"Nucleophile" Essays and Research Papers

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    t-Pentyl Chloride is a compound that is created through an SN1 nucleophilic substitution reaction in addition with Hydrogen Chloride in order to isolate the product. A variety of procedural techniques were utilized during the experiment including extraction‚ washing liquids‚ drying liquids‚ gravity filtration‚ and simple distillation. When a single solute or compound is transferred between two different solutes‚ it is known as extraction. Another technique that was utilized was washing‚ in which

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    Preparation of Azo Dyes

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    UNIVERSITY OF SAN CARLOS DEPARTMENT OF CHEMISTRY NAME: Maniwang‚ Ma. Aiza C. DATE: March 21‚ 2011 COURSE: BS Chemistry II APPROVED: ___________ PREPARATION OF AZO DYES ABSTRACT In this experiment‚ the azo dyes p-nitrobenzene azoresorcinol and methyl orange were prepared by the azo coupling reaction. The p-nitrobenzene azoresorcinol dye was prepared from p-nitroaniline and resorcinol. The diazonium salt formed was from the reaction of the cold solution of dissolved p-nitroaniline

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    Test 4, Ch 9,10,11

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    CHM 2210 – Fall 2012 – Test 4 Name (print):_________________________ 1. What is the IUPAC name for the following compound? a) b) c) d) 3-methyl-1-penten-4-yne 3-methyl-1-buten-4-yne 4-methyl-4-penten-1-yne 4-methyl-4-buten-1-yne 2. What is the major organic product obtained from the following reaction? 2 equiv Br2 a) b) c) d) 2‚3-dibromobutane 2‚2‚3‚3-tetrabromobutane 2‚3-dibromobutene 2‚2-dibromobutane 3. What is the best choice of reagent(s) to perform the following transformation

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    Acetic

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    anhydride was used to prepare acetanilide which could then be readily brominated to form a mono-brominated product‚ with the bromine positioned at either the ortho‚ meta or para position on the aromatic ring. Acetic anhydride is very reactive towards nucleophiles and this reactivity is the result of the difference in electronegativities of the carbon and oxygen atoms that are bonded in acetic anhydride. This difference in electronegativities causes one of the carbonyl groups in acetic anhydride to break

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    of aldehydes to primary alcohols. Borohydride‚ and Lithuim aluminum hydride are commonly used as reducing agents. We can note that both of these reagents have a (H-) anion‚ hence it will be a powerful base and also take the role of being the nucleophile. For the experiment sodium borohydride was used since its properties make it easier to be handled. In this experiment both the trans and the cis isomers of the 2-methylcyclohexanone were to be formed. This is due to the chiralty of the compound

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    the reaction to occur and to better control the stereochemistry and yield of the product‚ the metal hydride nucleophile of the reducing agents such as LiH‚ LiAlH4‚ or NaBH4 must be carefully chosen. Being that LiAlH4 and NaBH4 will not react with isolated carbon-carbon double bonds nor the double bonds from aromatic rings; the chosen compound can be reduce selectively when the nucleophile only react with electrophilic carbons. Figure 1: reduction mechanism for the reaction In this experiment

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    basic concepts questions

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    1. Predict the molecular formula of an alkane with 13 carbon atoms. .................................................................................................................................. [Total 1 mark] 2. Bromobutane‚ CH3CH2CH2CH2Br‚ can be reacted with hot aqueous sodium hydroxide to prepare butan-1-ol. CH3CH2CH2CH2Br + OH– → CH3CH2CH2CH2OH + Br– A student reacted 8.72 g of bromobutane with an excess of OH–. The student produced 4.28 g of butan-1-ol. (i) Calculate the amount

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    Sulfuric Acid | | | | | | | Compound/Product | | | | | | | 1- bromobutane | | | | | | | | | | | | | | Discussion: SN2 reactions are substitution reactions that involve the exchanging of a group(s) in a molecule. Nucleophiles are electron donors and want to give them away to electron acceptors. If the leaving group is a bad leaving group. In this experiment‚ I had foam in my flask from the microscale kit that could of caused an error in my desired product. The test

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    carbocation and water. In order to form the double bond‚ one of the beta hydrogens‚ hydrogens on a carbon adjacent to the carbocation‚ must be removed or eliminated. Therefore‚ another name for a dehydration reaction is beta elimination. Water acts as a nucleophile and attacks the carbocation‚ removing a beta hydrogen; the electrons from the C-H bond move to make a C-C pi-bond. The general mechanism is displayed by equation (1.0)Equation (1.0) shows a reaction with a primary alcohol. Usually primary alcohols

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    Lewis Acids and Bases

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    as acid and base interactions‚ derives from acceptance of the Lewis definition of acids and bases‚ which alternated the earlier Brønsted-Lowry concept. According to Lewis definition‚ acids (electrophiles) are electron pair acceptors and bases (nucleophiles) are electron pair donors. AlCl3 + (CH3)3N ↔Al-Cl3N+(CH3)3In the above example‚ AlCl3 is Lewis acid because it have unoccupied valence orbital and can receive electron pairs from (CH3)3N‚ which is Lewis base. In a Lewis base‚ nitrogen donates

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