|Subject: Surface area of a sphere | A connection which could be illustrated‚ and could be understood by students who know the perimeter of a circle‚ runs as follows: Put the sphere of radius R inside a cylinder‚ with the cylinder just touching the equator‚ and cut off at the height of the top and bottom of the sphere. (A cutaway view is in the diagram.) [pic] What is the area of the curved part of
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Mathematics Volume of Solids Formulae for Volume of Solids Cube | Cuboid | Triangular Prism | Cylinder | Cone | Pyramid | Sphere | AnyPrism | s3 | lwh | ½bhl | Πr2h | 1/3πr2h | 1/3Ah | 4/3πr3 | Ah | A = area of the base of the figure s = length of a side of the figure l = length of the figure w = width of the figure h = height of the figure π = 22/7 or 3.14 1. Compute the volume of a cube with side 7cm. Volume of cube: s3 s = 7cm s3 = (7cm x 7cm x 7cm) = 343cm3 2. Compute the
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or be found in multicellular organisms. The unicellular and multicellular organisms are linked to cell size and surface area to volume ratio. The experiment for cell size and diffusion was set to see how and how much water can go to the cells. This movement of water is called Osmosis. Osmosis is the movement of water molecules from an area of low concentration (lots of water) to an area of high concentration (little water) through a semi permeable membrane‚ demonstrated in ‘figure 1’. A semi permeable
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Performance Task in GEOMETRY * Computation of the surface area‚ amount and type of needed material and the volume of the package. Volume V= L x H x W = (23 cm) (4 cm) (12cm) = (276) (4) = 1 104 cm Area A= L x W = (23cm) (12cm) = 276cm Surface Area A= 2(Lh) + 2(Lw) + 2(Wh) / 2( lh + lw + wh) = 2(23*4) + 2(23*12) + 2(12*4) = 2(92) + 2(276) + 2(48)
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AREA (i) The area of a rhombus is equal to the area of a triangle whose base and the corresponding altitude are 24.8 cm and 16.5 cm respectively. If one of the diagonal of the rhombus is 22 cm‚ find the length of the other diagonal. (ii) The floor of a rectangular hall has a perimeter 250m. If the cost of paining the four walls at the rate of Rs 10 per m2 is Rs 1500. Find the height of the hall. (iii) A room is half as long again as it is broad. The cost of carpeting the room at Rs
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RELATIONSHIP BETWEEN SURFACE AREA AND THE VOLUME OF A CELL‚ HOW IT AFFECTS THE RATE OF DIFFUSION Nazirul Ibrahim 04.10.2011 DATA COLLECTION AND PROCESSING We have determined the following variables: * dV- the time for the color indicator phenolphthalein to reach the center of the cube (diffusion) * iV- the size of the cube * cV- the amount of Sodium Hydroxide the perfect dimensions of the cube‚ how the cube is fully submerged in the solution‚ the temperature of the cube and the constant
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the Ratio of Surface Area to Volume on Transformation Efficiency in Escherichia coli K-12 Eliana Pouchard‚ Steve Teng‚ and Cameron Wong Department of Microbiology & Immunology‚ UBC In the process of transformation‚ bact eria take up DNA fr om the environment through their cell wall. To induce competence in the cells‚ the DNA for uptake must first attach to the cell surface prio r to passing throug h the membrane. Previous studies on the effect of surface area on transformation
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find out if surface area affects reaction rate‚ and this experiment proved that surface area in fact does affect reaction rate. My experiment used a berocca tablet that was either cut into sections or left whole‚ the smaller fractions had a larger surface area as there was more area to cover‚ the pieces were then put into water to see what sized tablet reacted to the water the fastest. My hypothesis was supported as it was proven that the smaller pieces which had a larger surface area were much quicker
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The Aspire of Importing and Exporting _______________ gave this class a chance to help them figure out which floor matting will help a cargo box stop from moving. One factor that is used is friction. Friction happens when two surfaces rub against each other and may cause heat. Also there are four types of friction which are static‚ sliding‚ rolling‚ and fluid friction. The company needs the class to find out what type of flooring is best to use to stop a cargo box from moving. They have game
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Surface area / Volume ratio Experiment Introduction: The surface area to volume ratio in living organisms is very important. Nutrients and oxygen need to diffuse through the cell membrane and into the cells. Most cells are no longer than 1mm in diameter because small cells enable nutrients and oxygen to diffuse into the cell quickly and allow waste to diffuse out of the cell quickly. If the cells were any bigger than this then it would take too long for the nutrients and oxygen to diffuse into
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