"Lab 1 determination of the empirical formula of silver oxide" Essays and Research Papers

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    Chemistry Practical Report: Topic: Determining the Empirical Formula of Magnesium Oxide Patrick Doan 11 CHEM 11 26/9/08 Table of contents 1.0 Aim 1 2.0 Theory 2-3 3.0 Materials 4 4.0 Method 4 5.0 Results 4 - 5.1 Qualitative Observations 4 - 5.2 Example Calculations for each Calculated Value 5-7 -5.21 Experimental Values and Associated Errors 5-7 - 5.3 Accumulated Raw Data 8 - 5.4 Mean Experimental

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    Laboratory 3. Empirical Formula Of An Oxide This experiment will demonstrate the law of conservation of mass‚ and more specifically‚ how the law can be used to experimentally determine the empirical formula of our intended product‚ magnesium oxide. In this experiment we will learn how to: 1. heat a sample in a crucible with a Bunsen burner. 2. use the method of weight by difference to determine mass quantities. 3. convert grams to moles. 4. determine the simplest ratio between two

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    Steven Leung 9/19/06 Lab Report The Empirical Formula of a Copper Oxide Purpose: To convert an unknown copper oxide to copper (Cu) metal using natural gas to provide a reducing environment as shown below: Cu O (s) + CH (g) ¨ Cu (s) + Co (g) + H O (g) From the mass difference between the unknown copper oxide and the Cu metal generated at the completion of the reaction and the molar mass of Cu and oxygen‚ the empirical formula of the original copper oxide can be calculated. Materials:

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    Experimental Determination of the Formula of Magnesium Oxide. Introduction: Magnesium is a mental‚ it is known to react with oxygen. Magnesium reacts vigorously when heated in the presence of air‚ which is why we have chosen high heat in our method to facilitate combustion. This oxidation reaction produces magnesium oxide gaining oxygen from the air. When sharing of electrons occur a chemical bond is made and the atoms combine to form a molecule. So‚ the predicted molecular formula:

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    Empirical Formula

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    Empirical Formula Lab Class: Chemistry 1405 Fall 2013 Aim: The aim of this Lab Exercise is to use the mass of a chemical and use that mass to find the amount of moles of the final product you can get using the empirical formula. Introduction: The empirical formula of a compound is the simplest whole-number ratio of the elements in the compound‚ which as you will discover‚ is a ratio of the moles of those elements. “Empirical” also means “experimentally determined”. In this experiment

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    Name: J.T Empirical Formula of Magnesium Oxide: Lab Report The objective of the experiment is to determine the empirical formula of Magnesium Oxide through a procedure of heating magnesium ribbon to react with oxygen to form a magnesium oxide compound with the correct ratio of atoms within each element; 1:1. Equipment: REFER TO EXPERIMENT SHEET Method: REFER TO EXPERIMENT SHEET Results: Object | Mass (g) | Crucible + Lid | 38.23 | Crucible + Lid + Magnesium | 38.57 | Crucible

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    Empirical Formula

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    Chemistry pre- IB Empirical Formula Observations/Qualitative Data: I have used my sense to observe that the magnesium is a solid that is bendable‚ is very light and its color is silver. After being put in a Crucible covered by a lid‚ under a Bunsen burner for a few minutes‚ it has lit up and turned red. After the experiment was over‚ the magnesium was turned into an ash/powdery state and its color became white/grey. Data collection and Processing (DCP): Quantitative Data: Weight in grams

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    Empirical Formula PRE LAB

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    Sean Dowling  Julia Phaltankar  Mrs. Oakes  Chemistry w/ Algebra 10/G  February 18‚ 2015  Determining Empirical Formula Lab   Introduction:   One can find an empirical formula by taking a sample of a compound and dividing the  number of moles of one element in the compound by the number of moles of another element in  the compound to form a small whole­number formula. For example‚ in a sample of a made up  compound of oxygen and lead‚ one mole of lead has a molar mass of 207.2 g/mole‚ and oxygen 

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    The Empirical Formula of Magnesium Oxide. Focus Question – Can the mass of magnesium combusted in excess oxygen be used to determine the empirical formula of magnesium oxide? Hypothesis – Combustion of Magnesium will generate data which can be used to calculate the EF of Magnesium Oxide Experimental Report: Data Collection and Processing Qualitative Observations: * The Magnesium burnt with a very bright flame. (as seen in figure 2 below) * White smoke was formed and some

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    is important to determine the percentage composition of elements to work out the empirical formula. The empirical formula was found to be C10H12O and the mass of the unknown was 148.09 m/z which when calculating the molecular weight of the empirical formula it did equal 148.09 g mol -1. This means that the empirical formula is also the molecular formula. As 12.01x10 carbons +1.008x12 hydrogens + 16= 148.09 09 g mol -1. From this knowledge the unknown molecule must include either an alcohol‚ aldehyde

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