Time =40 z= (40-43)/2.38 = -1.26 Cumulative probability= 0.1038 or ~ 10% The critical activities are B‚ C‚ E‚ F‚ H‚ J and K. The project should be completed (earliest finish) in 43 weeks - therefore R.C. Coleman’s 40 week completion time cannot be achieved. The probability of R.C. Coleman meeting the 40 week deadline is ~10%. This is a low chance‚ so they should be cautioned if they make 40 weeks their deadline. 2. 80% of a probability of ~0.7995 has a z score of 0.84. Thus
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technicians‚ 4 engineers‚ 2 executives‚ and 50 factory workers. If a person is selected at random‚ what is the probability that he or she is a factory worker? A) 1 4 B) 1 8 C) 5 8 D) 2 5 An apartment building has the following distribution of apartments: 1 bedroom 2 bedroom 1st floor 3 1 2nd floor 2 2 3rd floor 1 4 3 bedroom 1 2 1 If an apartment is selected at random‚ what is the probability that it is on the 2nd floor or has 2 bedrooms? A) 7 11 B) 6 11 C) 13 17 D) 11 17 Box A contains
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expected time versus the first three options above. With the 10.38% probability of the project’s ability to be finished in 40 weeks‚ it is highly recommended to allow at least another two weeks to allow the project to be completed with fewer errors. However‚ if it is not feasible to allow this extra time for the expansion the following two clauses below will further define the possibilities available to increase the probability of earlier completion and the additional costs it would take to undergo
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made to high-risk borrowers. What is the probability that a high-risk borrower will default? 2. A fund manager is considering investing in the stock of a healthcare provider. The manager’s assessment of probabilities of the rates of return on this stock over the next year is summarized in the table below. |Rate of return |Less than -10% |-10% to 0% |0% to 10% |10% to 20% |More than 20% | |Probability |0.04
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measured in each. Assuming that the tobacco company’s claim is true‚ what is the probability that the mean tar content of the sample is greater than 4.15 milligrams? [0.00621] 2. The safety limit of a crane is known to be 32 tons. The mean weight and the standard deviation of a large number of iron rods are 0.3 ton and 0.2 ton respectively. One hundred rods are lifted at a time. Compute the probability of an accident. [0.1587] 3. A soft –drink vending machine is
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IEEE TRANSACTIONS ON WIRELESS COMMUNICATIONS‚ VOL. 8‚ NO. 11‚ NOVEMBER 2009 5601 A Comprehensive Analysis of Low-Power Operation for Beacon-Enabled IEEE 802.15.4 Wireless Networks Yu-Kai Huang‚ Student Member‚ IEEE‚ Ai-Chun Pang‚ Senior Member‚ IEEE‚ and Hui-Nien Hung Abstract—ZigBee‚ a unique communication standard designed for low-rate wireless personal area networks‚ has extremely low complexity‚ cost‚ and power consumption for wireless connectivity of inexpensive‚ portable‚ and moving
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Chapter 1: Permutations 1. In how many ways can three different awards be distributed among 20 students in the following situations? a. No student may receive more than one award. b. There is no limit on the number of awards won by one student. Answer: a) 6840 b)8000 2. Consider the word BASKETBALL: a. How many permutations are there? b. How many permutations begin with the letter K? c. How many permutations
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科目：企業決策 Case: Starting Right Corporation |1. Sue Pansky | |Alternatives |States of Nature | | |Profit or loss in |Profit or loss in | |
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10000 Total 1000 5‚970 129520 a. b. c. The probability that a bar containing $50 or $100 bill is purchased is 30 / 1000 = 0.03 Hence customer have to buy 100 bars of soap‚ so that he or she has purchased three bars containing a $50 or $100 bill. d. Given n=1000‚ E(X) = 5.97‚ SD(x) = 9.68912 The probability that a soap contains a bill of $20 or above is 100 / 1000 = 0.0.1 Binomial with n =8‚ p = 0.1 Hence the probability that at least one of these bar contains a bill of $20
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Model 2-door 4-door Automatic 135 351 Manual 251 213 If a car is picked at random from the fleet‚ calculate the probability that it is: (i) automatic‚ (2 marks) (ii) automatic or 2-door‚ (2 marks) (iii) manual and 4-door‚ (2 marks) (iv) 2-door given that it is manual transmission. (2 marks) 4. Consider a random variable M with the probabilities specified in the following figure: k 3 6 9 12 15 P (M = k) (i) Find E (M). (2 marks) (ii)
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