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week 1 discussion math 221

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week 1 discussion math 221
The date of birth I used was mine 7/19/86
I will now do all three question that was asked

a = 7 b = -19 c = 86

The INTEGERS above are needed to solve each given expressions.

A) A^3 – B^3
(7^3) – (-2^3)
343-(-6859)
=7,202
This is the given expression with VARIABLES A and B and raised to the EXPONENTS of 3 on each of them.
By substituting the integers in the variables and raising them to the 3rd power gives the answer of

B) (a – b)(a2 + ab + b2)
(7-(-19) (7^2+(7)(-19)+(-19^2)
(26) (49-133) + 361
(26)(277)
=7202
C) ( b-c )/ (2b- a) :-This expression uses all three variables: a, b, and c.
C) (b-c) this equation takes use of all three variables. It’s an expression with a divisor of 2b –a. (2b-a) after plugging in my date of birth into the given equation I begin to break down
-19-86 the equation by adding and subtracting the variables to come to a conclusion
2(-19)-7 after breaking down the fraction to the lowest terms I came up with an improper positive
= -105/-45= -21/-9 fraction.
= 7/3

The interesting fact was in both expressions of A and B the answers came to be same 7,202.

Simplifies Three Expressions

Total: 2.20

Distinguished - Correctly simplifies all three expressions. All steps of the process are shown in the required format.

Proficient - Correctly simplifies all three expressions. Most steps of the process are shown in the required format.

Basic - Correctly simplifies at least two of the expressions. Most steps of the process are shown, but work may not follow the required format.

Below Expectations - Correctly simplifies at least one of the expressions, but steps of the process may be incorrectly formatted or missing.

Non-Performance - The simplification of the three expressions is either nonexistent or lacks the components described in the assignment instructions.

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