"Dcpip" Essays and Research Papers

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    Vitamin C

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    of different food sample by using titration method and state whether the percentage and concentration of vitamin C. Methodology: Theory : DCPIP can also be used as an indicator for Vitamin C. If vitamin C‚ which is a good reducing agent‚ is present‚ the blue dye‚ which turns pink in acid conditions‚ is reduced to a colorless compound by ascorbic acid. DCPIP (blue) + H+ ——→ DCPIPH (pink) DCPIPH (pink) + VitC ——→ DCPIPH2 (colorless) C6H8O6 + C12H7NCl2O2 ——→ C6H6O6 + C12H9NCl2O2 In this titration

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    pipette‚ 3 small beakers‚ DCPIP solution‚ 0.1% ascorbic acid‚ distilled water‚ 4 varieties of fruit juice‚ for example mango‚ grape‚ apple‚ guava etc. Preparation Take a properly washed beaker and make 0.1% solution of vitamin C or ascorbic acid with 0.1 g of vitamin C in 100 cm3; this is 10 mg cm-3 or one may also use a readily prepared 0.1%ascorbic acid. Take a 0.1% solution of DCPIP. Take 6 test tubes and label them

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    vitamin C lab report

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    that is able to decolourise blue DCPIP (2.6-dichlorophenol indophenols). The decolourisation of DCPIP can therefore be used to calculate the vitamin C content of a variety of fruit juices. Research Question – To determine how the content of Vitamin C (%) will differ in fresh fruits (orange‚ mango‚ lemon‚ lime‚ blackcurrant‚ pineapple) from that in processed fruit juices (orange‚ pineapple) by adding drops of the aforementioned fruit juices to DCPIP until the DCPIP gets decolorized. Variables Independent

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    fresh orange juice and Mr. Juicy orange juice. Principle: DCPIP food test is conducted. Vitamin C can reduce the blue dye DCPIP (Dichlorophenol-indophenol) and turn its colour from blue to colourless. This process is known as decolourization. Thus‚ we can estimate the amount of Vitamin C in the brands of orange juice by comparing: 1.) The volume of vitamin C solution (of 0.1% concentration) needed to decolourize a certain volume of DCPIP solution. 2.) The volume of a certain brand of orange juice

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    Background To carry out our experiment we used 3 different types of orange juices‚ and we also used 0.1% of vitamin C solution. The aim of our experiment was to see how much DCPIP was needed to be added to make the orange juices turn back to the orange colour and the DCPIP to decolourise once the 0.1% of vitamin C was added. DCPIP is a blue dye in its non-reduced form; it becomes colourless when it gains electrons. Vitamin C is an anti – oxidant‚ this is found mainly in fresh fruit and vegetables. The

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    Determination of the concentration of vitamin C in fruits/vegetables by using the DCPIP test (2008) Principle : Vitamin C is a strong reducing agent. It can decolorize the blue dye DCPIP. The amount of vitamin C in a food sample can be estimated by the amount of it that is used to decolorize a fixed amount of DCPIP. Apparatus : Test tube‚ clean and dry Test tube rack 5 ml syringe or a good quality squeezing pipette 1 ml pipette

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    prevent diseases like cancers. In this experiment‚ DCPIP solution is used to test the amount of vitamin C in the tea sample. DCPIP solution is a blue substance that would turn from blue color to pink with acids while turn from blue color to colorless with ascorbic acid (vitamin C). Therefore the DCPIP solution is used to test the concentration of vitamin C in a certain substance‚ by measuring the amount of substance needed to decolorize the DCPIP solution. When more of the substance is required to

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    Type of Fruit Juice / Control | Amount of liquid needed to decolourise DCPIP (cm³) | Control | 0.35 | Apple | 57.8 | Lemon | 3.7 | Pineapple | 1.4 | Fruit Juice | Concentration of Vitamin C (mg/cm³) | Apple | 0.06055 | Lemon | 0.94594 | Pineapple | 1.94444 | Concentration Juice Type Juice Type Amount 3.5/volume of fruit juice = ____mg/cm³ of Vitamin C in the fruit juice. The experiment was reliable as we repeated; the experiment and we cross referenced it with other groups

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    Determining the Absorbance Maximum Wavelength and Molar Extinction Coefficient to Find the Molarity of the Unknown DCPIP Background Information: A spectrophotometer is an instrument used to help determine the absorption spectrum of chemicals. It does this by reading the absorbance of the chemical at different wavelengths. All chemicals absorb light in their own distinct way. This distinction helps to identify unknown chemicals. The absorption of light within a chemical is also very important because

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    solution‚ 2‚6-Dichlorophenol – Indophenol (DCPIP) solution‚ distill water‚ filter paper. Apparatus : Small test tube and rack‚ 1cm3 and 5cm3 syringes with needles‚ 250ml beaker‚ 25ml measuring cylinder‚ stirrer‚ electronic scale. Methods Part A: Standardization of DCPIP (Titrant) solution 1. 1.00g of ascorbic acid tablet was measured by electronic scale and dissolved in 100.00ml of distilled water. 2. A 1.00cm3 syringe was used to transfer 1.00cm3of DCPIP solution into a small test tube.

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