Chapter 12 Problems 1. Cash flow (LO2) Assume a corporation has earnings before depreciation and taxes of $100‚000‚ depreciation of $50‚000‚ and that it has a 30 percent tax bracket. Compute its cash flow using the format below. Earnings before depreciation and taxes _____ Depreciation _____ Earnings before taxes _____ Taxes @ 30% _____ Earnings after taxes _____ Depreciation _____
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created on a graph when using a frequency distribution method for a set of data‚ splitting the mean symmetrically. There is a big difference between standard deviation and the bell curve! Standard deviation shows the difference in variation from the average; the bell curve‚ also normal distribution or Gaussian distribution‚ shows the standard deviation and is created by the normal or equal distribution of the mean among either half. The bell curve is an important distribution pattern occurring in many
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sold‚ and that units left unsold at the end of the season were sold at a loss that average 8 percent of wholesale price. Therefore‚ the stock out probability equal to 8%/(24%+8%)=25% so there are 75% probability of being less than mean+0.67*SD (standard deviation). According to z table‚ z equal to 0.67 when probability is 0.75. Therefore‚ we can calculate quantity for each style include the risk of stock out by using formulate Q*=mean+z*SD. Therefore‚ we can get the maximum order units for each style
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Student Exploration: Sight vs. Sound Reactions Vocabulary: histogram‚ mean‚ normal distribution‚ range‚ standard deviation‚ stimulus Prior Knowledge Questions (Do these BEFORE using the Gizmo.) Most professional baseball pitchers can throw a fastball over 145 km/h (90 mph). This gives the batter less than half a second to read the pitch‚ decide whether to swing‚ and then try to hit the ball. No wonder hitting a baseball is considered one of the hardest things to do in sports! 1. What
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Standard Deviation in the Business World QRB/501 Abstract On Standard Deviations in Job Performance The purpose of this study was to compare the expected payoffs from personnel programs based on standard deviation of job performances in dollars‚ the Global Estimation model‚ and the CREPID procedure. The study was done for route salesmen of a large soft drink bottling company. The Global Estimation model and the CREPID procedure were behaviorally based‚ where the standard deviation of job performance
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m and the women have a mean height of 1.62 m. Find the mean height of the 100 mathematicians. (Total 4 marks) 3. The mean of the population x1‚ x2‚ ........ ‚ x25 is m. Given that = 300 and = 625‚ find (a) the value of m; (b) the standard deviation of the population. (Total 4 marks) 4. A supermarket records the amount of money d spent by customers in their store during a busy period. The results are as follows: Money in $ (d)|0–20|20–40|40–60|60–80|80–100|100–120|120–140| Number of
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milligrams of tar per cigarette and a standard deviation equal to 1.0 milligram. Suppose a sample of 100 low-tar cigarettes is randomly selected from a day’s production and the tar content is measured in each. Assuming that the tobacco company’s claim is true‚ what is the probability that the mean tar content of the sample is greater than 4.15 milligrams? [0.00621] 2. The safety limit of a crane is known to be 32 tons. The mean weight and the standard deviation of a large number of iron rods
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that have fairly high reliabilities. 4. A product engineer has developed the following equation for the cost of a system component: C _ (10 P ) 2 ‚ where C is the cost in dollars and P is the probability that the component will operate as expected. The system is composed of two identical components‚ both of which must operate for the system to operate. The engineer can spend $173 for the two components. To the nearest two decimal places‚ what is the largest component probability that can
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in analysing the data is determining if outliers exists within the data. The presence of outliers must be evaluated because their existence could distort the data and make it inaccurate. In order to determine if outliers exist the average and standard deviation must be calculated in order to calculate the Z score‚ which will show‚ wither or not outliers exist. In this instance to outliers where found present in the data set as all of the data fell within the +3‚-3 range‚ the largest positive outlier
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score decreases by -0.347 average number of hours per week. Next‚ we have to interpret the random error component ( ) of the least squares line. The estimate of error standard deviation for this particular data set is 12.28455 which suggests that the work-life balance score (y) values should be two times of the standard deviation. This can be best expressed as in the equation of 2s = 2(12.28455) which equals 24.57 average hours per week. Then‚ we can analyze the accuracy of hypothesis model to
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