# Vertical Motion Model

Topics: Reach, Equations, Standard gravity Pages: 3 (904 words) Published: February 25, 2013
Michelle Villanueva
Hey! I know the vertical motion model can be hard, but once you get the hang of it, it’s a piece of cake. Math is all about using your prior knowledge, plugging it into what you know, to solve for what you don’t know. The vertical motion model is made up of the velocity, and height. The equation is -16t2 + vt + h. V is equivalent to the velocity, and h is equal to the height. The vertical motion falls under the influence of gravity. As the force due to gravity may be opposite to the direction of motion, there exists the possibility that the body under force of gravity reverses its direction. It is, therefore, important to understand that the quantities involved in the equations of motion may evaluate to positive or negative values with the exception of time (t). We must appropriately assign sign to various inputs that goes into the equation and correctly interpret the result with reference to the assumed positive direction. Further, some of them evaluate to two values one for one direction and another of reversed direction.

The problem I created was based on Hope Solo and her soccer skills. Hope kicks the ball back at an initial height of 3 feet, and a vertical velocity at 20 feet per second. The equation to this problem would be h(t)= -16t2 + 20t + 3. This shows how 20 would be the velocity, and 3 would be the initial height. The problem would ask us for the equation, time the ball would hit the ground in seconds, time the ball was in the air at 5ft, and the maximum height of the ball. In order to find at what time the ball would hit the floor, we need to find zero in the calculator. First step into solving this problem is plugging in the equation into the calculator. You will the need to find zero under the x-axis, in trace zero. The calculator will ask you for left and right bound. The ball would then hit the ground at 1.4 seconds. Next, the problem asked for the...