Srivastava’s Srivastava’s MOTION IN ONE DIMENSION 1. A particle is projected vertically upwards with a velocity 20 m s1 from the top of the tower of height 100 m. Determine the time it takes to reach the ground. Answer: t 2 1 6 sec. A particle is dropped from the top of the tower of height h. At the same instant another particle is projected vertically upwards from the bottom of the tower with such a velocity that it will be able to just reach the top of the tower. When and at what height from ground
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released until it strikes the ground. 4. The time it takes for the ball to hit the ground depends on v0 ‚ g and h. 004 10.0 points The velocity of a projectile at launch has a horizontal component vh and a vertical component vv . When the projectile is at the highest point of its trajectory‚ identify the vertical and the horizontal components of its velocity and the vertical component of its acceleration. Consider air resistance to be negligible. 4. It cannot be determined. 002 10.0 points
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Task question In my task question I am going to study why does the velocity vary downstream? To carry out this investigation we will be going to Carding Mill valley; carding mill valley is located near the border of Wales‚ North West England in Shropshire. (This can be seen on image 1) (Image 1) (Image 1) This means we are collecting primary data which is mainly so we can get accurate and reliable set of results. In order to answer the task question
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(objects) and systems (groups of objects) without consideration of the forces that cause the motion. There are four activities done in this experiment. Graphical analysis of human motion‚ where displacement vs time and velocity vs. time were graphed. Graphical analysis of motion where in the 10th seconds the total displacement is 18.75m‚ average velocity is 1.88m/s and instantaneous velocity is 3.76m/s. Reaction time where one of the normal reaction time among the group is 0.16s and the reaction time
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Relative Velocity and Riverboat Problems On occasion objects move within a medium that is moving with respect to an observer. For example‚ an airplane usually encounters a wind - air that is moving with respect to an observer on the ground below. As another example‚ a motorboat in a river is moving amidst a river current - water that is moving with respect to an observer on dry land. In such instances as this‚ the magnitude of the velocity of the moving object (whether it be a plane or a motorboat)
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VECTOR & RELATIVE VELOCITY Set 1 1. What is the total displacement of a trip in which a person travels 10 km[N] and then 24 km[E]? 2. What is the total displacement of a trip of 50 km[W] followed by a trip of 100 km[N30°E]? 3. What is the total displacement of a trip of 100 km[N30°E] followed by a trip of 50 km[W]? What is significant about the result when compared to the answer for question 2? 4. A small boy goes to a store 2 blocks[N]‚ 3 blocks[E]‚ l block[S]‚ 5 blocks[W]
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2: SPEED‚ VELOCITY AND ACCELERATION 2.1 Distance and Displacement • Distance is the total length covered by a moving object irrespective of the direction of motion‚ i.e. only the magnitude is of importance. • Displacement is the distance measured in straight line AND in a specific d__________________. Both magnitude and d_________________ are important. Example 1 A car travels 5 km due east and makes a U-turn back to travel a further distance of 3 km. Find (a) the distance covered‚ (b)
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from the origin. Position –Time Graph Graph increased with time and then become constant Velocity-Time Graph Graph increased and decreased with time and then become zero Acceleration –Time Graph Graph increased and decreased with time some time becomes positive and some tie negative then zero. 2. In red make a prediction for the distance-time‚ velocity-time and acceleration-time graphs for each situation. b. The man is sleeping under the tree. When
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7t – 3t2‚ where x is in meters and t is in seconds. Its average velocity over the interval from t = 0 to t = 2 s is: A) 5 m/s B) –5 m/s C) 11 m/s D) –11 m/s E) –14.5 m/s vt= 7-6t = 7-12=-5 m/s 3. The coordinate of a particle in meters is given by x(t) = 16t – 3.0t3‚ where the time t is in seconds. The particle is momentarily at rest at t = A) 0.75 s B) 1.3 s C) 5.3 s D) 7.3 s E) 9.3 s 0=16-9t2 t2=16/9 t=1.33 s 4. Over a short interval near time t = 0 the coordinate
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09-1 Velocity Cellular Case Power Starterpack is part of Velocity Cellular Services that provides both the wireless services and products (cellular phones) to its clients. At the beginning of a cell phone contract‚ a cellular phone is sold with a wireless service that will generate cash for the service provider for the length of the contract; making Velocity Cellular Service multiple deliverables. Power Starterpack compromises of a single deliverable because the only service it is providing
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