Name: Keziah V. Cuyom Section: 9 - Malaya Topic: Types of Chemical Reaction A chemical reaction is a process that is usually characterized by a chemical change in which the starting materials (reactants) are different from the products. Chemical reactions tend to involve the motion of electrons‚ leading to the formation and breaking of chemical bonds. There are several different types of chemical reactions and more than one way of classifying them. Here are some common reaction types. However‚ if
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name of this reaction is called the Perkin’s reaction. The reaction was first used by William Perkin to create phenylcinnamic acids (Johnson). It is very similar to the aldol condensation which is followed by elimination. In this reaction E and Z isomers of phenylcinnamic acid are created using benzaldehyde and acetic anhydride. The intermediate product is acetic phenyl acetic anhydride. Benzaldehyde is an aromatic compound that Results: The reaction involves the use of benzaldehyde with acetic
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Sheet Names:______________________________ 6. Section 1 (Introduction to Isomers) 7. 8. Does the cis isomer have an optical isomer? _No________ 9. 10. Does the trans isomer have an optical isomer? ____No_____ 11. 12. Isomers of Pt(H2O)2Br2Cl2 (on back of this page) 13. 14. Section 2 (Complex Ions) | Coordination Number | Number or Isomers | [Cr(H2O)6]3+ | 6 | | [Ni(CN)4]2- | 4 | | [Cr(H2O)4Cl2]+ | 6 | | [Co(en)2(H2O)CN]2+
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of the product to determine whether the alcohol exhibited the Evelyn Effect. The reaction taking place for both the Cis and the Trans isomers for Methylcyclohexanol are as follows: E1 Mechanism for Cis Methylcyclohexanol E1 Mechanism for Trans methylcyclohexanol
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(Mr = 215.8) contains 22.24% carbon‚ 3.71% hydrogen and 74.05% bromine by mass. Show that the molecular formula of A is C4H8Br2. (3) (b) There are nine structural isomers of molecular formula C4H8Br2‚ three of which have branched carbon chains. Give the names and draw the displayed formulae for any two of the branched chain isomers of C4H8Br2. (4) (Total 8 marks) 4. The table below shows the fractions obtained from crude oil. Name of fraction Number of carbon atoms Use Gases 1-4 bottled
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our oxidation was successful. In the second week of this lab we will use sodium borohydride to reduce (Mechanism: Figure 7) the 4-tert-butylcyclohexanone created the previous week into the cis-4-tert-butylcyclohexanol isomer (Figure 4)‚ the trans-4-tert-butylcyclohexanol isomer (Figure 5)‚ or a racemic mixture of Tarnas 2 the two. We will then compare the isomeric composition of the product we yielded in week 2 to commercial 4-tert-butylcyclohexanol via NMR. Figure 1. 4-tert-butylcyclohexanone
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The aim of our investigation is to find out whether the use of different sugar isomers with yeast‚ will affect the rate at which the yeast respires at. The sugars to be tested are fructose‚ galactose‚ glucose‚ lactose and sucrose. Their effects on the respiration rate of yeast to be observed through the measurement (cm3) of the displaced water‚ which will tell us how much CO2 has been respired over 2 minutes. To compare the effects an average will be calculated for each and a result will be drawn
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be chlorinated with the combination of sulfuryl chloride and ABCN as an initiator to produce the chlorine radicals. The combination of 1-chlorobutane and sulfur chloride will produce four dichlorobutane isomers. The isomers produced and their reactivity will be analyzed by the amounts of isomers produced in the product and by gas chromatography. Procedure: 1) Assemble the apparatus in the hood using a Thermowell Heater 2) Use a 25-mL round bottom flask fitted with a reflux condenser
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butane Butane‚ C4H10 is an alkane with four carbon atoms which are bonded to each other by single bonds. Butane can form two isomers which are n-butane and isobutane. Figure1.1(a) and 1.1(b) shows the structures of n-butane and isobutane. Alkanes usually show conformational isomerism due the presence of C-C single bonds. It is important to understand that conformational isomer can only occur in compound with single bond but not double or triple bond. This is because only single bond allows free rotation
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ALKENES EXERCISES 1. Draw the one constitutional isomer that is missing from column 1 of Model 1. (2 points) 2. Draw ten skeletal representations constitutional isomers missing from column 2 in Model 1 as you can. (Hint: Other than cyclohexane‚ there are 11 ways to draw a six-carbon backbone that contains a ring. Plus there are isomers of cyclohexane that do not contain a ring.) (10 points) 3. Are any constitutional isomers missing from Column 3 in Model 1? A good way to answer
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