Chemical Bonds Chemical Bond: is the force that holds atoms together in a compound. They form because they lower the potential energy of the charged particles that compose atoms. Chemical bonds can be broadly classified into two types: Ionic and Covalent. Ionic: metal & nonmetal Metals have a tendency to lose electrons and nonmetals have a tendency to gain them. The metal atom becomes a cation and a nonmetal becomes an anion. The oppositely charged ions attract one another and form an ionic
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Empirical Formula of a Compound * Purpose: To determine the empirical formula of Magnesium Chloride. * Data 1. Mass of evaporating dish = 45.08g 2. Mass of evaporating dish and Magnesium = 45.17g 3. Mass of Magnesium: { 2 } – { 1 } = 0.09 4. Mass of evaporating dish and Magnesium Chloride First weighing = 45.48g (After heating and cooling) second weighing = 45.49g 5. Mass of Magnesium Chloride: { 4} – { 1 } = 0.41g
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injury‚ foreign microorganisms as well as initiate healing and repair process. However‚ inflammation can also be potentially harmful to our body because of the chemicals involve in inflammation process which are capable to destroy and injure normal tissues. The components of inflammatory process are white blood cells‚ plasma proteins and chemical mediator such as cytokines. All these induce the inflammation at the site of infection or damaged tissue. If inflammatory response is not under controlled‚
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EXPERIMENT NO. 9 CHEMICAL EQUILIBRIUM Audrey De Castro FCD3‚ Group 9‚ Ms. Sarah Sibug Kristine Tavares March 27‚ 2014 I. ABSTRACT Chemical equilibrium is mostly involved in industrial processes such as synthesis of ammonia
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Empirical and Molecular Formula | Key Concepts * Empirical Formula of a compound shows the ratio of elements present in a compound. * Molecular Formula of a compound shows how many atoms of each element are present in a molecule of the compound. * The empirical formula mass of a compound refers to the sum of the atomic masses of the elements present in the empirical formula. * The Molecular Mass (formula mass‚ formula weight or molecular weight) of a compound is a multiple of the empirical
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Chapter 1 Chemical Reactions and Equations Q.1. Why should magnesium ribbon be cleaned before burning in air ? Ans: Magnesium ribbon is a very reactive metal. When stored it reacts with oxygen to form a layer of magnesium oxide on its surface. This layer of magnesium oxide being a stable compound prevents further reaction of magnesium with oxygen. The magnesium is cleaned before burning in air to remove this layer so that the metal can be exposed to air properly. Q.2. Write the balanced
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CHEMICAL BONDS Chemical Bonds I. Introduction Chemical compounds are formed by the joining of two or more atoms. A stable compound occurs when the total energy of the combination has lower energy than the separated atoms. The bound state implies a net attractive force between the atoms called a chemical bond. The two extreme cases of chemical bonds are the covalent bonds and ionic bonds. Covalent bonds are bonds in which one or more pairs of electrons are shared by two atoms. Covalent bonds
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Ciba Specialty Chemical’s Case Analysis 1.) What caused Allied Colloids to become a takeover target? On March 12th 1998 Ciba Specialty Chemicals (SC) announced its acquisition of Allied Colloids‚ a company known as a global leader in water treatment. Allied Colloids acquisition aligned with Ciba’s goals in the form of establishing a new pillar for profitable and sustainable growth in the area of water treatment additives. Being the ambitious company that Ciba was‚ they realized that Allied Colloids
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of nitrogen gas?(2.8 mol) EMPIRICAL FORMULA WORKSHEET 1. What is the empirical formula for a compound which contains 0.0134 g of iron‚ 0.00769 g of sulfur and 0.0115 g of oxygen? (FeSO3) 2. Find the empirical formula for a compound which contains 32.8% chromium and 67.2% chlorine. (CrCl3) 3. NAME the compound which contains 0.463 g Tl (#81)‚ 0.0544 g of carbon‚ 0.00685 g of hydrogen and 0.0725 g of oxygen by finding its empirical formula. (TlC2H3O2)
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essential that the structure is derived. Firstly it is important to determine the percentage composition of elements to work out the empirical formula. The empirical formula was found to be C10H12O and the mass of the unknown was 148.09 m/z which when calculating the molecular weight of the empirical formula it did equal 148.09 g mol -1. This means that the empirical formula is also the molecular formula. As 12.01x10 carbons +1.008x12 hydrogens + 16= 148.09 09 g mol -1. From this knowledge the unknown
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