9.1 Orbitals and Theories of Chemical Bonding 1. Which one of the statements concerning valence bond (VB) and molecular orbital (MO) bond theories is correct? a) MO theory predicts that electrons are localized between pairs of atoms. b) In VB theory‚ bonding electrons are delocalized over the molecule. c) MO theory accurately describes bonding in O2 and NO‚ VB theory does not. d) VB theory can describe molecular bonding in excited states. e) MO theory is used to accurately predict
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magnesium‚ to use the reagent prepared to synthesise a tertiary alcohol (triphenylmethanol) by reacting reagent and ester (methyl benzoate)‚ and the product formed is analyse by infrared spectroscopy (IR)‚ melting point‚ thin layer chromatography (TLC)‚ gas chromatography mass spectrum (GCMS) and finally Nuclear Magnetic Resonance spectroscopy. Introduction Formation of long hydrocarbon chain compound as becomes very useful in organic chemistry synthesis. In 1912‚ Victor Grignard a French chemist
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Lab 5 Column Chromatography: Isolation of Lycopene from Tomato Paste Reading: Zubrick‚ pages 79-82‚ 127-130‚ 138-139‚ 141-143‚ and 235-240 Pre-lab: look up the structure of lycopene. Introduction: Lycopene is the red pigment in ripe tomatoes and‚ as an antioxidant‚ helps to fight certain cancers. In this lab you will isolate lycopene from tomato paste. To do this you will first extract carotenoid pigments from the paste and then use column chromatography to isolate the lycopene from
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Kayla Adkins Forensic Chemistry Exam 2 I have been honest and observed no dishonesty. 1. In specific detail‚ describe a published procedure for the definitive identification of Heroin utilizing gas chromatography-mass spectroscopy (GCMS). Heroin is a white crystalline powder with no odor and a bitter taste. It is a derivative of morphine in that the –OH (hydroxyl group) is replaced by an acetyl group‚ -OCOCH3 and has a molecular formula is C21H23NO5 with a molecular weight of 369.42
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International Conference on Harmonization of Technical Requirements for Registration of Pharmaceuticals for Human use (ICH) was established. Then‚ in late 80is‚ RS were classified as impurities. Categories of residual solvents were presented in the preceding paper. The ICH Harmonized Guidelines set up by the EU‚ Japan and USA for the registration of pharmaceutical products require‚ under ICH Topic Q3C (published in December 1997)‚ for testing to be performed for residual solvents when production or purification
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use Gas Chromatography to distinguish between two enantiomers of carvone from caraway oil and spearment oil and to find the 2 carvone’s optical activity as well as percent carvone in spearment and caraway oil. It was found that S-carvone had an optical activity of 0.0047 and R-carvone had an optical activity of 0.516 and that spearment oil is 59% carvone and caraway oil is 100% carvone. Backround: Gas Chromatography separates organic samples much in the same way as column chromatography. The only
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on physical properties. Paper chromatography will be used to separate the dye colors from M&M candy to see which colors contain yellow #5. Gravimetric separation will be used to separate salt and sand from a mixture. Procedure The procedure for this lab can be found on pages 16 – 30 in “General Chemistry CHE110L Laboratory Manual Fall 2013”. Data Tables Carbon copies of data tables have been attached to the back of this lap report. Calculations Paper Chromatography- 1. Yellow M&M’s Rf Value:
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Spearmint and Caraway Oils: (+)- and (-) – Carvones Purpose Compare (+)- carvone from caraway oil to (-)- carvone from spearmint oil‚ using gas chromatography. Experimental Odor: Smell containers of spearmint and caraway oil and two carvones. Analytical Gas Chromatography: Put five individual samples by different group members into Gas Chromatograph to calculate the percent composition. Claudia tested S- (+)- carvone and R- (+) – Limonene‚ Daniel tested Spearmint oil (pure)‚ Greg tested R-
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Name _____________________________ Date ____________ Period _______ Completing the Square Day 1 For each expression‚ find the number you would add to make it a perfect square trinomial. Leave fraction answers as improper fractions (no mixed numbers or decimals). Then factor each trinomial. 1. x2 + 10x + _______ 2. y2 – 6y + ¬¬¬¬_______ 3. z2 – 8z + _______ _____________________ _____________________ _____________________ 4. x2 + 12x + _______ 5. x2 – x + _______ 6.
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Chromatography Lab Questions Pre-Lab Questions 1. A pencil is used rather than a pen to mark the “starting line” in step two because a pen or marker while be used to place a small dot of ink in the center of the X that is made with a pencil. 2. Capillary action is filling of pores in a solid with a liquid. Capillary action is caused by spotting or absorption and is allowed to seep or flow through. 3. The type of pen that will probably give better separation in this paper chromatography
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