systems | Learning Outcomes | LO2.1 | LO2.2 | | | | | | LO 03: Be able to build and configure computer systems | Learning Outcomes | LO3.1 | LO3.2 | | | | | | LO 04: Be able to undertake routine maintenance on computer systems. | Learning Outcomes | LO4.1 | LO4.2 | | | | | | Merit and Distinction Descriptor | M1 | M2 | M3 | D1 | D2 | D3 | | | | | General Guidelines 1. A Cover
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End College of Business & Computing Centre No: 10562 Learner’s Name: Assessor’s Name: Miss O Okuwobi Assessor’s Signature: Date: 04/02/2013 Date Issued: 04/02/2013 First Submission Date: Final Submission Date Feedback Date: 10/04/13 20/10/13 19/03/2013 (Task 1 and Task 2 23/09/2013 (Task 3 and Task 4) 01/04/2013(Task 1 & 2) 01/10/2013 (Task 3&4) Learner Declaration I declare that all the work submitted for this assignment is my own work or‚ in the case of group work‚ the work myself and
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Reserve Bank of India will announce its Monetary and Credit Policy for the first half of the financial year 2002-03 on April 29. Even as RBI Governor Bimal Jalan puts the finishing touches to the document‚ have you ever considered what is the significance of the biannual exercise? In a world of policies in the financial sector‚ nothing could get as alien as the Monetary Policy. Terms like M3‚ CRR‚ SLR‚ PLR and OMO would make you think that the typical IT-bug has caught the financial sector. But take
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m/2)3 (Initial volume. You must take the diameter and divide by to to get the radius. Then you must stick it in the formula for volume of a sphere: (4/3)r3 Vo = .001569 m3 T = 170Cº (Change in temperature. 200Cº - 30Cº.) I then had the formula: V = 1e-6*.001569m3*170Cº V = 2.7 e-7 m3 *1e6 (Conversion from m3 to cm3.) V = .27 cm3 The answer is therefore .27 cm3. 19. If the fluid is contained in a long‚ narrow vessel so it can expand in essentially one direction only‚ show that
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a brand-new Mac Plus to help out with his studying‚ he found out it could not display grayscale images on the monochrome monitor. Without waiting a moment he started writing his own code to do the job. John‚ was also working on image processing at ILM and during a
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khayrun. [Type the abstract of the document here. The abstract is typically a short summary of the contents of the document. Type the abstract of the document here. The abstract is typically a short summary of the contents of the document.] ilm seeker mini book series www.amuslimhomeschool.com Welcome Ramadan by Allah tells us in the Qur’an… َّ َ ِ ۡ َ َّ ِ ۡ ُ َ َ َ ُوما خلَ ۡقت ٱلجن وٱۡلنس إَِّل لِي َۡعبُد ون ِ I created the jinn and humankind only that they might worship
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Mat MPS 1 Part A: Determining fair rank between teams(no ties) Let win=3‚ draw=1 and lose=0. The reason for this weighting method is because it is natural for the loser not to get a point. Also‚ there must be a visible gap between winners and draw players. This can be proved by contradiction proof. Blue | B | Crimson | C | Green | G | Orange | O | Red | R | Yellow | Y | Assume that win=2 draw=1 and lose=0. If the supremacy matrix is calculated‚ tie always occurs‚ which proves that
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57 M3 B) Since liver cells are spherical Volume of a sphere = 4/3r3 (Radius of liver cell = 20 M/2 = 10 M) 4/3*4187 M3 C) Volume of cylindrical palisade cells = r2h = *(10)235 = 10990 M3 B) How many E Coli will fit inside the human liver cells? # of E. Coli that can fit in liver cells = Volume of Liver Cells/Volume of E Coli = 4187 M3/1.57
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830 large units engaged in textile industrial processes in Tirupur alone. These industries have established eight Common Effluent Treatment Plants (CETPs) and many individual Effluent Treatment Plants (ETP)‚ which are subjected to treat about 75‚000 m3 of effluent per day genereated by textile industries. On the other hand‚ the sludge that retained due to the solids separation process in the treatment plants create lot of environmental problems due to lack of disposal methods. The practicing method
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450°C based on (a) the ideal-gas equation‚ (b) the steam tables. 5. A 3.27-m3 tank contains 100 kg of nitrogen at 175 K. Determine the pressure in the tank‚ using (a) the ideal-gas equation. Compare your results with the actual value of 1505 kPa. 6. A 1-m3 tank contains 2.841 kg of steam at 0.6 MPa. Determine the temperature of the steam‚ using (a) the idealgas equation 7. A piston–cylinder device initially contains 0.07 m3 of nitrogen gas at 130 kPa and 120°C. The nitrogen is now expanded to a pressure
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