Data Analysis Bsb123 Essay Example

Q1 T1,2,3 | mean:x=i=1nxin, 3+4+7+7+9+126=426=7 | median: n+12=6+12=72=3.5=7, SD s= = x-x2n-1 | Q1n+14, Q7+14=84=2postion Q3=3(n+1)4=3(7+1)4=244=6, IQR Q3-Q1, | CV=sx×1003.297×100%=47%/ n = 5 has a mean of 10.2.four data: 9, 10, 8 17, find the missing data value.x=i=1nxin=8+9+10+17+?5=*5=10.2, 5×10.2=51 Therefore: 8+9+10+17+?=51Therefore: 8+9+10+17+?=51Simplifying: 44+?=51And so ?=51-44=7Thus the missing data value is 7. | Variance/s2= x-x2n-1, [3-72+4-72+7-72+7-72+9-72+12-72]6-1 =545 =10.8 | egA manufacturer of insulation randomly selects 20 winter days and records the daily high temperature 11, -11, -8, -6, -4, -4, -3, -3, -3, -1, 0, 2, 3, 3, 5, 6, 7, 8, 12, 13 number of classes: 5 (between 5 and 15/class interval (width): (24/5)~5/class boundaries (limits): -11, -6, -1, 4, 9, 14 class midpoints: -8.5, -3.5, 1.5, 6.5, 11.5/ | Calculate the covariance and correlation for the Sample of n = 4:(2, 3), (7, 9), (4, 5), (4, 6) sol x=2+7+4+44=174=4.25, y=3+9+5+64=234=5.75 ,x-xy-y=15.26/covariance=x-xy-yn-1=15.264-1=5.09, correlation=r=covarsx×sy=5.092.06×2.5=0.99x y (x-x ̅) (y-y ̅) (x-x ̅ )(y-y ̅)2 3 -2.25 -2.75 6.197 9 2.75 3.25 8.94 4 5 -0.25 -0.75 0.194 6 -0.25 0.25 -0.06 | Q3T6 Any normal distribution (with any mean and standard deviation combination) can be transformed into the standardised normal distribution ] If X is distributed normally with mean of 100 and standard deviation of 50, the Z value for X = 200 is for x zt