Assignment Q1Find the parameters of binomial distribution when mean=4 and variance=3. Q2. The output of a production process is 10% defective. What is the probability of selecting exactly two defectives in a sample of 5? Q3. It is observed that 80% of television viewers watch “Boogie-Woogie” Programme. What is the probability that at least 80% of the viewers in a random sample of five watch this Programme? Q4. The normal rate of infection of a certain disease in animals is known to
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I found the concept on frequency distribution using Google and the search words “frequency distribution” at http://www.mathsisfun.com/data/frequency-distribution.html This website is geared towards younger people and therefore breaks down frequency distribution into very basic terms: values and their frequency (how often each value occurs). The website uses the example of a child’s soccer team and how many goals they scored in recent games. For the assignment this week‚ I have chosen to use the
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Abstract This paper discusses the various distribution methods at the disposal of American Eagle Outfitters. It discusses product manufacture and how the products get from the manufacturers to the United States‚ and then to the American Eagle Outfitters stores. It discusses the best practices for distribution‚ as well as indirect vs. direct distribution. It shows the many direct and indirect ways that American Eagle Outfitters achieve this distribution model. Introduction Clothing is desired
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CHAPTER 8. TRIP DISTRIBUTION NPTEL May 3‚ 2007 Chapter 8 Trip distribution 8.1 Overview The decision to travel for a given purpose is called trip generation. These generated trips from each zone is then distributed to all other zones based on the choice of destination. This is called trip distribution which forms the second stage of travel demand modeling. There are a number of methods to distribute trips among destinations; and two such methods are growth factor model and gravity
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standard deviation = square root of variance = sqrt(846) = 29.086 4. If we have the following data 34‚ 38‚ 22‚ 21‚ 29‚ 37‚ 40‚ 41‚ 22‚ 20‚ 49‚ 47‚ 20‚ 31‚ 34‚ 66 Draw a stem and leaf. Discuss the shape of the distribution. Solution: 2 3 4 5 6 | | | | | 219200 48714 0197 6 This distribution is right skewed (positively skewed) because the “tail” extends to the right. 5. What type of relationship is shown by this scatter plot? 45 40 35 30 25 20 15 10 5 0 0 5 10 15 20 Solution: Weak positive linear
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goal of the distribution of income is to achieve economic equality‚ which is to give every citizen the opportunity of earning a decent living. However‚ our current system’s inability to better allocate the resources we have at our disposal has widened the gap between the wealthy and the poor especially during the past 20 years. The primary benefit of the distribution of income is to transfer wealth‚ with the help of the government‚ to those who are less fortunate. The current distribution of income
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Normal Distribution:- A continuous random variable X is a normal distribution with the parameters mean and variance then the probability function can be written as f(x) = - < x < ‚ - < μ < ‚ σ > 0. When σ2 = 1‚ μ = 0 is called as standard normal. Normal distribution problems and solutions – Formulas: X < μ = 0.5 – Z X > μ = 0.5 + Z X = μ = 0.5 where‚ μ = mean σ = standard deviation X = normal random variable Normal Distribution Problems and Solutions – Example
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25‚ 28 26‚ 28‚ 26‚ 28‚ 31‚ 30‚ 26‚ 26 the information is to be organized into a frequency distribution. A. How many classes would you recommend? b. What class interval would you suggest? C .what lower limit would you recommend for the first class? d. organize the information into a frequency distribution and determine the relative frequency distribution. e. comment on the shape of the distribution. 15. Molly’s Candle Shop has several retail stores in the coastal areas of North and South
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solve k = 20.275 d) P ( 17 < X < 21) P ( (17 -18)/2.5 < Z < ( 21-18)/2.5) P ( -0.4 < Z < 1.2) = 0.8849 – 0.3446 = 0.5403 ( 4 decimal places) 4. In a sample of 25 observations from a Normal Distribution with mean 98.6 and standard deviation 17.2‚ find: Ans: a) n = 25‚ [pic] = ( = 98.6‚ [pic] = /n = 17.2/(25 = 3.44 [pic]( N
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Jouni Lampinen Multiobjective Nonlinear Pareto-Optimization A Pre-Investigation Report LAPPEENRANTA 2000 1(30) Contents 1 Introduction 2 Major Information Sources 2.1 2.2 2.3 2.4 2.5 Literature surveys‚ reviews Bibliographies Thesis works Books Some significant articles 13 15 17 18 23 25 27 2 9 3. Basic Problem Statements 4. Classification for Multiobjective Optimization Approaches 5. Usage of Weighted Objective Functions 6. Pareto Optimization – Definitions 7. Evaluation of Multiobjective
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