Solubility Test Lab Report Essay

To identify an unknown sample, there were several steps that helped determine the molecular structure and the name of the sample. When Belle #9 (unknown) was given to me, it’s physical state and color was recorded on the data sheet. Since the sample was a pure liquid, there was no need for distillation. Next, a solubility test was given. When one drop of the unknown liquid was added to about 2 mL of water, the sample was tested to be soluble due to the dissolubility between the two compounds. By following the chart that was given on the sheet, the pH of the solution was tested. Since the two litmus did not changed color, the sample was identify to have a low molecular weight and a neutral substance. Based on the solubility test, some possible
Based on the IR graph, I can tell that the primary functional group would be a ketone. After the IR spectra, the NMR of the unknown was analyzed. First, the general region was predicted to give an idea of how the molecular may look like. Based on the chart, it does seem like a ketone was present with a couple of C-H stretches near the functional group. Next, four H proton signals and five carbons singles were identified on both of the H and C NMR. Finally, the splitting pattern was identified where it provided where the C-H bonds were potentially located on the H NMR . With the molecular weight of 100.16 g/mol given along with the information provided by the IR spectra and NMR spectrum, the possible molecular formula of the structure was identified as C6H12O and the structure of the molecular was predicted. To figure out the structure of the molecule, the ketone structure was drawn first. Next, I drew out the possible C-C bonds along with their Hs by following the information that was given by the H and C NMR spectrum. Finally, the structure was checked with the molecular weight and its