"Lcm and hcf" Essays and Research Papers

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    ijh{kk mŸkh.kZ gksus ij viuh NksVh cgu dks c/kkbZ i= fy[ksaA MATHS Use Euclid`s divison algorithm to find the HCF of each of the following pairs of numbers: (i) 105‚375 (ii) 819‚27 (iii) 885‚1990 1. 2. 3. 5. 5. 6. 7. 8. 9. 10. 11. 12. 13. 14. 15. 16. 17. 18. 19. 20. 21. 22. 23. (iv) 330‚121 (v) 140‚368 (vi) 1290‚228 Use Euclid`s division algorithm ti find the HCF of

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    Euclidean algorithm

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    Euclidean algorithm In mathematics‚ the Euclidean algorithm‚ or Euclid’s algorithm‚ is a method for computing the greatest common divisor (GCD) of two (usually positive) integers‚ also known as the greatest common factor (GCF) or highest common factor (HCF). It is named after the Greek mathematician Euclid‚ who described it in Books VII and X of his Elements. The GCD of two positive integers is the largest integer that divides both of them without leaving a remainder (the GCD of two integers in general

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    Integer and Polynomial X2

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    natural number cannot end with the digit 0 or 5. Prove that each of the following are irrational : 1 a] 7 − 3 2 b] c) 3 + 5 5 +2 Use Euclid’s division algorithm‚ to find the HCF of a] 455 & 42 b] 392 & 267540 Express each of the following as a non-terminating recurring decimal a] 1/7 b] 13/44 c] 1/15 d] 1/370 Find the HCF and LCM of 30‚72 and 432 by using the fundamental theorem of arithmetic. Show that one and only one out of p‚ p + 4‚ p + 8‚p +12 and p + 16 is divisible by 5‚ where p is any positive

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    ACTUAL PARAMETER | FORMAL PARAMETER | A) | PARAMETER THAT APPEARS IN FUNCTION CALL STATEMENT IS KNOWN AS ACTUAL PARAMETERExp. int y = ob.sum (m‚ n); | A) | PARAMETER THAT APPEAR IN FUNCTION DEFINATION IS KNOWN AS FORMAL PARAMETERSExp. void sum(int a‚ int b) | B) | THIS IS USED TO PASS VALUE | B) | THIS IS USED TO RECEIVE VALUE | | | | | WHILE | DO WHILE | A) | WHILE LOOP WILL NOT EXECUTE AT ALL IF THE CONDITION IS NOT SATISFIED | A) | BUT DO WHILE CONTINUE ATLEAST ONCE | B) |

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    engineering mathematic

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    0‚1‚ 2‚ 3‚... zero 0 or that is 2‚ 4‚ 6‚8‚10‚... 2 Engineering Mathematics 1 (AQB10102) Odd Numbers – any number that is not divisible by 2 Composite Numbers – natural numbers but not a prime number LOWEST COMMON MULTIPLY (LCM) 1‚ 3‚ 5‚ 7‚ 9‚...

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    MATHS-SA1-TEST1 Q1) Use the following information to answer the next question. The steps for finding the H.C.F. of 2940 and 12348 by Euclid’s division lemma are as follows. 12348 = a × 4 + b a = b × 5 + 0 What are the respective values of a and b? A. 2352 and 588 B. 2940 and 588 C. 2352 and 468 D. 2940 and 468 Answer The steps to find the H.C.F. of 12348 and 2940 are as follows. 12348 = 2940 × 4 + 588 2940 = 588 × 5 + 0 Comparing with the given steps‚ we obtain a =

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    General Knowledge

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    minutes.There are 3 sections: 20 questions in section I‚ 20 in section II and 10 in section III. Section – I : Logical Reasoning‚ Section – II : Mathematical Reasoning & Section – III : Everyday Mathematics SYLLABUS Roman numerals‚ Number sense‚ HCF and LCM‚ Addition and subtraction‚ Multiplication and division‚ Fractional numbers‚ Decimal fractions‚ Geometrical shapes‚ Angles‚ Arithmetical ability‚ Area and perimeter of rectangle‚ square‚ circle‚ triangle‚ Volume‚ Pictorial representation of data

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    Maths Answers Class 10 Ncert

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    51 2. An integer can be of the form 6q‚ 6q + 1‚ 6q + 2‚ 6q + 3‚ 6q + 4 or 6q + 5. EXERCISE 1.2 1. 2. 3. (i) 2 × 5 × 7 (iv) 5 × 7 × 11 × 13 (i) LCM = 182; HCF = 13 (i) LCM = 420; HCF = 3 2 (ii) 22 × 3 × 13 (v) 17 × 19 × 23 (ii) LCM = 23460; HCF = 2 (ii) LCM = 1139; HCF = 1 7. 36 minutes (iii) 32 × 52 × 17 (iii) LCM = 3024; HCF = 6 (iii) LCM = 1800; HCF = 1 4. 22338 EXERCISE 1.4 1. (i) Terminating (iii) Non-terminating repeating (v) Non-terminating repeating (vii) Non-terminating repeating (ix)

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    CLASS VII CBSE-i Introduction to Rational Numbers nt’s Section Stude Shiksha Kendra‚ 2‚ Community Centre‚ Preet Vihar‚Delhi-110 092 India UNIT-3 CLASS VII UNIT-3 CBSE-i Mathematics Introduction to Rational Numbers Shiksha Kendra‚ 2‚ Community Centre‚ Preet Vihar‚Delhi-110 092 India The CBSE-International is grateful for permission to reproduce and/or translate copyright material used in this publication. The acknowledgements have been included

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    English

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    COMBINED CIVIL SERVICES - II General Studies Preliminary Examination (for Group – II (CSSE -I) Services) 200 ITEMS - 300 MARKS Unit-I General science : Physics-Universe-General Scientific laws-Scientific instruments-Inventions and discoveriesNational scientific laboratories-Science glossary-Mechanics and properties of matter-Physical quantities‚ standards and units-Force‚ motion and energy-electricity and Magnetism -Heat‚ light and sound-Atomic and nuclear physics. Chemistry-Elements and Compounds-Acids

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