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    the height of the track to the cart’s acceleration? The data shows that sinӨ‚ which is dependent on the height‚ is getting higher as acceleration is increasing. This implicates that when object is at higher altitude‚ its acceleration is faster. 2. From the data obtained‚ how is time‚ t related to the inclination of the track? Explain why? Time and position of velocity are interrelated to each other and the height and gravitational pull affects the acceleration of a moving and a free falling object

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    2d Motion Lab

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    Go to http://phet.colorado.edu/simulations/sims.php?sim=Motion_in_2D and click on Run Now. 1) Once the simulation opens‚ click on ‘Show Both’ for Velocity and Acceleration at the top of the page. Now click and drag the red ball around the screen. Make 3 observations about the blue and green arrows (also called vectors) as you drag the ball around. The vectors appear to have both direct and inverse relationships with each other. When I move the ball one direction‚ both of the vectors move the

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    Cart on a Ramp

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    Objectives: To learn about motion through studying and matching graphs of position vs. time and velocity vs. time; to develop an understanding of the concepts of kinematics. Predict‚ sketch‚ and test motion graphs to better understand motion. Equipment: Computer Vernier computer interface Logger Pro Vernier Motion Detector Meter stick Masking tape Preliminary Questions: 1a. The pink line shows the position of an object at rest with respect to

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    Physics Formula

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    | |Average Speed |Vavg |Vavg = (total distance | | | |traveled)/(total elapsed time) | |Acceleration |a |a = DV/Dt  =   (V2 - V1) / (t2 - t1) | |Final Speed |V2 |V2 = V1 + aDt | | Original Speed

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    cheese making

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    velocity and acceleration of four moving objects at a given instant in time are given in the following table. Determine the final speed of each of the objects‚ assuming that the time elapsed since t = 0 s is 2.0 s.   Initial velocity v0 Acceleration a (a) +12 m/s +3.0 m/s2 (b) +12 m/s -3.0 m/s2 (c) -12 m/s +3.0 m/s2 (d) -12 m/s -3.0 m/s2   29.   A jogger accelerates from rest to 3.0 m/s in 2.0 s. A car accelerates from 38.0 to 41.0 m/s also in 2.0 s. (a)   Find the acceleration (magnitude

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    Scalar and Vectors

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    vector or scalar quantities. Of particular interest‚ the forces‚ which operate on a flying aircraft‚ the weight‚ thrust‚ and aerodynamic forces‚ are all vector quantities. The resulting motion of the aircraft in terms of displacement‚ velocity‚ and acceleration are also vector quantities. These quantities can be determined by application of Newton’s laws for vectors. The scalar quantities include most of the thermodynamic state variables involved with the propulsion system‚ such as the density‚ pressure

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    velocity has the constant value vx = C; that is‚ x = Ct i. On the diagram above‚ indicate the directions of the particle’s velocity vector v and acceleration vector a at point R‚ and label each vector. ii. Determine the y-component of the particle’s velocity as a function of x. iii. Determine the y-component of the particle’s acceleration. b. Suppose‚ instead‚ that the particle moves along the same parabola with a velocity whose x-component is given by vx = C/(1+x²)½ i. Show

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    Newtons Second Law

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    JAFARUDIN REG. NO: 16DKM12F2016 LECTURER’S NAME: MISS DINA IZZATI BT HASHIM TITLE: NUMERICAL VERIFICATION OF NEWTON’S SECOND LAW OF MOTION OBJECTIVES: 1. To numerically examine the relationship between force‚ mass and acceleration. 2. To find the acceleration of the cart in the simulator. 3. To find the distance covered by the cart in the simulator in the given time interval. EQUIPMENT: 1. Newton’s Second Law of Motion Virtual Lab simulator. 2. Computer Figure 1.1:

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    Physics Circular Motion

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    5. acceleration – change in speed over time (vector quantity) TWO types; a. Linear acceleration – speed up or slow down b. Centripetal acceleration – change direction B. Centripetal acceleration (ac) – acceleration changes due to change in direction. 1. Centripetal means center seeking 2. ac is always directed toward the center of the curved path (circle) 3. If an object is moving in a circle it will always have a centripetal acceleration 4. ac

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    Hgjftjfykyk

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    Ɵ = 83.72 or Ɵ = 84° | 3. A car starting from rest‚ accelerates for 15.0 min until it’s velocity is 20 m/s. It then moves at constant velocity for another 20.0 min before it slow down and finally stopped in another 10.0 min. Find (a) acceleration during the first 15 min‚ (b) the deceleration during the last 10 min of its motion‚ (c) the distance traveled during the last minute‚ and the (d) total displacement. (e) Draw the displacement versus time graph and velocity versus time graph for

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