REACTION PAPER It is said that effective teacher will use both assessment and evaluation regularly to improve student learning and to guide instruction. Indeed‚ both have pivotal roles in the teaching-learning process yet‚ somehow they do differ in many ways. Assessment and evaluation measure whether or not learning and/or learning objectives are being met. One could look at assessment and evaluation as the journey (assessment) versus the snapshot (evaluation). (Sue Watson‚ 2009) Assessment requires
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Laboratory 9 Lab title: Conductivity of solutions and Household Items PURPOSE: To understand the compounds that dissociate (break into ions) when dissolved in water. Determine ionic compounds are electrolytes. To identify solutions as electrolytic and non-electrolytic‚ and to identify variations in conductivity among electrolytes. Substances that are capable of conducting an electric current in solution are known as electrolytes. Substances that do not conduct an electric current
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cheese. Lactic acid bacteria(LAB)‚ a bacteria that can be found in the production of cheese‚ its stress gene was investigated in the experiment by using various biochemical and genetic techniques to identify and extract. The characterisation of the strain illustrates how identification of strains differ using different methods‚ such as gram stain and 16s rRNA screening. After the characterisation‚ the stress gene isolation assist the further understanding of the gene on LAB be giving different stress
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AP Chem Exam - ‘98 1. Solve the following problem related to the solubility equilibria of some metal hydroxides in aqueous solution. (a) The solubility of Cu(OH)2(s) is 1.72 x10–6 g/100. mL of solution at 25° C. (i) Write the balanced chemical equation for the dissociation of Cu(OH)2(s) in aqueous solution. Cu(OH)2 Cu 2+ + 2 OH – (ii) Calculate the solubility (in mol/L) of Cu(OH)2 at 25 °C. (1.72 x10–6 g/0.100 L)(1 mol/97.5 g) = 1.76 x10–7 mol/L (iii) Calculate
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Toxicology Lab 1. In this investigation‚ a wide range of concentrations of Sodium Chloride (NaCl) solution were created and the effects that they had on radish seeds were tested. This ultimately created a doseresponse experiment in which it was detectable whether or not radish seeds were a reliable bioassay for the toxicity of NaCl. The goal of this experiment was to determine a correlation between toxicity and seed germination/radicle
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Observations | Reaction Type | Complete and Balance | 1. When heated in oxygen‚ magnesium gives off a bright white flame. | combination reaction | 2Mg + O2-----> 2MgO | 2. Bubbling and fizzing occurs; the zinc appears to “dissolve” and what appears to be “steam” comes off out of container. | single-displacement reaction | Zn + 2 HCl (aq) --> ZnCl2(aq) + H2(g) | 3. Black smoke occurs | decomposition reactions | 2 (H2O2)(aq) MnO2 2 (H2O) + (O2) | 4. reddish-brown deposit
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Double Replacement Reactions Lab Pre-Lab 1. If a solid‚ a gas or a weakly ionizing compound such as H2O formed‚ then a reaction has occurred. 2. The formation of a solid‚ the formation of a gas and the formation of a weakly ionizing compound are the driving forces that control a double replacement reaction. 3. a. Balanced equation: CaCl2 (aq) + NaPO4 (aq) Ca3(PO4)2 (s) + 6NaCl (aq) Ionic equation: 3Ca2+(aq) + 6Cl-(aq) + 6Na+(aq) + 2PO43- (aq) Ca3(PO4)2 (s) + 6Na+ (aq)
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temperature on reactions between the enzyme catalase found in animal tissue with the substrate H2O2. The hypothesis stated that an increase in the temperature of the substrate would create a subsequent increase in the rate of reaction between the enzyme and the substrate. This hypothesis was tested by immersing 1cm cubes of animal tissue (sheep liver) which contained the enzyme catalase into the substrate (H2O2 ) mixed with detergent which foamed showing a visual display of the reaction. After 10 seconds
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Experiment 15 & 16: Preparation of 1-bromobutane‚ an SN2 reaction Preparation of 2-chloro-2-methylbutane‚ an SN1 reaction Introduction The purpose of this experiment is to synthesize 1-bromobutane from 1-butanol and sodium bromide. In order for this reaction to reach completion there are four major operations that need to be performed. The four major operations include refluxing‚ simple distillation‚ separation‚ and drying. To begin‚ in order for the compounds to react they will be dissolved
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of the mass and the mole has to be the same; by this we can check the actual equation and the actual oxidation number of iron in this reaction. This process will finally end us up of finding out which oxidation number of iron is used in this experiment. So‚ if the oxidation number is 2: Fe (Ⅱ) + CuCl2 (aq) → Cu + FeCl2 If the oxidation number is 3 the reaction equation will be: 2Fe (Ш) + 3CuCl2 (aq) → 3Cu + 2FeCl2 In addition‚ we will need to find the percent yield of copper. Percent yield is
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