Objective: The benefit of this lab was to acquaint oneself with the fundamentals of the Aldol Condensation reaction by demonstrating the synthesis of dibenzalacetone (trans‚ trans-1‚5-Diphenyl-1‚4-pentadien-3-one) through the aldol condensation of acetone with benzaldehyde. The synthesis began by using a strong base to generate the acetone enolate ion. The ketone/enol tautomerization is an equilibrium process that produces little of the enol (ppm or less). However‚ any enol that formed quickly reacted
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test‚ Iodoform Test‚ and Lucas Test. This was conducted to classify the samples from being a primary alcohol‚ a secondary alcohol‚ a tertiary alcohol‚ aldehyde‚ or a ketone. Introduction In analyzing the oxygen bearing organic compounds‚ there are several tests that may be performed to distinguish among the different classes of alcohols‚ aldehydes‚ and ketones. All these tests exploit differences in the type and degree of reactivity of each of the functional groups. Several different oxidizing agents
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condensation reaction using an unknown aldehyde and an unknown ketone. H NMR is used to identify the unknown aldehyde and ketone. Melting point is used to identify the aldol condensation reaction. Theory: Condensation reaction is also known as a dehydration reaction. In the mechanism of condensation reaction‚ a bond is formed between two molecules and creates water as a byproduct. Aldol condensation is a C-C bond forming reaction between the alpha Carbon of the aldehyde or ketone and carbonyl carbon of
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oxygen (different than an aldehyde because it can only be found in the inside of a molecular chain- the carbon does not have to be attached to a hydrogen). Ketones‚ aldehydes‚ and carboxylic acids contain the carbonyl functional group: C double bound to O. Alkyl Halide: haloalkane‚ replace X in the drawing with a halogen from the periodic table; when drawing a haloalkane be sure to not forget the lone pairs on X (there are three below) :O: X C C C C Aldehyde: defined by a carbon
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formed. This product formed involves two aldehydes or ketones in the presence of dilute base‚ yields a molecule having both aldehyde and alcohol. The aldol products are β-hydroxyaldehydes or β- hydroxyketones. Condensation reaction is the transformation that result from combination of large molecules to produce another larger molecule. In an aldol condensation‚ β-hydroxyaldehyde or a β-hydroxyketone is produced in but upon heating the α‚β-unsaturated aldehyde or ketone with water is produced. In double
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(Corresponding author) Departamento de Química‚ Faculdade de Ciências and Tecnologia Quinta da Torre‚ 2829-516 Caparica‚ Portugal E-mail: mbgawande@yahoo.co.in‚ m.gawande@fct.unl.pt Abstract A new one-pot and efficient three-component condensation of aldehydes‚ ketones‚ and amines in the presence of MgO/ZrO2 as an inexpensive and effective catalyst for the synthesis of β-amino carbonyl compounds by Mannich reaction is described. The present methodology offers several advantages‚ such as good yields‚ short
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Aldol Condensation Discussion: 1. Aldol condensation reactions take place in basic conditions‚ where a deprotonated enol becomes an enolate and proceeds to attack the aldehyde. Since the solution is basic‚ it is able to deprotonate the alpha carbons of the product‚ which forces the hydroxide groups to leave. The product is then considered to be dehydrated and unsaturated. In terms of our reaction‚ cyclopentatone is deprotonated to form an enolate‚ which then attacks the two molecules of p-tolualdehyde
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predictable ways‚ making it possible to develop diagnostic reactions to test for their presence in an organic molecule. Common functional groups found in organic molecules are listed below: * Alkene * Primary alcohol * Tertiary alcohol * Aldehyde * Ketone * Carboxylic acid * Ester * Halogen alkane * Phenol Alkene In organic chemistry‚ an alkene is an unsaturated chemical compound. This means it contains a carbon – carbon bond. All alkenes are hydrocarbons‚ (a molecule
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sharp absorption at 1705 wavenumbers. This indicates the presence of a carbonyl. Therefore I had to prove which of the two compounds my final product was. The first was the oxidation of the primary alcohol‚ forming an aldehyde and a secondary alcohol. The textbook states that aldehydes show 2 characteristic absorption’s in the range of 2720-2820 wavenumbers. No such absorption’s were present in my sample. Therefore my final product was the oxidation of the secondary alcohol. My final product had a
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A- HPTLC Flavonoid profile of methanol extract M. concanensis leaves B- HPTLC Flavonoid profile of methanol extract M. concanensis flowers C- HPTLC Flavonoid profile of methanol extract M. concanensis seeds 4.2.3.1 C) HPTLC Phenol profile of M. concanensis Nimmo. HPTLC finger printing of M. concanensis was done by using selected solvent system Chloroform: Ethyl acetate: Formic acid (50%:40%:10%v/v) for leaf‚ flower and seed extracts‚ visualized under UV 254 and 366 nm showed more
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