College General Biology I Enzymes‚ test for effect of pH on catalase activity Purpose The main purpose of this experiment was to learn about enzymes and how to test for the effect of pH on catalase activity and to be able to tell if a reaction is an exergonic or endergonic process. Introduction Enzymes are made from amino acids‚ which are made from proteins. In order to make an enzyme‚ hundreds of amino acids are strung together in a very specific and unique order and eventually is folded
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Enzymes lower the amount of energy needed in a chemical reaction. This happens because enzymes are catalysts‚ so they speed up the activation rates that occur in living organisms. Without enzymes‚ it would be difficult to break down particles like food in the digestion system. Enzymes are all very specific to what chemical reactions they will work with‚ and the temperature‚ pH‚ and salt concentration have to be a specific levels in order for the enzyme to function. The structure of each enzyme has
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Tittle : Investigation of the Enzymatic Effects of Materials on Hydrogen Peroxide Solution Objective: To investigates the enzymatic effect of various materials in the hydrogen peroxide solution. Table 1 Test Tube Contents with 5 cm3 hydrogen peroxide Observations before and after using wood splint Observation of after Observation of after adding hydrogen using wooden glowing peroxide splinter 1 Fresh liver Moderate
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Enzyme Activity How does temperature affect enzyme activity? In this practical investigation‚ my aim is to discover how temperature will affect enzyme activity‚ by looking at the rate of reaction. I predict that the higher the temperature will be‚ the faster the reactions take place. However‚ I also think that there will be an optimum temperature‚ at which the reaction will work at its fastest; if the temperature goes beyond that‚ the reactions will stop altogether as the enzymes would have
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Enzyme Activity Over Different Concentrations and Effects The goals of this experiment were to examine the effectively of enzymes on samples of different enzyme concentrations and substrate concentrations. In addition‚ the experiment tested how effective enzymes are on samples of pH levels and temperature levels. A. Effect of Enzyme Concentration Hypothesis: With half as much enzyme concentration then the reaction rate will be half as much than when the enzyme concentration is equal
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Effect of Temperature ( C ͦ) on Enzyme Catalase Activity in potato Aim: To investigate the Effect of temperature (10‚ 37‚ 60) Celsius (C ͦ) on enzyme catalase activity in potato using 2% of hydrogen peroxide (H202) as the substrate measuring the height (cm) of oxygen gas (bubbles) and calculating the volume of oxygen bubbles produced (cm3) Introduction: Enzymes are biological catalysts that speed up metabolic reactions without being affected. They lower the activation energy needed to start
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amylase lab‚ it was being tested if amylase‚ an enzyme found in saliva‚ would be denatured by being put in an acid or high temperatures. This lab is about denaturing amylase. It is tested by exposing it to pH and temperature changes. It is then mixed with Benedict’s solution‚ is a solution that changes color from blue to reddish brown when maltose is present. Amylase breaks starch into maltose‚ so is the amylase isn’t denatured‚ it should change colors. Amylase is an enzyme. Enzymes are a type
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ABSTRACT: This lab allows us to observe the conversion of hydrogen peroxide (H2O2) into water and oxygen gas. An enzyme known as catalase facilitates this decomposition reaction. The catalase enzyme acts as catalysis‚ helping lower the energy needed to activate the reaction while the enzyme itself is not affected. Catalase is a digestive enzyme used to break down hydrogen peroxide‚ which is a normal byproduct of cellular respiration. The reaction could take place without the help of catalase‚ but
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(Justification-2 Enzyme Inhibition) By quantitative balance‚ the total amount of Enzyme is [E] 0= [E] + [EI] + [ES] + [ESI]. By using a=1+[I]/KI and a′=1+[I]/K′I‚ it is followed by [E]0=[E]a+[ES]a′ This equation can be written like this‚ [E]0=(Km[ES])/([S]0)a + [ES]a′=[ES]( aKm/[S}0+a’)‚ because of Km=[E][S]/[ES] and [S]≈[S]0. V=kb [ES] =kb [E] 0/ (aKm/[s] 0+a’). Kb [E] 0 is Vmax. This is why V=Vmax/(a^’+aKm/[S]0). This equation can be rearranged like this‚ 1/V= a’/Vmax+(aKm/Vmax)1/[S]0‚ which is
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In the first part of the lab‚ we prepared a salivary amylase solution and aggregated acetic acid to detect the presence of mucin. Then‚ 4 test tubes were made of the following: Tube 1 = 3 ml starch + water + 37 degrees water bath; Tube 2 = 3 ml starch + saliva in water bath; Tube
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