Transformation of Amyloplasts into Chloroplasts in Potato Tubers’ Received for publication November 9‚ 1983 and in revised form January 19‚ 1984 YU S. ZHU‚ DENISE L. MERKLE-LEHMAN‚ SHAIN D. KUNG* Department of Biological Sciences‚ University of Maryland Baltimore County‚ Catonsville‚ Maryland 21228 ABSTRACT The transformation of amyloplast into chloroplasts in potato (Solawum tuberosum L.) tuber tissue can be induced by light. Excised potato tuber discs illuminated with white light of 3000
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Potato Osmosis and Diffusion Lab Report Emily Cocq Research Question: Will there be a difference in the experimented potato cores after being subjected to high concentrations of sugar? Introduction: Water can move through protein channels in cell membrane/cell walls. The water will move due to the water potential of the cells. If there is a greater concentration of solutes (chemicals) inside the cell than outside the cell and the chemicals can not move‚ then water will respond by moving
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from potato starch – extracting starch In this activity you are going to extract starch from potatoes. This starch can be used to make a plastic. A similar process is used in industry to extract starch‚ which is then used in a number of products‚ including food and packaging. You will need: q q q q q q Approx 100 g clean (not muddy) potatoes Grater Tea strainer Distilled water Pestle and mortar 100 cm3 measuring cylinder. What to do q q q q q Grate about 100 g potato. The
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substances in the cells of a potato using Osmosis. I predict that the potato in the higher concentration of salt solution will lose an increasingly high amount of weight. I think this because the higher the concentration in salt‚ the more water particles will move through the potato cell’s semi-permeable membranes to try and balance the salt concentration. For example‚ if you placed a larger piece of potato into a beaker of an almost 100% salt solution; the potato would completely shrivel up because
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Effects of Tonicity on Cell Membrane Abstract The purpose of this experiment was to determine the effects of tonicity on a cell membrane using red blood cells‚ potato strips and three unknown solutions (A‚ B‚ C). First three slides were prepared containing RBC’s and unknown solutions A‚ B and C. A control slide was prepared only using RBC’s. After observing each slide under the microscope it was determined that unknown solution A was hypertonic because the RBC appeared to have shrunk. The
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this lab was to find the water potential of a potato cell. The problem of this lab was‚ if there was a high molarity of solute‚ would it have a positive or negative water potential? The hypothesis of the experiment was‚ if there is a high molarity of solute then the water potential would be lower or negative. After obtaining potatoes‚ we cut them into pieces‚ weighed them‚ and then placed them in a solution overnight. In this lab‚ we explored the potato cell’s water potentiality. From the results‚
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CONTENTS * INTRODUCTION ----------------------------------------------------------- 3 * AIMS ----------------------------------------------------------- 4 * HYPOTHESIS ----------------------------------------------------------- 5 * RESULTS ----------------------------------------------------------- 6 - Calculations - Table 6.1 - Table 6.2 - Table 6.3 - Graph 6.1 - Graph 6.2 * DISCUSSIONS ----------------------------------------------------------- 7
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B. Potato I FACTS Mr. B. Potato‚ a wealthy real estate investor‚ recently purchased a house on a parcel of land for $400‚000. The house was appraised at a value of $300‚000 and the land had an appraised value of $100‚000. Mr. Potato plans to tear down the house and replace it with a new house worth $1‚500‚000 with the intentions of living in it personally. Paying to have the house bulldozed would cost Mr. Potato a considerable amount of money. It has been suggested to Mr. Potato to permit
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Sonia St James Investigation: Factors that affect the outcome of enzyme activity Introduction In this project I will monitor the rate of activity of Catalase. Catalase is an Enzyme which in the right conditions catalyses the decomposition of Hydrogen Peroxide into water and oxygen; 2H2O2 + Catalase >>> 2H2O + O2 Catalase is found in all cells and protects them from Hydrogen Peroxide which is a dangerous waste product that needs to be eliminated. Without Catalase living things could not survive
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different concentrations of an inhibitor. The hypothesis was that hydrogen peroxide will be broken down by catalase into hydrogen and oxygen‚ where a higher concentration of inhibitor will yield less oxygen‚ resultant of a lower rate of reaction. Crushed potato samples of equal weight were placed in hydrogen peroxide solutions of various temperatures. The results showed that less gas was produced as the concentration of the inhibitor rose. This Is because more enzymes were inhibited‚ and so less active sites
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