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    Title : C2 Investigating the capacitance of a capacitor I. Objective : * To investigate the factor which affect the capacitance of a parallel-plate capacitor using a reed switch. II. Apparatus * Reed Switch * Signal generator * Capacitor Plates (1 pair) * Polythene spacers * Low voltage power supply * Voltmeter * Variable resistance * Light-beam galvanometer * CRO * Standard mass (eg. 100g ) * Connecting leads * Drawing board *

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    Dc Power Supply Report

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    Objectives To design a 12-volt DC power supply with a maximum output current of 200mA. To reduce the ripple factor to a value less than 0.1%. Apparatus 120-volt rms 60Hz input 60 ohm to 1k ohm load resistor 10 to 1 step-down transformer FWB bridge Voltage Regulator 2 100nF capacitors 10uFcapacitor 4.7 uF Capacitor Overview The goal of this experiment was to construct a power supply that would convert a 120-volt 60 Hz input ‚such as that received from a wall socket‚ to a 12-volt

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    Construction of Paper-and-Pencil Test School: Kingston College Subject: Physics Grade: 11-1 Date: October 23‚ 2013 Duration: 2.5 hours INSTRUCTION TO CANDIDATES You are allowed ten (10) minutes to read the instructions and write your name‚ date and ID number on the answer sheets provided. Answer ALL questions in EACH section.

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    Seligram Solution

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    Seligram Case Study Presented To: Dr. Khaled Hegazy Presented By: Mona Abdallah Student ID: 131239 Question 1: What caused the existing system at ETO to fail? The existing cost system failed because of four main reasons. 1-The existing cost system is related to direct labor hour. One cost pool used for cost allocation under assumption: All product lots use direct labor and Overhead in the same proportion. 2- Cost system doesn’t match the complex business model. 3- New trends in

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    1. Suppose you are working as an operator in a call centre in India and receiving calls from Americans and Londoners. How would you handle such calls? Ans: As an operator first thing which I would try and ask politely would be that what is the route cause of the problem of the customer and would try and give time for explaining or removing out the frustration after which the customer would then have patience in listening to what we would try and explain. As an operator I would rectify the problem

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    Some of the hypothesis in this experiment supported the results and some of the other hypothesis rejected the results. Some hypothesis which supported the results were that the there would be about one‚ two‚ or three channels in the radio‚ the bobby pin could not replace the germanium diode‚ and that the crystal radio ware efficient as a normal store bought radio. On experiment two the crystal radio had like 3 stations. The sound was very clear and loud. Also‚ the bobby pin method did not work.

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    phy lab

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    EC1 VI-1 The results of experiment EC1 part V1 are summarized as below. V‚ I‚ Rm are directly measured   Resistor A Resistor B Resistor C Resistor D V±ΔV(V) 6.748±0.001 7.759±0.001 9.061±0.001 10.383±0.001 I±ΔI(mA) 44±0.5 35±0.5 23±0.5 10±0.5 V/I±ΔR(Ω) 153.36±1.7 221.69±3.2 393.96±8.61 1038.30±52.02 Rm±ΔRm(Ω) 145.21±0.01 214.90±0.01 385.60±0.01 907.50±0.01 VI-2 (V‚ I) pairs for Resistor A using a DC power supply V-2 f = 0 Hz # V(Volts) I(mA) 1

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    Ultrasonics

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    Signal amplification circuit The ultrasonic signal which was received with the reception sensor is amplified by 1000 times(60dB) of voltage with the operational amplifier with two stages. It is 100 times at the first stage (40dB) and 10 times (20dB) at the next stage. As for the dB (decibel)‚ refer to "Logarithm Table". Generally‚ the positive and the negative power supply are used for the operational amplifier. The circuit this time works with the single power supply of +9 V. Therefore‚ for the

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    voltage doubler rectifier in particular the Greinacher voltage doubler rectifier‚ where the components used are mainly capacitors‚ diodes. Light emitting diode (LED) and 3-turn coil are also incorporated into Design 2 and Design 3 circuits. There are two main reasons of using a voltage doubler rectifier. Firstly‚ the LED require a forward voltage of 1.7V to 2.2V‚ and the 3-turns coil on the implant will not be able to pick up that much AC voltage‚ thus a voltage doubler rectifier is used to double

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    A Visit to a Forest

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    foil that "breaks" a circuit as the glass is broken. It is an alarm that is triggered when the protective circuit is opened. Circuit Operation:- The circuit consist of a n-p-n transistor‚ an alarm working on 6V DC and a SCR (Silicon Controlled Rectifier). The transistor is biased in voltage divider mode. the out put is taken from the emitter which is fed to the SCR gate. The transistor biasing circuit acts as a voltage follower to the SCR. When the protective circuit is closed‚ the transistor works

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