Microbiology-2460 Lab-003 March 31‚2008 Lab Report-Escherichia coli Abstract The purpose for this lab report was to identify and inform of an unknown bacteria that has been causing a patient to have lower abdominal and pelvic pain. To obtain the identification of this unknown bacterium‚ several biochemical tests needed to be performed in order to prescribe the correct medication to treat and cure the symptoms. Introduction In a lab today‚ I am to identify an unknown bacterium that is
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January 1999 B io Factsheet Example glucose fructose galactose Number 39 Carbohydrates: Revision Summary Carbohydrates contain 3 elements: Carbon (C)‚ Hydrogen (H) and Oxygen (O). Thus‚ if we remove water from carbohydrates‚ all that remains is carbon. Carbohydrates can be divided into 3 categories; monosaccharides‚ disaccharides and polysaccharides (Table 1). Table 1. Structure of monosaccharides‚ disaccharides and polysaccharides Category Monosaccharide (made of 1 sugar molecule)
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Aaron Santos Ralph Reyes LBYMATB V26B Report Title Of Activity: Yogurt Making Date Performed: October 4‚ 2012 I. Introduction Last October 4‚ the group performed an activity that involved making our own yogurt. The group prepared the materials and followed the procedures to make the said yogurt. In the activity paper that was given‚ it dictated that during the yogurt making process‚ the bacteria underwent fermentation. “Fermentation is any process where microorganisms use an external
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The structural features of carbohydrates account for the fact that a wide variety of polysaccharides exist is pentoses and hexoses. The examples of pentose are ribose‚ deoxyribose‚ ribulose and xylulose. The examples of hexose are glucose which is found in fruits‚ fructose which is found in milk and galactose which is found in honey. Both pentoses and hexoses are mostly found in monosaccharides. They are the most simplest sugar which cannot be futher hydrolysed into smaller units. They contain
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removed a tissue sample for examination and referred the patient to a gastroenterologist for a barium xray and colonoscopy. While utilizing the methods stated above‚ the bacterium found was a facultative anaerobe due to the Gram Negative Rods‚ fermentation‚ and the production of indole. The specific Gram Negative Enteric Bacilli was Shigella dysenteriae. There are many reasons for knowing how to control bacterial growth as well as such as antimicrobial drugs‚ which assist the body’s defenses against
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Undergraduate Questions (50 Pts) 1. (4 pts) A chemist working in a pharmaceutical lab synthesized a new drug as a racemic mixture. Why is it important that she separates the two enantiomers and test each for its biological activity? 2. (6 pts) Phosphoric acid (H3PO4) has three dissociable protons‚ with the pKa’s shown below. Which form of phosphoric acid predominates in a solution at pH 4? Explain your answer. Acid pKa H3PO4 2.14
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How Carboxylic Acids and Alcohols React to Produce Esters: Esters and Ester Production: Esters are abundant and ever present‚ and are the chemical basis of almost all fatty acids and oils. Small esters are responsible for the aroma of fruits‚ perfumes and‚ by extension‚ wines and other alcohols. Esters are formed when a carboxylic acid and an alcohol chemically combine‚ losing a molecule of water in the process. Carboxylic acids are organic molecular compounds that form a homologous series
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cheese. Lactic acid bacteria(LAB)‚ a bacteria that can be found in the production of cheese‚ its stress gene was investigated in the experiment by using various biochemical and genetic techniques to identify and extract. The characterisation of the strain illustrates how identification of strains differ using different methods‚ such as gram stain and 16s rRNA screening. After the characterisation‚ the stress gene isolation assist the further understanding of the gene on LAB be giving different stress
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Student’s Name Date of Experiment- 11/27/12 Date Report Submitted 11/27/12 Title: Caloric Content of Food Purpose: to be able to measure the energy content of foods Procedure: We are going to take food items and burn them to heat water to be able to determine the amount of “energy” a food source can emit. Data Tables: |Data Table 1: Food Item - Observations
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- Always starts anaerobic in the cytosol – glycolysis – only 2 ATP saved - By the end of the process‚ you get 2 pyruvate – 3-carbon molecules NO O2 - Fermentation 1. Lactic Acid – your muscles ache because of the accumulation of lactic acid. 2. Alcohol Fermentation- ethanol is fancy word for alcohol. Alcohol fermentation is alcohol + CO2 O2 Aerobic * Respiration * Mitochondria * Matrix – Krebs Cycle – C6 – gives you 2 more ATP * Innermembrane- ETS – 34 ATP Mitochondria
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