insoluble solid. 3. Decantation. This separates a liquid from an insoluble solid by carefully pouring the liquid from the solid without disturbing the solid. 4. Filtration. This separates a solid from a liquid through the use of a porous material as a filter. Paper is a good filter. Filters allow the liquid to‚ pass through but not the solid. 5. Evaporation. This is the process of heating a mixture in order to drive off a volatile liquid and make the remaining component dry. The mixture
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(milk) and gas (food coloring) in the respiratory system. Because I know milk is non-polar and food coloring is polar‚ my hypothesis predicts the two will not mix voluntarily at first‚ but the soap acting as a surfactant‚ when added‚ will help the two liquids mix together. Materials (Part on: water surface tension) 1- A penny 2- A dropper 3- Water 4- Paper towels (Part two: surfactant) 1- Milk 2- 2 different color food coloring 3- Dishwashing soap 4- Cotton swab 5- A mall clear dish 6- Timer 7-
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LET’S START WITH COPPER CHEMISTRY REPORT 2012 INTRODUCTION: The law of conservation of mass means that the atoms of an object cannot be created or destroyed‚ but can be moved around and be changed into different particles. This law says that when a chemical reaction makes two different atoms into a new product‚ the mass will be the same. Knowing this the mass of the copper should be the same at the beginning and at the end of the experiment. In this investigation we will see
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many peritectics? ______ How many peritectoids? ______ How many pure metal phase transitions? ______ How many congruent melting points??______ Q.2 a) A 90 wt% Ag-10 wt% Cu alloy is heated to a temperature within the b + liquid phase region. If the Composition of the liquid phase is 85 wt% Ag‚ determine: (a) The temperature of the alloy (b) The composition of the b phase (c) The mass fractions of both phases b) For a copper-silver alloy of composition 25 wt% Ag-75 wt% Cu and at 775°C (1425°F)
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able to: Define Fluid State differences between solid and fluid Calculate common fluid properties: i. Mass density ii. Specific weight iii. Relative density iv. Dynamic viscosity v. Kinematic viscosity INTRODUCTION Fluid Mechanics Gas Liquids Statics i F 0 F 0 i Laminar/ Turbulent Dynamics ‚ Flows Compressible/ Incompressible Air‚ He‚ Ar‚ N2‚ etc. Water‚ Oils‚ Alcohols‚ etc. Stability Pressure Buoyancy Surface Tension Compressibility Density Viscosity Vapor
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INTRODUCTION. SOLIDS‚ LIQUIDS AND GASES have properties that are use to describe how they behave‚ e.g. for solids it has a definite shape‚ you can hold a solid rock in your hand. You can push on a solid brick wall. Scientists say a solid is something that has shape. A solid resists any change in its shape. TASKS 2. LOOK AT THE PICTURES BELOW FOR SOLID‚ LIQUID AND GAS AND WRITE DOWN THREE PROPERTIES OF EACH? Wood as a Solid. Solid has a fixed shape Its particles are tightly held together
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MID REVIEW ON EXPERIMENTAL AND NUMERICAL INVESTIGATION OF GAS LIQUID FLOW IN TWO PHASE SYSTEM FACULTY MENTOR:- Dr.Pravin kodgire ‚HOD Chemical engg Dept‚PDPU By Siddhartha jain B.Tech chemical engineering PDPU MULTIPHASE FLOW DEF:- Interacting flow of two or more phases‚ where the interface between the phases is influenced by their motion.examples being gas-liquid flows in evaporators and condensers‚ gas-liquid-solid flows in chemical reactors‚ solid-gas flows in pneumatic conveying
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covalent bonds have lower melting and boiling points. 1. Do ionic compounds conduct electricity as: (3 points ) A. Solids? No B. Liquids? No C. Aqueous solutions (when the ionic compounds are dissolved in water)? Yes 2. Do covalent compounds conduct electricity as: (3 points ) A. Solids? B. Liquids? C. Aqueous solutions (when the covalent compounds are dissolved in water)? 03.06 Covalent Bonding and Lewis Structures: Lab and Rubric Part
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(given by client) / (by process cal.) Molecular weight of comp. = 36.5 Liquid / Scrubbing media Properties Scrubbing media = 20% NaOH Liquid flow rate‚ L = 77 kg/h = 0.0214 kg/s Liquid Density‚ L = 1100 kg/m3 Conversion : Liquid Viscosity‚ µL = 0.0035000 Ns/m2 3.5 Cp = 0.00350000 Ns/m2 Packing factor
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Marriott Corporation Evaluating the cost of capital 1. What is the weighted average cost of capital for Marriott Corporation? 1 (a) What risk-free rate and risk premium did you use to calculate the cost of equity? R (f)‚ or risk free rate used for calculating cost of equity was the Geometric Mean (GM) for LT US govt. bond returns (Exhibit 4). We used the overall GM of 1926-1987 of 4.27%. This is because this is the period that Marriott has been in operation and would be a good reflection
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