Chemistry Lab Report Jeffrey Kenneth Bangero Introduction Firstly we calculated the mass of the beaker and then we put the assigned grams of sodium carbonate and calcium chloride. Then we add 50 ml of distilled water to each substance‚ sodium carbonate dissolved faster than calcium carbonate. After we mixed both sodium carbonate and calcium chloride and they form a solid precipitate. Then we poured it a funnel with a filter paper to get the solid precipitate. Purpose ● The purposed
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Aim: To determine the rate law of chemical reactions Introduction: The aqueous solution of potassium peroxydisulphate can oxidize potassium iodide as follow: Equation: K S 0 (aq) + 2KI (aq)->2K S0 (aq)+I (aq) 2 2 8 2 4 2 KI(aq) +I (aq) -> KI (aq) 2 3 _________________________________________________ K S 0 (aq) +3KI(aq) -> 2K S0 (aq)+ KI (aq) 2 2 8 2 4 2 The rate law of this reaction can be represented as follow: Rate=k[S208 2-]^a [I-]^b When the concentration of peroxydisulphate ions
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Chemical reactions proceeding until all the reactants are used is a common misconception. Chemical reactions actually behave differently. The general reaction equation is a A + b B → c C +d D in this equation A and B are the reactants forming the products C and D. However‚ unlike the common thought that the reaction ends when it runs out of A and B it actually does not. In most reactions C and D start to react to form A and B at a certain point as you can see in the equation c C + d D → a A + b
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investigating how the rate of reaction differs when we change the concentration of Hydrochloric Acid whilst reacting with Magnesium. The rate of reaction is explained by the Collision Theory. This theory explains how various factors affect the reaction rates and how chemical reactions occur. The 4 factors of the Collision Theory are: • Temperature • Concentration • Surface area • Catalyst I am investigating how different concentrations of acids affect the rate of reaction. However I must control
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Investigate the effect of concentration on the rate of a reaction Research question: To what extent does the concentration of hydrochloric acid affect the rate of the following reaction: 2 HCl(aq) + CaCO3(s) → CaCl2(aq) + H2O(l) + CO2(g) Data Collection and Processing: Table1: Different volumes of Co2 gas produced by Different concentrations of HCL acid. Volume of CO2gas formed from 5 different concentrations of HCL acid ±0.5ml 5 different concentrations of HCL acid (Mol) ±0.5ml Time (sec) ±0
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will increase the speed of reaction as the greater the surface of the solid reactants‚ the more particles are required to expose and ‘cover’ the capacity of the solid. Increased surface area results in an increased chance of collisions between reactant particles. Since the collisions become more frequent and abundant‚ the rate of reaction increases. Aim The aim of the experiment is to see if a greater surface area of a dissolvable tablet creates a faster or slower reaction Independent Variable
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survival and when this ability is impaired by the presence of Hydrogen ions‚ our cells cannot function properly. This experiment was conducted to determine if the reaction rate changes in response to a variation of acidic‚ neutral‚ and basic solutions. The experimental results indicated that the basic/high pH solution has a faster rate of reaction in the solution. Introduction Enzymes are proteins that catalyze and convert molecules into combinations of other molecules which is necessary for the
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on the rate of reaction. By using self investigative and experimental skills‚ the experiment was done in order to determine how the rate of reaction will be altered‚ whether it will increase‚ decrease or remain constant when the different concentration of enzymes added. INTRODUCTION: Enzymes are produced naturally in plant‚ animal‚ and microbial cell. There are thousands of different enzyme can be found in any cell. Enzymes can be describe as molecules that are greatly increase the rate of chemical
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factors that can influence the rate of diffusion through a membrane. Chemical kinetics plays a large part in diffusion. In order for a solute to passively diffuse through a membrane‚ it must line up with a pore in the membrane and pass through it (textbook 101). The concentration gradient is also important for diffusion because solutes diffuse from areas of high concentration to areas of low concentration (textbook page 101). There are different factors that can affect the rate of this diffusion. Our intent
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The reaction order‚ based on the rate law‚ was first order with respect to crystal violet and second order with respect to OH-. The rate law was as follows: Rate law = k [CV]1[OH-]1 where k equaled 2.61. In order to determine the reaction order with respect to crystal violet‚ the graph that described the relationship between ln[CV] and time (seconds) was Figure 2. Not only did Figure 2 generate a more linear relationship‚ but it had the highest R2 value of 0.992 than ([CV] versus time) and ([1/CV]
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