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    oxidation of alcohol lab

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    Oxidation of an Alcohol: Oxidizing Methoxybenzyl Alcohol to Methoxybenzaldehyde Using Phase-Transfer Catalysis PURPOSE OF THE EXPERIMENT Oxidize methoxybenzyl alcohol to methoxybenzaldehyde‚ using sodium hypochlorite as the oxidizing agent and tetrabutylammonium hydrogen sulfate as the phase-transfer catalyst. Monitor the progress of the reaction by thin-layer chromatography. BACKGROUND REQUIRED You should be familiar with extraction‚ evaporation‚ and thin-layer chromatography techniques

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    Oxidation of Alcohol

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    Lab 5 Oxidation of an alcohol CHM2123 Introduction: Oxidation is a key reaction in organic chemistry. Oxidation of an alcohol can produce aldehydes‚ ketones‚ or carboxylic acids. One of the methods of oxidation is an aldol reaction through carbon-carbon bonds. The oxidation oxidizes primary alcohols to aldehydes and secondary alcohols oxidizes ketones. Tertiary alcohols are converted to the common oxidizing agents. Scheme 5.1: Aldehydes can be oxidized easily to carboxylic acids in aqueous medias

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    Bleach Oxidation of 9-Hydroxyfluorene The purpose of this experiment was to oxidize an alcohol (9-hydroxyfluorene) to a ketone (9-fluorenone) using aqueous sodium hypochlorite (bleach) as the oxidizing agent‚ while introducing techniques used in microscale experiments. Reaction: Results 1. Recrystallized Product Yield Product yield = (actual yield/theoretical yield) x 100% 3mL 9-hydroxyfluorene x (1mL/1000mL) x (0.09 mol/L) = 2.7 x 10-4 moles 0.05g 9-fluorenone / (180.20g/mol) = 2.77 x 10-4

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    ACCOUNTING MCGRAW HILL

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    CHAPTER 2 AN INTRODUCTION TO COST TERMS AND PURPOSES 2-1 A cost object is anything for which a separate measurement of costs is desired. Examples include a product‚ a service‚ a project‚ a customer‚ a brand category‚ an activity‚ and a department. 2-2 Direct costs of a cost object are related to the particular cost object and can be traced to that cost object in an economically feasible (cost-effective) way. Indirect costs of a cost object are related to the particular cost object but cannot

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    Experiment 9-Dehydration of 2-methylcyclohexanol Name______________________________________________________________________ Lab Partner_________________________________________________________________ Lab Day and Time____________________________________________________________ Report appearance (Typed‚ on time‚ in order‚ presentable‚ complete) 1 2 3 4 5 Abstract 1 2 3 4 5 Introduction 1 2 3 4

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    McGraw-Hill: Primis Custom Publishing Francesca Jackson Dr. Albert Cruz INF 620: Management of Information Systems March 25‚ 2013 McGraw-Hill: Primis Custom Publishing McGraw-Hill Education is a unit of The McGraw-Hill Companies‚ a worldwide information services provider that boasts over 350 offices in 33 nations. Headquartered in New York City‚ New York‚ its revenue topped 4.5 billion back in fiscal year 2001. In

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    Oxidation Lab Part 1: Purpose: You are going to investigate the ease with which different metals undergo oxidation and reduction. Materials: | 4 samples of each of: lead‚ zinc‚ iron‚ copper | spot plates steel wool/sand paper | | | | Solutions of: | copper(II) sulfate Ferric nitrate Silver nitrate Lead (II) nitrate | | Procedure: 1. Obtain 4 samples of each metal and clean with steel wool or sand paper. Wash your hands after cleaning the metals so you are not exposed to lead

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    3.5 Critical Analysis McGraw-Hill Ryerson Mathematics of Data Management‚ pp. 202–211 1. Edwin compares the street address numbers of three of his neighbours with the quality of their front lawn‚ which he rates on a scale of 1 to 10. He observes a positive linear correlation and concludes that people with higher street address numbers have better lawns. In Edwin’s study: a) What are the independent and dependent variables? The independent variable is the street number and the dependent

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    moles/1000 mL = .0005 moles/10 mL = moles of hydroxylammonium chloride Ratio of Fe+2 to NH3OH+ = 2:1 2e- + 2Fe+3 --> 2Fe+2 so transfer of 2 electrons NH3OH+ --> something + 2e- Oxidation number of N in NH3OH+ is -1‚ therefore the oxidation number for N on the product side must be +1 because it gains 2 electrons. N2O has an oxidation number of +1 for N‚ so that would work. Data:Equation 1: NH3OH+ + 2Fe+3 --> something + 2Fe+2 Equation 2: 8H+ + 5Fe+2 + MnO4- --> 5Fe+3 + Mn+2 + 4H2O Equation 3: 6H+ +

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    The purpose of this lab was to measure the reduction potentials of metals and to understand how a reduction-oxidation relationship works to produce spontaneity. Lastly‚ these results were used to determine the Faraday’s constant and Avogadro’s number by electrolysis‚ which is chemical decomposition produced by passing an electrical current through a solution with ions. The primary objective of part one of this experiment was to discover how the properties of an electrochemical cell works. An electrochemical

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