Ideally‚ the percent yield should be 100%‚ as this means that you have recovered 100% of that material. A yield over 100% would mean that the substance still has some traces of another material that is adding additional mass. Ex. The iron filings having some sand particles leftover. A yield under 100% would mean that some of the substance was not recovered‚ it could have been lost (spilled) or found in another substance (not separated completely). The percent yields may give some insight into what
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Percent Composition Report Hypothesis : By using seperation techniques properly‚ the 3 substance such as; water‚ sand‚ and salt can be seperated and the percent composition of each substance. Which will then be calculated theoritically and after comparison with the actual result‚ the accuracy of the 2 result can be found. Aim : The aim of this experiment is to compare the gravimetric result of the original mixture and the separated substance. The other objective is to calculate each percent
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Purpose: To find out the percent yield of copper in the reaction between copper sulfate (CuSO4) and Iron (Fe). Materials: Balance 100-mL beaker 250-mL beaker Bunsen burner Copper sulfate crystals Glass stirring rod 100-mL graduated cylinder Iron filings Ring stand and ring Wire gauze Procedure: 1. Record mass of clean 100-mL beaker. 2. Add 8.0 grams of copper sulfate crystals to beaker. 3. Add 50.0 milliliters of distilled water to the crystals. 4. Put wire gauze on ring on ring
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Determining the Limiting Reactant and Percent Yield in a Precipitate Reaction (SMG 6D) AP Chemistry One example of a double replacement (metathesis) reaction is the mixing of two solutions resulting in the formation of a precipitate. In solution chemistry‚ the term precipitate is used to describe a solid that forms when a positive ion (cation) and a negative ion (anion) are strongly attracted to one another. In this experiment‚ a precipitation reaction will be studied. Stoichiometry
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CunananProfessor Stewart Chemistry 400 T/TH 1:30 PM 18 March‚ 2014 Objectives: In this Experiment‚ we will be decomposing KClO3 into two different compounds‚ KCl and O2. We are given a known mixture that has MnO2 in it to act as a catalyst. When decomposing KClO3 it releases O2 gas‚ which we then collect into the Erlenmeyer flask. The gas then displaces the water into the beaker‚ which we can then calculate the water evolved. The first method we use to determine the percent composition is Gravimetric
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Yield of CuCl2.2DMSO Formula weight (Mr) of CuCl2 = 63.55 + (35.45 x 2) =134.45g/mol Formula weight of product CuCl2.2DMSO = 134.45 + 2[16 + 32.06 + (12.01 x 2) + (1.0079 x 6)] = 290.704g/mol Mass of CuCl2= 0.850g Equation for reaction CuCl2 + 2DMSO -> CuCl22DMSO Mole ratio between CuCl2 and CuCl22DMSO = 1:1 Mole of CuCl2 = Mass/ Mr = 0.850/134.45 = 0.00632 moles Since the ratio between CuCl2 and CuCl22DMSO = 1:1‚ mole of CuCl2DMSO is also 0.0063 moles. To find theoretical yield of CuCl2
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Determining the Limiting Reactant and Percent Yield in a Precipitation Reaction Objectives: Observe the reaction between solutions of sodium carbonate and calcium chloride. Determine which of the reactants is the limiting reactant and which is the excess reactant. Determine the theoretical mass of precipitate that should form. Compare the actual mass with the theoretical mass of precipitate and calculate the percent yield. Materials: Balance 0.70 M sodium carbonate solution‚ Na2CO3(aq)
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with a 12 percent coupon. Bond D is a 6 percent coupon bond currently selling at a discount. Both bonds make annual payments‚ have a YTM of 9 percent‚ and have five years to maturity. The current yield for Bonds P and D is percent and percent‚ respectively. (Do not include the percent signs (%). Round your answers to 2 decimal places. (e.g.‚ 32.16)) | If interest rates remain unchanged‚ the expected capital gains yield over the next year for Bonds P and D is percent and percent‚ respectively
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Chapter 10 Bond Prices and Yields 1. a. Catastrophe bond: Typically issued by an insurance company. They are similar to an insurance policy in that the investor receives coupons and par value‚ but takes a loss in part or all of the principal if a major insurance claim is filed against the issuer. This is provided in exchange for higher than normal coupons. b. Eurobond: They are bonds issued in the currency of one country but sold in other national markets. c. Zero-coupon bond: Zero-coupon bonds
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Alumina Yield in the Bayer Process; Past‚ Present and Prospects Edited by TMS (The Minerals‚ Metals & Materials Society)‚ 2007 ALUMINA YIELD IN THE BAYER PROCESS PAST‚ PRESENT AND PROSPECTS Roelof Den Hond1‚ Iwan Hiralal2‚ Ab Rijkeboer3 Alcor Technology‚ Clinckenburgh 10‚ 2343 JH Oegstgeest‚ The Netherlands 2 Hiracon‚ Prinses Irenelaan 2‚ 2273 DD Voorburg‚ The Netherlands 3 Rinalco‚ Helmlaan 16‚ 2244 AZ Wassenaar‚ The Netherlands 1 Keywords: hydrate‚ alumina‚ yield‚ liquor productivity
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