2013 Percent Yield of Calcium Carbonate Introduction: The purpose of this experiment is to examine the percent yield of a precipitate in a double displacement reaction. A solution of calcium citrate and sodium carbonate were mixed together‚ then the products were filtered out as so only the precipitate remained. The filtered paper was then dried and the mass of the precipitate in the experiment divided by the theoretical mass of the precipitate from the calculated gave the percent yield. The
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Description Whenever we do experiments‚ the actual result is a little different from the result we predicted. In chemistry‚ this discrepancy is compared by calculating the percent yield. In this lesson‚ we will define percent yield‚ and go over a few examples. !!!What is Percent Yield? Sometimes you look at a recipe and it says how many servings it will make if you follow the amounts listed on there. There are times‚ however‚ that the number of servings after you have made the food is not the
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The Grignard Synthesis of Triphenylmethanol Abstract: Grignard synthesis of triphenylmethanol was achieved by use of the Grignard reagent phenyl magesium brominde. The organometallic grignard reagent was synthesized by use of a reflux apparatus recrystallization techniques. Once synthesized it was used in a Grignard reaction that involved nucleophilic addition to a carbonyl in order to make triphenylmethanol. The final product was solidified and recrystallized and spectral data was
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Grignard Synthesis of Triphenylmethanol Aim The aim of this experiment was to prepared Grignard reagent (phenylmagnesium bromide) from bromobenzene and magnesium‚ to use the reagent prepared to synthesise a tertiary alcohol (triphenylmethanol) by reacting reagent and ester (methyl benzoate)‚ and the product formed is analyse by infrared spectroscopy (IR)‚ melting point‚ thin layer chromatography (TLC)‚ gas chromatography mass spectrum (GCMS) and finally Nuclear Magnetic Resonance spectroscopy. Introduction
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| Percent Yield Lab | | | | 4/20/2012 | Mrs.Sardella Per4 Matt ‚ Kait Mrs.Sardella Per4 Matt ‚ Kait | Introduction *Limiting Reactant: A reactant that is completely consumed during a chemical reaction‚ limiting the amount of product that is produced. *Excess Reactant: A reactant that remains after a reaction is over. *Theoretical Yield: The amount of product that is predicted by stoichiometric calculations *Actual Yield: The amount of product that is recovered
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conditions. The experiment resulted in 8.29grams of purified compound‚ which is a 66.27 percent yield. Procedure: As per handout with changes Equation: Mechanism: Results: (Scan IR spectrum) Compounds t-Butyl Chloride(Experimental) t-Butyl Chloride(Book Value) Molecular Weight (g/mol) 92.5681 92.5681 Density (g/cm3) 0.842 0.842 Boiling Point (°C) 48 50 Refractive Index 1.3855 1.3857 Theoretical Yield: Let A = t-Butyl Alcohol Let C = t-Butyl Chloride 10.02gA x 1 mol A x 1 mol C
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Tie-Dye Grignard Synthesis Abstract: 4-Bromo-N‚N-dimethylaniline underwent a Grignard reaction with diethyl carbonate to produce a type of the tie-dye chemical triarylmethane. This specific triarylmethane produces a vivid crystal violet color when dyed. The experiment was first heated under reflux to produce the necessary Grignard reagent as a grey liquid. It was then reacted with diethyl carbonate and hydrochloric acid to produce crystal violet. The resulting chemical was very absorbent to
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Grignard Synthesis of Triphenylmethanol from Benzophenone Purpose: The purpose of this experiment was to synthesize the tertiary alcohol triphenylmethanol from a Grignard reagent‚ phenyl magnesium bromide. The Grignard reagent was synthesized from bromobenzene and magnesium and then reacted with benzophenone to produce triphenylmethanol. It was important that water be excluded from the reaction‚ in order to prevent the formation of benzene. The reaction of phenyl magnesium bromide and benzophenone
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Determine the theoretical yield of the NaCl product‚ showing all of your work in the space below. (5 points) NaHCO3 – The Empty Dish 37.06 (grams) – 24.35 (grams) = 12.71 (grams) NaHCO3 12.71 (grams) NaHCO3 ÷ 84.01 (grams/mole) = 0.1513 moles of NaHCO3 0.135 Moles of NaHCO3 × 58.4428 (Molar mass of NaCl) Giving me 8.8240 (grams) NaCl as my theoretical yield. 4. What is the actual yield of NaCl in your experiment? Show your work below. (4 points) The actual yield is: 31.52 (grams) – 24.35 (grams)
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The Grignard Synthesis of Triphenylmethanol Organic Chemistry Lab II March 19‚ 2012 Abstract The purpose of this experiment was to synthesize the Grignard reagent‚ phenyl magnesium bromide‚ and then use the manufactured Grignard reagent to synthesize the alcohol‚ triphenylmethanol‚ by reacting with benzophenone and protonation by H3O+. The triphenylmethanol was purified by recrystallization. The melting point‚ Infrared Spectroscopy‚ 13C NMR‚ and 1H NMR were used to characterize and confirm
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