Ionic Reactions Introduction: Today we are going to observe the chemical changes when mixing two solutions. Some will change colors‚ produce gases proving if the solutions are soluble or insoluble. Materials and Methods: I first pulled out the small wells and place two drops of the Cobalt (II) Nitrate in seven of the wells. I then moved to the next row and placed two drops of Copper (II) Nitrate in the next row‚ into seven of the wells‚ and so on with the other three Nitrates. I then cut off
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Calculations CALCULATION IN ORDER TO FIND THE PERCENTAGE OF VITAMIN C Chemical reaction: C6H8O6 + I2→ 2I + C6H6O6 Ascorbic Acid: C6H8O6 Relative formula mass of C6H8O6= (12.01076) + (1.007948) + (15.99946)= 176.12412 g/mol Convert Iodine lost from mL to dm-3 = Iodine lost in mL1000= Iodine lost in dm-3 Convert Iodine lost (dm-3) to moles (n) by multiplying it with the concentration of Iodine used: n=0.005 Iodine lost in dm-3= mol of C6H8O6 Find the mass (g) of C6H8O6 in 50 mL by using this
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The progress of the reaction was monitored in my case using two TLC plate. It first started off with the spotting of Standard benzoin and benzil which were provided in the lab and followed by the addition of the reaction mixture at once it starts changing colour/boiling‚ then at 10 and 20 mins into the reflux. Once all the necessary steps were spotted‚ the TLC plate was placed in in a beaker containing CH₂Cl₂(methylene chloride)‚ which was used as the developing solvent in this experiment. To check
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Qualitative Observations of Double Displacement Reactions Lab Table 1.0 Qualitative Observation of Products Formed |Balanced Chemical Equations |Qualitative Observations | |BaCl2 (aq) + 2NaOH (aq)( BaOH2(aq) + 2NaCl(s) |An aqueous solution formed | | |Precipitate
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The Equilibrium Constant of an Ester Hydrolysis Reaction Julia Stanley CHM 152 LL Dr. Asmita Kane Budruk Goal of the lab: The purpose of this laboratory is to determine the equilibrium constant‚ Kc‚ for the acid-catalyzed reaction between an unknown ester and water to produce an unknown alcohol and an unknown carboxylic acid. I was using Unknown Ester #3 with a density of 0.9342 and Molar Mass of 74.08 g/mol; alcohol with density 0.7914 and Molar Mass 32.04 g/mol. Chemical
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term structure of interest rate we need to elaborate how interest rates function and how they are determined. Interest rates are a vital tool to all the macro-economic policy objectives of a government such as control of inflation‚ investment as well as employment. Interest rates refer to the price paid by deficit agents for borrowing funds from the surplus agents. A line that plots interest rate at a set point in time is the term structure or yield curve. Interest rates which may be short term or
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the difference in heart rates before and during intense exercise. Aim: The aim of the investigation was to discover how the heart rate varied with the intensity of exercise. The heart rate is a term describing the regularity of the cardiac cycle. The heart rate is the amount of times it contracts (beats) in a unit of time‚ nearly always per minute. At rest the adult female’s heart rate regulates 75 bpm (beats per minute) but this varies between people. If the heart rate is measured before‚ during
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Project report On Rate of Exchange and Foreign Investment The Indian case from 2009-10 to 2011-12 Acknowledgement As a part of PGDM curriculum at Birla Institute of Management Technology‚ the preparation of this project report has been a unique and rewarding experience. Apart from our efforts‚ the success of any project depends largely on the encouragement and guidelines of many others. We take this opportunity to express our gratitude to the people
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Class Time on Thursday‚ 7/18 1. | London | New York | Spot Exchange Rate ($/GBP) | 1.3264 | 1.3264 | Interest Rates | 3.900% | 4.500% | Expected Inflation Rates | 0.650% | 1.250% | a. What is the expected rate of inflation in London? iPC - iBC = PC - BC 4.500% - 3.900% =1.250% - BC PC = 0.650% b. Using Uncovered Interest Rate Parity‚ what is the value of the expected spot exchange rate in two years? E(ST) = S0 * [(1+i)/(1+i*)]T E(S2) = 1.3264 * [(1.045)/(1.039)]2
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Russia Exchange rate system Russia used to pledge its nominal exchange rate with some main currencies such as US dollar. However‚ the Russian crisis has forced Russia to develop managed floating exchange rate system‚ where the exchange rate driven by market forces of the Ruble’s demand and supply with the help of government intervention. With this exchange rate‚ the government can ensure stability and predictability of ruble exchange rate and prevent abrupt fluctuation of the Ruble rate. Moreover‚
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