Page 1/3 09/2010 SE 110.22 Forces in an Overdeterminate Truss The picture shows SE 110.22 in a frame similar to SE 112. * Comparison of forces in statically determinate and overdeterminate trusses1 * Bars with strain gauge full bridges to measure bar force1 * Computerised evaluation of experiments Technical Description Overdeterminate trusses are employed where overdimensioning is purposely required because safety must be maintained in the event of failure of an element‚ such as in aircraft
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of motion: The resultant force is proportional to the change in momentum per a second. We know that force = mass x acceleration. So F (mv-mu)/t F m (v-u)/t = ma so F=kma Momentum is a vector quantity: Momentum has a direction as well as a magnitude Momentum and Newton’s first law of motion: An object remains at rest or in uniform motion unless acted upon by a force. If an object had a constant momentum‚ it will have a constant amount of force needed to that will mean
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Physics r r W =F s Force× Displacement = Force × Displacement *SI Units: 1 N.m = 1 Joules (i.e. same as the unit of energy) 2 Recall “Dot Product” The dot product allows us to multiply two vectors to get something that is SCALAR. r A r A For a constant force: r r r B = A B cos ! r B = Ax Bx + Ay By + Az Bz Only those along the direction of motion contribute to the total work done on an object. 3 With position-dependent forces F Vector sum of all forces acting on the body Area
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OBJECTIVE The purpose of this assignment is to experimentally and analytically determine shear forces and bending moments when an external load is applied in various scenarios. In turn‚ we aim to investigate the relative accuracy of such comparisons taking into considerations possible practical applications and possible attributes to the error. Additionally‚ we attempt to develop shear force and bending moment diagrams using MATLAB. Finally we investigate the loadings in a real life situation
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Purpose The purpose of this experiment is to test Coulomb’s Law which states that the force between two spherically symmetric charged objects is directly proportional to the product of the charges‚ and inversely proportional to the square of the distance between the centers of the two charges. In mathematical vector notation Coulomb’s Law is expressed as where Fr is the force on particle 1 due to particle 2 in Newtons‚ q is the charge on 12 1 particle 1 in Coulombs‚ q2 is the charge on particle
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secured them in two smaller boxes. I secured the eggs in the smaller boxes by rolling a piece of cardboard about an inch in width around the egg to create a holder. The egg can easily slide in out of the holder‚ but not easily enough to fall out once a force is applied. I taped the holder to smaller squares of cardboard and taped them down to the bottom of the smaller box. Each small box had the same construction. Finally‚ to secure the smaller boxes in the big box‚ I hot glued them down in the center
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trains. The passenger train should move quickly with high speeds. The rail road will not be always straight it should pass through curves and turns. We all know that if you are driving in your car and you take a turning at speed you feel centrifugal forces. Well it is no different from
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Momentum Running: When running the bases in softball‚ there is a lot more to it then the average person would think. While we run the bases‚ we are changing our momentum by applying more force‚ the force of friction‚ onto the ground which causes more force exerted on us because of Newton’s 3rd law. Applying more force in turn increases the base-runner’s velocity. Catching: When catching a fly ball or grounder‚ it is best to move with the ball and not catch it right over your head or right in front
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to figure out the net force and its direction on the Apollo 13 spacecraft as it followed its path. NASA made sure that Apollo 13 would make it back to Earth and not be lost in space. Another scene in which Newton’s Law of Universal Gravitation was needed was when the Apollo 13 crew needed to execute a burn. This law helped them calculate the forces acting on them by other planetary objects‚ and therefore how much force their burn needed to apply. By simply adding together force vectors NASA could predict
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(deceleration) S = 2a v2 u2 = 2( 1) 0 102 = 2 100 = 50m It will travel 50m before coming to rest. 3. Body is kept on the horizontal table. If no force is applied‚ no frictional force will be there f frictional force F Applied force From grap it can be seen that when applied force is zero‚ frictional force is zero. 4. From the free body diagram‚ R – mg cos = 0 R = mg cos ..(1) For the block U = 0‚ s = 8m‚ t = 2sec. s = ut + ½ at2 8 = 0 + ½ a 22 a = 4m/s2
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