A cylinder is a shape with a circular bottom at the both ends that kind of looks like a pringles potato chip bottle THE formula of finding the volume of a cylinder is base area times height of cylinder. The base area will be the area of the circle which is pi x radius x radius So you just take that answer and multiply it by the height of a cylinder. done math math math cylinder cylinder asdfghjk lkjhgh jhgf ghjxskdskdgc kdshfkhshfkshksskkkkjs wordlimit mine is
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Title: Preparation of Solutions and Buffers Objectives: 1. To learn and understand the theory‚ principle and formula behind buffers and solutions preparation. 2. To learn the methods for buffers and solutions preparation. Introduction: (Wikipedia‚ 2013) Solute is a substance dissolved in another substance. Solvent is a substance in which the solute is dissolved by it. Solution is a mixture of two or more substances. The amount of solute dissolved in a solvent is called concentration
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-1Determination of an Unknown Liquid (2-butanol) Through Fundamental Analysis Lee Billips Department of Chemistry‚ Shippensburg University‚ 1871 Old Main Drive. Shippensburg‚ PA‚ 17257. Abstract: The identification and characterization of unknowns are an important part of organic chemistry. It is fundamental to know experimental methods to deductively identify compounds (1) . The determination of unknown #6 (2-butanol) was identified by a series of test; first taking the boiling point (94-96
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Goals The main goal of this project is to learn how to identify the properties of an unknown ionic compound. In order to do this successfully the group has to use a variety of methods and run several tests on the unknown compound. By doing this the group will be able to identify the different chemical and physical properties of the compound that will help obtain the identity of the specific compound given. The group will devise two syntheses of the compound‚ and compare them for cost effectiveness
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Intelligence: Knowns and Unknowns Ulric Neisser (Chair) Gwyneth Boodoo Thomas J. Bouchard‚ Jr. A. Wade Boykin Nathan Brody Stephen J. Ceci Diane E Halpern John C. Loehlin Robert Perloff Robert J. Sternberg Susana Urbina In the fall of 1994‚ the publication of Herrnstein and Murray ’s book The Bell Curve sparked a new round of debate about the meaning of intelligence test scores and the nature of intelligence. The debate was characterized by strong assertions as well as by strong
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• initial assessment in identifying learner needs: Reference question: Describe ways you could‚ or do‚ initially assess your learners. Reflect on what the strengths and pitfalls of these methods might be. For an initial assessment‚ I would incorporate a questionnaire and self-assessment task. With the use of questionnaire‚ I can easily collect the information needed from the learner including the learning support‚ expectations and the like. On the other hand‚ questions might misinterpreted by
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Abstract ( why people willing to choose harmful ways to lose weight ) Nowadays‚ there seems to be a trend among the new generation. They want to appear with slim and fit body. Some of them will choose the harmful ways such as extreme dieting and taking pills which are not certified by health authorities to achieve their goals. People nowadays want to slim down because of their perspective‚ they assume that thin is beautiful or handsome. This is because model or artists are mostly slim and fit
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Experiment 3 : Preparation of Solutions and Buffers Objectives : 1. To study and understand the principle theory and formula of preparation of buffer and solution. 2. To learn the methods of buffer and solution preparation. 3. To focus on concentration units of molarity‚ percentage of concentration‚ and dilution of solution. Introduction : When a substance‚ called a solute‚ is dissolved in another substance‚ called the solvent‚ a solution is formed. A solution is known as a homogeneous
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The unknown soda ash from experiment 3 was used‚ to determine the weight for each trial we used the equation of (M of HCl) x (18 ml x 105.99) / (10 x 2 x Na2CO3 ). Which was equal to (0.01472 M) x ((18 mL X 105.99)(10 x 2 X 2.428 % )= 0.6 g. To start we had to rinse the beakers‚ electrode and the stirring bar with diluted water. The sample we needed was weighted to the closest 0.1 mg which we got was 0.3 for the first trial. The sample was transferred to a 250 mL beaker and dissolved in 70 mL of
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