excess of potassium iodide solution to a known volume of an acidified standard potassium iodate solution according to the following equation: IO3-(aq) + 5 I- (aq) + 6 H+ (aq) 3I2 (aq) + 3H2O (l) Then the experiment is immediately followed by a back titration of the excess liberated iodine with standard sodium thiosulphate solution as shown below: I2 (aq) + 2S2O32- (aq) → 2I- (aq) + S4O62- (aq) With iodine solution‚ the thiosulphate ion is oxidized quantitatively to tetrathionate ion. The amount of
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The reactions showed that hydrogen ions were produced at the anode‚ making it acidic and hydroxide ions were produced at the cathode‚ making it basic. In all parts of the experiment‚ the reaction that took place at the anode was 2H2O(l) O2(g) +
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one reaction between the titrant and the analyte [6]. ( )( ( ) )( ( ( ) ) ) In Reaction 1‚ the analyte of unknown concentration was titrated against the standard Iodine solution. It reduced the titrant‚ Iodine (I2)‚ into Iodide; while the titrant acted as oxidizing agent to the analyte. The reduction of iodine was dependent on the strength of its reducing agents; weakest reducing agents do not proceed to completion due to Iodine’s comparatively weak oxidizing capacity;
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changing concentration: iodine clock reaction. Abstract This is an experiment to show the Iodine Clock Reaction. To create a chemical reaction to see how long it takes for solution to change to a dark blue Color. When changing the concentration of the iodide (K1) and adding distill water to make it up to 5cm³ each time. This is to see if the reaction takes less with less concentration or faster with more concentration added to the peroxodisulphatee. So with the solution made with more concentration it
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I- :2S2O32I2 + 2e S4O62- + 2e 2I- The iodine/thiosulphate titration is a general method for determining the concentration of an oxidising agent solution. A known volume of an oxidising agent is added into an excess solution of acidified potassium iodide. The reaction will release iodine:Example: (a) With KMnO4 2MnO4- + 16H+ + 10I(b) With KIO3 IO3- + 5I+ 6H+ 3I2 + 3H2O 2Mn2+ + 5I2 + 8H2O The iodine that is released is titrated against a standard thiosulphate solution. From the stoichiometry of the
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ALCOHOLS Alcohols are compounds in which one or more hydrogen atoms in an alkane have been replaced by an -OH group. For the purposes of UK A level‚ we will only look at compounds containing one -OH group. For example: Primary alcohols In a primary (1°) alcohol‚ the carbon which carries the -OH group is only attached to one alkyl group Some examples of primary alcohols include: Secondary alcohols In a secondary (2°) alcohol‚ the carbon with the -OH group attached is joined directly to
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CO3 + H2SO4 = bubbly reaction‚ little to no colour change. CO3 + 6M HCl = Barrium hydroxide began to go cloudy‚ indicating the presence of BaCO3(Carbonate anions) Chloride Solution + 0.1M AgNO3 =white precipitate formed‚ very fine texture. Iodide solution + 0.1M AgNO3 =yellow/white precipitate formed‚ cloudy texture. Silver Chloride + ammonium hydroxide = white precipitate forms‚ slowly begins to disappear. Adding HNO3 the reappearance of a white precipitate began‚ indicating the presence
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Lorraine Chen Chem 106 Lab South Street Seaweed Seaport Warm up: 1. Coffee Beans are crushed into small pieces‚ water is added to it and the mixture is heated over a flame. What do you think would happen to the coffee beans as it interacts with the water? Explain your prediction I think the heating of the water and coffee beans would cause the water to turn a light brown color because this process is most likely removing some kind of excess substance from the surface of the coffee beans. This
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chlorine-containing metabolites‚ such as chlorite and chloride ions. Abdel-Rahman et al. (1980b) developed a method to quantitatively and qualitatively measure the metabolites of chlorine dioxide (e.g.‚ ClO2-‚ and ClO-) in biological fluids. These biomarkers can be used to indirectly measure chlorine dioxide exposure. The concentration of residual chlorite ion in vegetables and eggs treated with sodium chlorite was determined by UV-ion chromatography (Suzuki et al. 1997). Sodium chlorite was extracted
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or loses electrons while being bonded with another atom an ion is formed. This bond causes an atom to become either a positive or negative ion. Electrons have a negative charge‚ meaning that if an atom loses an electron‚ the amount of protons are greater than electrons. This makes the atom turn into a positive ion which is known as a cation. The opposite of this is known as an anion‚ which is when an atom gains electrons and becomes an ion that is negative. Non-metals form anions and metals form cations
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