Determination of Rate and Order of a Reaction Results This experiment used a spectrometer to find the wavelength with maximum absorbance in a green food coloring solution. For this particular solution the wavelength was 629.7 nm. The system was then calibrated to that and was set to measure the food coloring and bleach solution. The measured visible light absorbance of the mixed solution was collected over a time of 200 seconds and eight points were then selected and placed into the Absorbance
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Title: Kinetics: The Rate of a Chemical Reaction Objectives: 1. To study the kinetics of chemical reaction‚ 2 I- + S2 O82- I2 + 2 SO42- . 2. To study the effects of reactant concentration (persulphate‚ S2O82-‚ and iodide‚ I-) and temperature on the rate of chemical reactions. ( i) Study the effect of 0.20M (S2O82-) on the rate of chemical reaction. ( ii) Study the effect of 0.10M (S2O82-) on the rate of chemical reaction. ( iii) Study the effect
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Demonstration of the Rates of Reaction Between Sulphuric Acid (25mL ±0.5mL) and Magnesium (0.02g ±0.01g) Changing Due to Different Surface Areas By Chania Baldwin Introduction: When sulphuric acid and magnesium are added together‚ magnesium sulphate and hydrogen gas is created. To create such a reaction the atoms must collide with a sufficient amount of energy. Every reaction requires a different amount of energy to create the reaction‚ which is called the activation energy; when there is not enough
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Lab Report: How Temperature affects Reaction Rate Aim: The Aim is to investigate how temperature can affect Reaction Rate. The experiment will be performed by heating equally sized and weighted lime stones with equal amounts and concentration of Hydrochloric acid at different temperatures. The temperatures will be 35˚C and 40˚C. We will measure the reaction rates by observing gas release of the reaction between lime stones and Hydrochloric acid. The amount of gas release at different
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Title: Effect of a Catalyst on Reaction Rate II. Introduction: The basis of the experiment is the enzyme; an enzyme is a biological molecule that acts as a highly selective catalyst. By combining with a substrate‚ an enzyme is able to create a new product that helps the body function. (Ex. Lactose/Lactase) A substrate is a molecule an enzyme acts upon‚ the two combine at an area called an active site. This active site allows induced fit which allows the reaction to occur and a new product to be
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environments affecting the rate of reaction‚ PNPP (p-nitrophenyl phosphate) + H20 ? PNP (p-nitrophenol) + H3P04. This reaction is catalyzed by the enzyme phosphatase. Different environments produced different reaction rates as environmental factors affect the efficiency of phosphatase. This is because environmental factors can change the tertiary structure of phosphatase‚ which alters its active site‚ and thus changes its efficiency to catalyze the reaction. We measured the rate of reaction‚ by using a chromogenic
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The Effect of the Number of Drops of HCl and NaOH on the Net Change in the pH of Plant‚ Animal‚ and Nonbiological Solutions Research Question: How do plants and animals respond to changes in pH? Analysis Questions: Summarize the effects of HCl and NaOH on the tap water. HCl is an acid and when in tap water‚ dissociates into H+ and Cl-. Since it releases the H+ ion in the tap water‚ it raises the concentration of H+‚ which lowers the pH of the tap water. Unlike HCl‚ NaOH is a base. NaOH is a base because
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RESULTS AND DISCUSSION REPORT—EXPERIMENT 3 (CHEMICAL KINETICS) CALCULATIONS Effect of Concentration on Reaction Rate [S2O32-]initand [H+]init for each run‚ knowing the original concentrations and volumes of [S2O32-]‚ [H+]‚ and water used. [S2O32-]init= __(M[S2O32-])(V[S2O32-])__ [H+]init= _____(M[H+])(V[H+])____ V[S2O32-]+V[H+]+V[water] V[H+]+V[S2O32-]+V[water] Run 1 [S2O32-]init= (0.15 M)(10 mL) (10+3+2)mL = 0.1 M [H+]init= (3 M)(2
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Affecting Rate of Reaction Introduction Hydrogen Peroxide (H2O2)‚ is the most simple peroxide and commonly used in several household items such as toothpaste or as an alternative to bleach. However hydrogen peroxide it is a very dangerous substance when accumulated in large amounts. If that situation occurs this substance must be decomposed. But how can we decompose this reaction? Well it decomposes by itself very slowly (2H2O2(aq) -> 2H2O(l) + O2(g))‚ but that would take too long. This reaction can
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initial rate of reaction. I will measure the effect of the enzyme in 5 different concentrations against the controlled variable of the reactant. The enzyme which will be used is different concentrations of potato and the reactant used will be Hydrogen Peroxide. Hydrogen Peroxide which will be the buffer solution is a PH of 7.2. My hypothesis for the experiment is that as the concentration of the enzyme is increased the rate of reaction will be increased‚ producing oxygen at a faster rate. The results
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