Section IV will contain our reported results‚ error analysis‚ and discussion of any possible conflicts with theory. Finally‚ in Section V‚ we will provide the reader with a summary of our experiment with major conclusions. where I0 is the moment of inertia about the point of oscillation and α is simply the angular acceleration. We note that this ultimately yields the following differential equation −M dg sin θ d2 θ = dt2 I0
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moment of inertia of an assembly and using the result to predict the periodic time of a trifilar suspension of the assembly. Theory: The moment of inertia of a solid object is obtained by integrating the second moment of mass about a particular axis. The general formula for inertia is: where Ig = inertia in kg.m2 about the mass centre m = mass in kg k = radius of gyration about mass centre in m. In order to calculate the inertia of an assembly‚ the local inertia Ig needs
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Flywheels Laboratory Experiment 4 Aziz Darwish H00124728 14th November‚ 2012 Mechanical Engineering B51PX Praxis Mounif Abdallah Contents Page number Abstract/Introduction 1 Aim/Objective 1 Theory 1-2 Apparatus (Equipment) 3 Procedure 3 Calculations 3-4 Results
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CONTENTS CONTENTS 972 l Theory of Machines 24 eatur tures Features 1. Introduction. 2. Natural Frequency of Free Torsional Vibrations. 3. Effect of Inertia of the Constraint on Torsional Vibrations. 4. Free Torsional Vibrations of a Single Rotor System. 5. Free Torsional Vibrations of a Two Rotor System. 6. Free Torsional Vibrations of a Three Rotor System. 7. Torsionally Equivalent Shaft. 8. Free Torsional Vibrations of a Geared System. Torsional Vibrations 24.1. Introduction We have
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moment of inertia of an assembly and using the result to predict the periodic time of a trifilar suspension of the assembly. Theory: The moment of inertia of a solid object is obtained by integrating the second moment of mass about a particular axis. The general formula for inertia is: where Ig m k I g = mk 2 = inertia in kg.m2 about the mass centre = mass in kg = radius of gyration about mass centre in m. In order to calculate the inertia of an assembly‚ the local inertia Ig needs to
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Kinetics of Motion 1. Introduction. 2. Newton’s Laws of Motion. 3. Mass and Weight. 4. Momentum. 5. .orce. 6. Absolute and Gravitational Units of .orce. 7. Moment of a .orce. 8. Couple. 9. Centripetal and Centrifugal .orce. 10. Mass Moment of Inertia. 11. Angular Momentum or Moment of Momentum. 12. Torque. 13. Work. 14. Power. 15. Energy. 16. Principle of Conservation of Energy. 17. Impulse and Impulsive .orce. 18. Principle of Conservation of Momentum. 19. Energy Lost by .riction Clutch
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ES 12: Dynamics of Rigid Bodies First Semester‚ 2012-2013 Due: October 5‚ 2012/ Class Hours PROBLEM SET FOR LQ4 Instructions: 1. Answer this problem set at the back page of used short/A4 size bond paper. 2. At the TOPMOST portion of the first page of your answer sheets‚ write the following: “I hereby certify that I have worked on this problem set by my own honest effort‚ without giving or receiving any inappropriate help. I understand that any evidence which contradicts the foregoing statement
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SAMPLE PROBLEMS: 111-SET #9 ROTATIONAL MOTION PROBLEMS: 09-1 1) A grinding wheel starts from rest and has a constant angular acceleration of 5 rad/sec2. At t = 6 seconds find the centripetal and tangential accelerations of a point 75 mm from the axis. Determine the angular speed at 6 seconds‚ and the angle the wheel has turned through. |We have a problem of constant angular acceleration. The figure & coordinate system are |[pic]
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The moment of inertia is a measure of an object’s resistance to changes in its rotation. It must be very specific to the chosen axis of rotation. Also‚ it is specific to the mass and shape of the object‚ including the way that is mass is distributed in the object. Moment of inertia is usually quantified in kgm2. An object’s where the mass is concentrated very close to the center of axis of rotation will be easier to spin than an object of identical mass with the mass concentrated far from the axis
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Where P is the applied force‚ L is the length of beam‚ E is the modulus of elasticity of aluminum‚ and I is the moment of Inertia. For a beam of rectangular cross section‚ say of width w and thickness t‚ the same mid spam deflection of the centrally loaded beam when the flat side is supported‚ then be compared to that when the thin side is supported. The moment of inertia for the respective situations are given by: I1 = wt3/12 and I2 = w3t/12 It could be readily verified that the later situation
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