Titration Lab
Introduction
A titration is a technique used to find the solution of known concentration in the concentration of another unknown solution. Typically, the known solution is added from a known quantity of unknown solution until the reaction is complete. Titrations are also often used to determine the pH of a solution. This is important because without knowing how acid or basic a solution is people could hurt themselves and others but mixing chemicals together that are lethal. The objective of the is lab is to develop familiarity with the concepts and techniques of titration and to determine the concentration of an acidic acid solution. It was necessary to add Phenolphthalein because it acts as an indicator, that is a weak acid, so it is easier …show more content…
Repeat the process two more times, using wells A-2 and A-3. Record your results for each trial. Note: All three titration results should agree within 1 drop of the others. If they do not, you have made a computation error and should repeat the titration.
Calculate the average number of drops of NaOh used for the 3 trials and record.
Calculate the Normality of the vinegar using the previously given equation.
Calculate the mass of the acetic acid in grams using the previously given equation.
Calculate the percentage of acetic acid using the previously given equation.
Thoroughly clean all your equipment and wash any left over acid or base down the sink with lots of water. Remember, acids and bases will neutralize each other when mixed.
Data and Results
*Normality of vinegar (Na) = (Nb)(dropsb) / (dropsa) (.5)(22) / (10) = 1.1 N
*Mass of Acetic Acid = (Na)(GMMa) (1.1)(60) = 66 g
*% of Acetic Acid = Massa (g/L) / 1000 g/L x 100% 66 / 1000 x 100 = 6.6 g/L
Balanced equation: HC2H3O2 + NaOH ——> NaC2H2O2 + …show more content…
The average amount of drops it took was twenty-two. The acid and base were so close in drops because while they are opposites, they are the exact opposite of each other, meaning that one drop of acid will neutralize one drop of a base and vice-versa. The normality of the base was .5 because there was only one equivalent of NaOH so the morality would be Nam. The equation that would be used to find Na is :
*Na= (Nb)(average # drops of base) / drops of acid (10)
The Nb is .5 N, the average number of drops of base is 22, and the drops of acid is 10. The answer is 1.1 and that is the normality of vinegar. Some changes that took please were the change in color when the drops of base were added to the vinegar. Also, one could see that the more drops that were added made the solute a deeper pink, so much that it almost looked red. Some potential sources of error were that the plates had so left over water in them, the plates had al ready been used, and that the sizes of the drops of solution were either not big enough or to big which would mean that the data was not very
A titration is a technique used to find the solution of known concentration in the concentration of another unknown solution. Typically, the known solution is added from a known quantity of unknown solution until the reaction is complete. Titrations are also often used to determine the pH of a solution. This is important because without knowing how acid or basic a solution is people could hurt themselves and others but mixing chemicals together that are lethal. The objective of the is lab is to develop familiarity with the concepts and techniques of titration and to determine the concentration of an acidic acid solution. It was necessary to add Phenolphthalein because it acts as an indicator, that is a weak acid, so it is easier …show more content…
Repeat the process two more times, using wells A-2 and A-3. Record your results for each trial. Note: All three titration results should agree within 1 drop of the others. If they do not, you have made a computation error and should repeat the titration.
Calculate the average number of drops of NaOh used for the 3 trials and record.
Calculate the Normality of the vinegar using the previously given equation.
Calculate the mass of the acetic acid in grams using the previously given equation.
Calculate the percentage of acetic acid using the previously given equation.
Thoroughly clean all your equipment and wash any left over acid or base down the sink with lots of water. Remember, acids and bases will neutralize each other when mixed.
Data and Results
*Normality of vinegar (Na) = (Nb)(dropsb) / (dropsa) (.5)(22) / (10) = 1.1 N
*Mass of Acetic Acid = (Na)(GMMa) (1.1)(60) = 66 g
*% of Acetic Acid = Massa (g/L) / 1000 g/L x 100% 66 / 1000 x 100 = 6.6 g/L
Balanced equation: HC2H3O2 + NaOH ——> NaC2H2O2 + …show more content…
The average amount of drops it took was twenty-two. The acid and base were so close in drops because while they are opposites, they are the exact opposite of each other, meaning that one drop of acid will neutralize one drop of a base and vice-versa. The normality of the base was .5 because there was only one equivalent of NaOH so the morality would be Nam. The equation that would be used to find Na is :
*Na= (Nb)(average # drops of base) / drops of acid (10)
The Nb is .5 N, the average number of drops of base is 22, and the drops of acid is 10. The answer is 1.1 and that is the normality of vinegar. Some changes that took please were the change in color when the drops of base were added to the vinegar. Also, one could see that the more drops that were added made the solute a deeper pink, so much that it almost looked red. Some potential sources of error were that the plates had so left over water in them, the plates had al ready been used, and that the sizes of the drops of solution were either not big enough or to big which would mean that the data was not very