Space Constructors

Space Constructors Inc.
Hanchen Li
Jianyang Zhang
St. Thomas University
BUS 670 Advanced Operations Management
Dr. Paul D. Maxwell
Jan 29, 2014

1. Reduce total project duration as much as possible without unnecessary additional cost. Indicate the new critical path or paths. Show how much slack or float remain in the noncritical paths.

Below is the path without unnecessary additional cost.

Path
Original times(weeks) reduce total duration as much as possible with additional cost time(weeks)
Slack or float(weeks)
Original Cost (Dollars)
Additional total cost(Dollars)
ADG
3+5+4=12
2+3+2=7
5
5000+10000+10000=$25000
10000+18000+24000= $52000
AF
3+7=10
2+5=7
3
5000+11500= $16500
10000+17500= $27500
BG
6+4=10
4+2=6
4
14000+10000= $24000
26000+24000= $50000
CEG
2+2+4=8
1+2+2=5
3
2500+8000+10000= $20500
5000+8000+24000= $37000

From the excel, we can find that the ADG and AF are the longest path, so both are the critical paths. From the slack or float remain time, we can find how much slack or float remain in the noncritical paths.

2. Assume that the situation proves to be less urgent than it seems to Messrs Alison and Phillips. Revises the schedule in order to complete the job within ten weeks. Indicate the new cost and critical path or paths.

From the excel above, we can find that Path AF and BG is ten weeks. And the path CEG is 8 weeks. So just need to control the path ADG within 10 weeks. So activity A and D are to use original time, and D use additional cost time. SO
ADG=3+5+2=10 so cost is 5000+10000+24000=39000
If A and G to use original time, and D is to use additional cost.SO
ADG=3+3+4=10, and cost is 5000+18000+10000=33000
So the second one is a better option because it is cheaper.
ADG=10 AF=10 BG=10 CEG=8 total cost is 33000+16500+24000+20500=94000
And paths ADG AF BG are both critical paths

3. Suppose SCI were proceeding on the 10 week schedule and it became