. These data sometimes are used directly to obtain descriptors. Standard uses techniques to compute
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pair of vertical angles. APD and APC are 9. A diagonal is a line segment in a polygon connecting any two nonconsecutive vertices. 10. If two lines lie in the same plane and are perpendicular to the same line‚ then they are parallel. 11. If the sum of the measures of two angles is 180°‚ then the two angles are complementary. 12. A trapezoid is a quadrilateral having exactly one pair of parallel sides. 13. A polygon with ten sides is a decagon. 90 Chapter 1 Introducing Geometry © 2008 Key
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around us is made of shapes‚ from the smallest type of micro-organisms to the biggest structure you will ever see in your life. They are the faces of the 3D solids we see around us‚ either being there in its own‚ or being a mix between two or more polygons. Shapes resemble different things and delivers different thoughts when looking or passing by them through the day. Putting these shapes or joining the to form volumes gives as a huge number of volume‚ they could be in the form of Cubes
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Christopher Lothman Geometry Distance Formula: Translation A’ (10‚ 1) B’ (2‚ 1) C’ (2‚ 7) Rule: (x‚ y) > (x 8‚ y + 4) A2C2 = sqrt(((2 (10))^2) + ((7 1)^2)) = 10 AC = sqrt(((6 (2))^2) + ((3 (3))^2)) = 10 A2C2 = AC A2B2 = sqrt(((2 (10))^2) + ((1 1)^2)) = 8 AB = sqrt(((6 (2))^2) + ((3 (3))^2)) = 8 A2B2 = AB B2C2 = sqrt(((2 (2))^2) + ((7 1)^2)) = 6 BC = sqrt(((6 6)^2) + ((3 (3))^2)) = 6 B2C2 = BC Triangle A2B2C2 = Triangle ABC by construction
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1. Find the distance between the points (a) (0‚ 2) and (3‚ 6) (b) (-2‚ 3) and (4‚ -5) © (2‚ -5) and (-3‚ 7) 2. Find the exact length of the interval between points (a) (2‚ 3) and (-1‚ 1) (b) (-1‚ 3) and (-7‚ 7) 3. Prove that the triangle with vertices (3‚ 4)‚ (-2‚ 7) and (6‚ -1) is isosceles. 4. Show that the points (3‚ -4) and (8‚ 1) are equidistant from the point (7‚ -3). 5. Prove that the points X(2 ‚ -3)‚ Y(-1‚ 10 ) and Z(-6 ‚ 5 ) all lie on a circle with centre at the origin. 6. If
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examples. 2. Ask the students to tell what the names of their figures are. 3. Tell the students that today we are going to learn about what are the kinds of plane figures are. B.2 LESSON PROPER Shapes can be polygons → A closed plane figure made up of line segments. | A polygon with 3 sides | A 4-sided figure with 4 right angles and opposite sides parallel and the same length | A 4-sided figure that has 4 equal sides and 4 right angles | A 4-sided figure that has exactly one pair
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Punctuality. What it is Some men are in the habit of doing their duties in time. They attend office in time‚ they open their shops in time‚ they go to see a person in time. This habit of doing a thing in time is called punctuality. Benefits Punctuality is a good habit. It saves much of our time. Many things can be done within a short time if we are punctual. Time does not wait for anybody. If time is once gone we cannot bring it back. We leave many things often undone. It is‚ therefore
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Construct a perpendicular line through a point on the given line. Construct a perpendicular line through a point not on the given line. Construct an equilateral triangle inscribed in a circle. Construct a square inscribed in a circle. Construct a regular hexagon inscribed in a circle. Part 2: Explanation: Using complete sentences‚ explain how you created two of the three constructions from part 1. To create a line segment and copy it‚ I connected points a and b to create a line segment. Then
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1. Use the values given in the above triangle and find the value of B‚ b‚ and c. A. A+B+C=180 B. A+C=48+97=145 C. B=180-145=35 2. Two sides and an angle (SSA) of a triangle are given. Determine if the given measurements produce one triangle‚ two triangles‚ or no triangle at all. Sin B)/5=sin70/7 Sin B/5=0.9397/7 Sin B=0.6712 then B=42 or 138〗 B = 138 is impossible since 138 + 70 = 208 and exceeds 180 B=42 since 42+70 = 112 and less than 180 C = 180 – 112
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09.03 Module 9 Quiz Saje McDowell Question 1: Campsite #1‚ lookout tower‚ and campsite #2 form a central angle within the circle. If the angle formed is 120°‚ describe the relationship between the angle and the arc it intercepts. You must show all work to receive credit. Since the central angle is 120 degrees‚ the arc BEC would be its intercepted arc. Since a intercepted angle and a central angle have the same value‚ it would be 120 degrees. Question 2: An inscribed angle is formed by lookout
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